tag:blogger.com,1999:blog-56750369363676083462024-03-20T20:14:52.576-07:00AP Eapcet 2022 Ap Eamcet 2022 Seat allotment CounsellingAP Eapcet 2021 Ap Eamcet 2022 RESULT AP EAPCET 2022 Seat allotment registration Notification exam dates application online Download hall ticket fee result counselling
Unknownnoreply@blogger.comBlogger14125tag:blogger.com,1999:blog-5675036936367608346.post-21222588909665324112021-07-13T18:31:00.033-07:002023-08-14T06:51:16.846-07:00Ap Eapcet 2022 or Ap Eamcet 2022 Notification Exam dates counselling fee result<h1 style="text-align: left;"><span style="font-size: medium;"> <span style="background-color: white; color: #222222; font-family: inherit;">Ap Eapcet 2021 or Ap Eamcet 2021 Counselling Seat allotment </span></span></h1><div><span style="font-size: medium;"><span style="background-color: white; color: #222222; font-family: inherit;">AP Eapcet seat allotment 2021 ap eapcet counselling phase 1 seat allotment </span></span></div><body><script async="" src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
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</script></body><div><span style="font-size: medium;"><span style="background-color: white; color: #222222; font-family: inherit;"><br /></span></span></div><div><span style="font-size: medium;"><span style="background-color: white; font-family: inherit;"><a href="https://sche.ap.gov.in/APSCHEHome.aspx" target="_blank"><span style="color: #04ff00;">AP EAPCET 2021 SEAT ALLOTMENT</span></a><br /></span></span></div><div><span style="font-size: medium;"><span style="background-color: white; color: #222222;"><div>list of documents required for online counselling -</div><div><br /></div><div>Rank card</div><div><br /></div><div>Hall ticket</div><div><br /></div><div>Memorandum of marks (Inter or inter equivalent)</div><div><br /></div><div>Study certificate from 6 to Intermediate</div><div><br /></div><div>Transfer Certificate(t c)</div><div><br /></div><div>Proof of date of birth (SSC or ssc equivalent memo)</div><div><br /></div><div>EWS certificate, if applicable</div><div>Local status (lc) certificate, if applicable</div><div><br /></div><div>A P residence certificate in prescribed format in case of (Nl) non-local candidates</div><div><br /></div><div><br /></div><div>Residence certificate in prescribed format for private candidates</div><div><br /></div><div>IMPORTANT DATES:</div><div><div>Registration from 25-10-2021 to 30-10-2021</div><div><br /></div><div>Verification of Uploaded Certificate from 26-10-2021 to 31-10-2021</div><div><br /></div><div>Option Entry from 01-11-2021 to 05-11-2021</div><div><br /></div><div>Allotment of Seats Phase-1 - 10-11-2021</div></div><div><br /></div><div><br /></div></span></span></div><h2 style="background-color: white; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif;"><span style="color: #04ff00;"><span style="font-family: inherit; font-size: medium;"> </span><span style="font-family: inherit; font-size: x-large;">COUNSELLING HERE</span> </span></h2><h2 style="background-color: white; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif;"><span style="color: #04ff00; font-family: inherit; font-size: medium;"></span></h2><span style="color: #04ff00;"></span><h2 style="background-color: white; color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; text-align: left;"><span style="font-family: inherit; font-size: medium;">Ap Eapcet notification released </span><a href="http://www.eapcet.com/2021/06/ap-eapcet-2021-syllabus-engineering.html" style="font-size: x-large;" target="_blank"><span style="color: #04ff00; font-size: x-large;"> SYLLABUS</span></a></h2><div><span style="font-family: inherit;"><span face="Arial, Tahoma, Helvetica, FreeSans, sans-serif" style="background-color: white; color: #222222; font-size: large;">Andhra Pradesh State Council of Higher Education has released the AP EAPCET 2021 exam dates Apeamcet is now Eapcet . Eapcet likely be conducted from August 19 to August 25</span></span></div><br /><head><script async="" data-ad-client="ca-pub-1795821529243874" src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
</head><div class="separator" style="clear: both; text-align: center;"><br /></div><div class="separator" style="clear: both; text-align: center;"><div><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjfEfGnMT345IzEBO-uKOb_GjGW_Nig9HdtkoBFmFbLpyVpbMCxLM1A4oLVICcc7q50ZUThwgz1Bw0MoR_BUuxXPJdqDWfgbzID-vzLZhBz6Joc9j4Qe445XahuEZGhieSTr_ufyy_TIlqw/s615/EAPCET.jpg" style="margin-left: 1em; margin-right: 1em;"><img alt="EAPCET 2021" border="0" data-original-height="615" data-original-width="591" height="400" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjfEfGnMT345IzEBO-uKOb_GjGW_Nig9HdtkoBFmFbLpyVpbMCxLM1A4oLVICcc7q50ZUThwgz1Bw0MoR_BUuxXPJdqDWfgbzID-vzLZhBz6Joc9j4Qe445XahuEZGhieSTr_ufyy_TIlqw/w385-h400/EAPCET.jpg" title="EAPCET 2021" width="385" /></a></div></div><div><span style="background-color: white; color: #222222;"><span style="font-size: large;">Engineering agriculture and pharmacy common entrance test 2021 ap eapcet 2021 of andhra pradesh will be conducted through computer based test by jawaharlal nehru technological university kakinada for entry into the first year of the folloing professional courses offered for the academic year 2021-2022 in the state of andhra pradesh</span></span></div><div><br /></div><div><div style="background-color: white; color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif;"><span style="font-size: large;">a)Engineering ,Bio technology ,B tech(dairy technology),Btech(agr.engg),Btech(food science and technology)</span></div><div style="background-color: white; color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif;"><span style="font-size: large;">b)B.sc(Ag)/B.sc(hort)/B.V.Sc&A.H/B.F.Sc</span></div><div style="background-color: white; color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif;"><span style="font-size: large;">c)B.pharmacy,pharma D</span></div></div><div style="background-color: white; color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif;"><span style="font-size: large;"><br /></span></div><div style="background-color: white; color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif;"><span style="font-size: large;"><div><a href="https://sche.ap.gov.in/ECET/ECET/ECET_HomePage.aspx" style="font-size: xx-large;" target="_blank"><span style="color: #04ff00;">AP EAPCET 2021 REGISTRATIONS STARTED APPLY </span></a></div><div><br /></div><div><a href="http://www.eapcet.com/2021/06/ap-eapcet-2021-syllabus-engineering.html" target="_blank"><span style="color: #04ff00; font-size: x-large;">AP EAPCET 2021 SYLLABUS</span></a></div><div><br /></div><div><span style="color: #04ff00; font-size: x-large;"><a href="https://sche.ap.gov.in/EAPCET/Eapcet/EAPCET_PaymentStatus.aspx" target="_blank"><span style="color: #04ff00;">AP EAPCET 2021 KNOW YOUR PAYMENT STATUS </span></a><br /></span></div><div><span style="color: #04ff00;"><br /></span></div><div><span style="font-size: x-large;"><a href="https://sche.ap.gov.in/eapcet/EapcetHomePages/Home.aspx" target="_blank"><span style="color: #04ff00;">AP EAPCET 2021 HALLTICKETS DOWNLOAD </span></a></span></div><div><br /></div><div>candidates who wish to apply for AP EAPCET 3</div></span></div><div><div style="background-color: white; color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif;"><div><span style="font-size: large;">2021 shall submit their application through online mode only the detailed information regarding eligibility,age,syllabus related instructions and procedure for online application are available in the website www.sche.ap.gov.in/eapcet</span></div><div><span style="font-size: large;">dates timing for the the test and details of registration fee </span></div><div><span style="font-size: large;">Engineering (E) stream exam dates from 19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12 p.m and 3 p.m to 6 p.m registration fee for O C Rs600/- B C Rs550/- S C/S T Rs500/-</span></div><div><span style="font-size: large;">Agriculture (A) stream exam dates from 19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12 p.m and 3 p.m to 6 p.m registration fee for O C Rs600/- B C Rs550/- S C/S T Rs500/-</span></div><div><span style="font-size: large;">E and A both streams exam dates from 19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12 p.m and 3 p.m to 6 p.m registration fee for O C Rs1200/- B C Rs110/- S C/S T Rs1000/-</span></div><div><span style="font-size: large;">Commencement of application submission : 25-06-2021 </span></div><div><span style="font-size: large;">Last date for submission without late fee 25-07-2021</span></div><div><span style="font-size: large;">Downloading of halltickets from website 12-08-2021</span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">The registration fee may be paid through payment gateway/credit,debit/net banking</span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">Last date for submission with late fee </span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">Rs500/- 05-08-2021 </span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">Rs1000/- 10-08-2021</span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">Rs 5000/- 16-08-2021</span></div><div style="font-size: 13.2px;"><span style="font-size: medium;"><br /></span></div><div><span style="font-size: large;">Rs10000/- 18-08-201</span></div><div style="font-size: 13.2px;"><span style="font-size: medium;"><br /></span></div><div style="font-size: 13.2px;"><span style="font-size: medium;">25th last date hurry </span></div><div style="font-size: 13.2px;"><h3 style="margin: 0px; position: relative;"><span style="font-family: inherit; font-size: medium;"><span style="color: #333333;">Engineering Agricultural And Pharmacy Common Entrance Test </span></span></h3><span style="font-size: medium;"></span><div><span style="font-family: inherit;"><span style="color: #333333; font-size: medium;"><b>Ap eapcet exam to be held in august </b></span></span></div><div><span style="font-family: inherit;"><span style="color: #333333; font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Ap eapcet 2021 Important dates </b></span></span></div><div><span style="font-family: inherit;"><span style="color: #333333; font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>EApcet 2021 will be conducted from august 19 to 25</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>From this year this entrance test name changed as Eapcet eapcet 2021 notification will be issued on june 24</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet opening date of application : 26-06-2021</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet closing date of application : 25 -07-2021</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet last date to apply with late fee of 500 rupees 26-07-2021 to 05-08-2021 </b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet last date to apply with late fee of 1000 rupees 06-08-2021 to 10-08-2021</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><div style="color: black; font-size: large;"><span style="color: #333333;"><b>Eapcet last date to apply with late fee of 5000 rupees 11-08-2021 to 16-08-2021</b></span></div><div style="color: black; font-size: large;"><span style="color: #333333;"><b><br /></b></span></div><div><div style="color: black; font-size: large;"><span style="color: #333333;"><b>Eapcet last date to apply with late fee of 10000 rupees 17-08-2021 to 18-08-2021</b></span></div></div></div></div><div style="color: black;"><span style="color: #222222;"><span style="color: #333333; font-size: large;">AP EAPCET 2021 is a Entrance Test to get Admission in Engineering and Agriculure and pharma Colleges through out Andhra Pradesh State.</span></span><h4 style="color: #222222; font-size: 13.2px; margin: 0px; position: relative;"><span style="font-family: inherit; font-size: medium;">candidates will be required to fill out the application form of AP EAMCET 2021 AP EAPCET 2021</span></h4><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;">Education Minister Adimulapu Suresh said the notification would be released on June 24 2021.</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;"><br /></span></span></p><p style="color: #222222;"><span style="font-size: large;"><span style="font-family: "Proxima Nova";">All other common entrance tests like PGECET (Post Graduate Engineering Common Entrance Test for MTech/MPharma),</span><span style="font-family: "Proxima Nova";">ECET (Engineering Common Entrance Test, lateral entry for diploma holders), EdCET (Education Common Entrance Test for BEd)</span><span style="font-family: "Proxima Nova";">ICET (Integrated Common Entrance Test for MBA/MCA), </span><span style="font-family: "Proxima Nova";">PECET (Physical Education Common Entrance Test for BPEd/UG DPEd) and Lawcet (Law Common Entrance Test for three- and five-year law courses and for PG Law) </span><span style="font-family: "Proxima Nova";"> are proposed to be conducted in the first half of September</span><span style="font-family: "Proxima Nova";">Jawaharlal Nehru Technical University, Kakinada, will relase the AP EAMCET 2021 AP EAPCET 2021 Exam Date</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Candidates must check the AP EAM</span><span style="font-family: "Proxima Nova"; font-size: large;">CET AP EAPCET 2021 eligibility criteria before submitting the application form</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">The details related to AP EAMCET or AP EAPCET Application Form 2021 can check below:</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">AP EAMCET OR AP EAPCET Application form 2021 will be available on the website </span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;">Applicants can register and fill the application form online mode from the website</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;">Aspirants can check the complete procedure of filling the application </span><span style="font-size: medium;">f</span><span style="font-size: large;">orm from the instruction booklet available on the website.</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;">In case applicants want to correct the details of the application form, they can correct the application from </span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Mode of payment :</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;">Debit and credit card</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;">Net banking</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Aspirants must check the AP EAMCET or AP EAPCET Eligibility before applying for the entrance exam:</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Nationality:</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">The candidate should be Indian National or PIO/OCI cardholders.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;">Engineering Courses:</span></span></p><p style="color: #222222;"><span style="font-size: large;"><span style="font-family: "Proxima Nova";">Aspirants must have appearing/passed his/her ten plus two(10+2) with subjects of Chemistry ,Physics and Mathematics as an optional or related vocational program in Engineering</span><span style="font-family: "Proxima Nova";"> and Technology fields conducted by BIE, Telangana/AP</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;">He/she must belong to Telangana/AP State and must satisfy Non-Local/Local status requirements laid down in Telangana/AP Educational Institutions.</span></span></p><p style="color: #222222;"><span><span style="font-family: "Proxima Nova";"><span style="font-size: large;">He/she must have passed the Diploma examination in Engineering organized by the State</span><span style="font-size: 13.2px;"> </span><span style="font-size: x-large;">Board of Technical Education and Training, </span></span><span style="font-family: "Proxima Nova"; font-size: x-large;">AP/Telangana or its equivalent recognized by the Board.</span></span></p><p style="color: #222222;"><span style="font-size: x-large;"><span style="font-family: "Proxima Nova";"> </span><span style="font-family: "Proxima Nova";">o, get ready to prepare the AP EAPCET 2021 OR AP EAPCET 2021 Previous Question Paper Sets A, B,C, D to get Good marks in Final EAPCET OR EAPCET Exams 2021.</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: x-large;">Age : candidates applying for Engineering programs must have completed 16 years of age on 31st December 2021. No upper age limit prescribed.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: x-large;">Subjects: The question paper will include questions from the subjects of Mathematics, Chemistry, and Physics</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: x-large;">Language: The exam paper will be in English And Telugu language.</span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: x-large;">Time Duration: The time duration will be three</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: x-large;"> 3 hours.</span></span></p><p style="color: #222222; font-size: 13.2px;"><span style="font-family: "Proxima Nova"; font-size: medium;">AP EAPCET – 2021</span></p><p style="color: #222222; font-size: 13.2px;"><span style="font-family: "Proxima Nova"; font-size: medium;">IMPORTANT INSTRUCTIONS TO THE CANDIDATES</span></p><p style="color: #222222; font-size: 13.2px;"><span style="font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p style="color: #222222; font-size: 13.2px;"><span style="font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">1)<span style="white-space: pre;"> </span>The Candidates who wish to apply for APEAPCET-2021 are requested to fill the particulars carefully in the ONLINE APPLICATION FORM. The required information should be collected from the relevant documents.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">2)<span style="white-space: pre;"> </span>The Candidates are requested to check the filled in particulars before pressing SUBMIT button during online application process.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">3)<span style="white-space: pre;"> </span>After submission of ONLINE APPLICATION FORM, if any corrections are to be incorporated, candidate has to see the corrections link in Homepage of</span><span style="font-family: "Proxima Nova"; font-size: medium;"> https://sche.ap.gov.in/eapcet</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">4)<span style="white-space: pre;"> </span>To fill the required details in ONLINE APPLICATION FORM, the following documents may be referred:</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;"><br /></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">S.NO<span style="white-space: pre;"> </span>Details Required<span style="white-space: pre;"> </span>Documents to be referred</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">1.<span style="white-space: pre;"> </span>AP Online/ TS Online Transaction Id. (if</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">payment is being made through AP Online/ TS Online)<span style="white-space: pre;"> </span>Receipt form from AP Online / TS Online</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">2.<span style="white-space: pre;"> </span>Qualifying Examination appeared or passed, Hall<span style="white-space: pre;"> </span>ticket<span style="white-space: pre;"> </span>Number<span style="white-space: pre;"> </span>of<span style="white-space: pre;"> </span>Qualifying</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Examination<span style="white-space: pre;"> </span>Marks<span style="white-space: pre;"> </span>Memo<span style="white-space: pre;"> </span>/<span style="white-space: pre;"> </span>Hall<span style="white-space: pre;"> </span>Ticket Intermediate (10+2) / Equivalent<span style="white-space: pre;"> </span>of</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">3.<span style="white-space: pre;"> </span>Stream Applied for (E), (AM), or both (E &</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">AM)<span style="white-space: pre;"> </span>Eligibility Criteria in the APEAPCET-</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">2020 website</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">4.<span style="white-space: pre;"> </span>Date of Birth, Birth District, Birth State<span style="white-space: pre;"> </span>Birth Certificate / SSC or Equivalent</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Certificate</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">5.<span style="white-space: pre;"> </span>Hall Ticket Number of SSC or Equivalent</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">examination Certificate<span style="white-space: pre;"> </span>SSC or Equivalent Certificate</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">6.<span style="white-space: pre;"> </span>Local Status (OU/AU/SVU/ Non- local)<span style="white-space: pre;"> </span>The local candidate certificate issued by</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">MRO or Competent Authority</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">7.<span style="white-space: pre;"> </span>Income of Parents (Income upto Rs.1.00</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Lakh (or) up to Rs.2.00 Lakhs (or) more than Rs. 2.0 lakhs<span style="white-space: pre;"> </span>The<span style="white-space: pre;"> </span>Income<span style="white-space: pre;"> </span>certificate<span style="white-space: pre;"> </span>issued Competent Authority<span style="white-space: pre;"> </span>by</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">8.<span style="white-space: pre;"> </span>STUDY DETAILS<span style="white-space: pre;"> </span>Study<span style="white-space: pre;"> </span>certificates<span style="white-space: pre;"> </span>from<span style="white-space: pre;"> </span>Class</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Intermediate (10+2) / Equivalent<span style="white-space: pre;"> </span>I<span style="white-space: pre;"> </span>to</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">9.<span style="white-space: pre;"> </span>Category (SC, ST, BC, etc.) and Application</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">number of the Caste Certificate<span style="white-space: pre;"> </span>The latest Caste Certificate issued by</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Competent Authority</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">10.<span style="white-space: pre;"> </span>Special Category (NCC, PH, Sports, CAP,</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">etc.)<span style="white-space: pre;"> </span>The Certificate Issued by Competent</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Authority</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">11.<span style="white-space: pre;"> </span>Aadhaar Card details<span style="white-space: pre;"> </span>Aadhaar Card</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">12.<span style="white-space: pre;"> </span>Ration Card details<span style="white-space: pre;"> </span>Ration Card</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">13.<span style="white-space: pre;"> </span>Economically Weaker Sections Certificate</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">details<span style="white-space: pre;"> </span>EWS Certificate</span></p><p style="color: #222222; font-size: 13.2px;"><span style="font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">5)<span style="white-space: pre;"> </span>Other Information required for filling Online Application</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">a)<span style="white-space: pre;"> </span>Recent passport size digital color photograph (file size less than 30 KB and “.jpg” file format) of candidate for uploading (whose photograph is not available in Intermediate databases)</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;"> </span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">b)<span style="white-space: pre;"> </span>Digital Signature of the candidate (file size less than 15 KB and “.jpg” file format) of</span><span style="font-family: "Proxima Nova"; font-size: large;"> candidate or uploading (whose Signature is not available in Intermediate databases.)</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">c)<span style="white-space: pre;"> </span>Regional Center to which candidate wishes to appear for AP EAPCET-2021 examination. d) Gender (Male / Female/Transgender.)</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">e)<span style="white-space: pre;"> </span>Non-Minority / Minority</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">f)<span style="white-space: pre;"> </span>Mobile Number of the candidate.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">g)<span style="white-space: pre;"> </span>E-mail of the candidate.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">h)<span style="white-space: pre;"> </span>Place of Education - Municipality / Corporation or Rural area in SSC and Intermediate.</span></p><p style="color: #222222; font-size: 13.2px;"><span style="font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">6)<span style="white-space: pre;"> </span>It is advised to visit your allotted Examination Center well before so that you can take examination tension – free.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">7)<span style="white-space: pre;"> </span>The candidate will not be allowed to take the examination even if late by 1minute.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">8)<span style="white-space: pre;"> </span>The candidate does not have option of choosing specific date / session to appear for the AP EAPCET-2021 entrance examination. This information is known to him / her only after downloading Hall Ticket. For any reason if the candidate fails to appear in the given slot, he / she is treated as absent.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">9)<span style="white-space: pre;"> </span>The candidate has to submit the “FILLED IN ONLINE APPLICATION FORM” to the invigilator in the Examination Hall on the day of the AP EAPCET-2021 exam. Also, affix a</span><span style="font-family: "Proxima Nova"; font-size: medium;"> r</span><span style="font-family: "Proxima Nova"; font-size: large;">ecent color photograph (3.5cms x 3.5cms) in the box provided (Bottom – Left side) on the FILLED IN ONLINE APPLICATION FORM and get it attested by a Gazetted Officer / Principal of the college where studied.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">10)<span style="white-space: pre;"> </span>The candidate belonging to SC / ST category has to submit the attested “CASTE CERTIFICATE” along with the FILLED IN ONLINE APPLICATION FORM” to the Invigilator on day of the AP EAPCET-2021 exam in the Examination Hall, in case, the Application number of his/her Caste Certificate is not provided at the time of the Online submission of the Application.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova";"><span style="font-size: large;"></span></span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">* NOTE: For items 5(a) and 5(b), please don’t paste Photograph and Signature on another paper and scan. Instead scan the photograph and Signature as separate files</span></p><div style="color: #222222; font-size: 13.2px;"><br /></div><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">syllabus: The AP EAMCET or AP EAPCET Syllabus 2021 session will prescribe as per the Syllabus introduced by BIE(BOARD OF INTERMEDIATE EDUCATION), AP, for the intermediate level exam.</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;">Each of the questions will be one mark awarded. There is no negative marking for the right answers</span></p><p style="color: #222222;"><span style="font-family: "Proxima Nova"; font-size: large;"> The entrance exam question will ask to test theintelligent understanding and candidate's knowledge of the subject.</span></p><p style="color: #222222; font-size: 13.2px;"><span style="font-family: "Proxima Nova";"><span style="font-size: medium;"> The Syllabus will include various topics from the subjects of Chemistry,Mathematicsand Physics</span></span></p></div></div></div><div><head><script async="" data-ad-client="ca-pub-1795821529243874" src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><div style="color: black; font-size: large;"><span style="color: #333333;"><b>Eapcet last date to apply with late fee of 5000 rupees 11-08-2021 to 16-08-2021</b></span></div><div style="color: black; font-size: large;"><span style="color: #333333;"><b><br /></b></span></div><div><div style="color: black; font-size: large;"><span style="color: #333333;"><b>Eapcet last date to apply with late fee of 10000 rupees 17-08-2021 to 18-08-2021</b></span></div></div></div></div><div style="color: black; font-size: large;"><span style="color: #333333;"><b><br /></b></span></div><div style="color: black; font-size: large;"><span style="font-size: medium;"><span style="color: #333333;">AP EAPCET 2021 is a Entrance Test to get Admission in Engineering and Agriculure and pharma Colleges through out Andhra Pradesh State.</span></span><h4 style="color: #222222; margin: 0px; position: relative;"><span style="font-family: inherit; font-size: medium;">candidates will be required to fill out the application form of AP EAMCET 2021 AP EAPCET 2021</span></h4><div><span style="font-family: inherit; font-size: medium;"><br /></span></div><div><span style="font-family: inherit; font-size: medium;"><div style="font-size: medium;"><span style="font-size: medium;">The registration fee may be paid through payment gateway/credit,debit/net banking</span></div><div style="font-size: medium;"><span style="font-size: medium;"><br /></span></div><div style="font-size: medium;"><span style="font-size: medium;">Last date for submission with late fee </span></div><div style="font-size: medium;"><span style="font-size: medium;"><br /></span></div><div style="font-size: medium;"><span style="font-size: medium;">Rs500/- 05-08-2021 </span></div><div style="font-size: medium;"><span style="font-size: medium;"><br /></span></div><div style="font-size: medium;"><span style="font-size: medium;">Rs1000/- 10-08-2021</span></div><div style="font-size: medium;"><span style="font-size: medium;"><br /></span></div><div style="font-size: medium;"><span style="font-size: medium;">Rs 5000/- 16-08-2021</span></div><div style="font-size: medium;"><span style="font-size: medium;"><br /></span></div><div style="font-size: medium;"><span style="font-size: medium;">Rs10000/- 18-08-201</span></div><div style="font-size: medium;"><span style="font-size: medium;"><div style="font-size: medium;"><div style="color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; font-size: 13.2px;"><br /></div></div></span></div></span></div><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">Education Minister Adimulapu Suresh said the notification would be released on June 24 2021.</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova";">All other common entrance tests like PGECET (Post Graduate Engineering Common Entrance Test for MTech/MPharma),</span><span style="color: #222222; font-family: "Proxima Nova";">ECET (Engineering Common Entrance Test, lateral entry for diploma holders), EdCET (Education Common Entrance Test for BEd)</span><span style="color: #222222; font-family: "Proxima Nova";">ICET (Integrated Common Entrance Test for MBA/MCA), </span><span style="color: #222222; font-family: "Proxima Nova";">PECET (Physical Education Common Entrance Test for BPEd/UG DPEd) and Lawcet (Law Common Entrance Test for three- and five-year law courses and for PG Law) </span><span style="color: #222222; font-family: "Proxima Nova";"> are proposed to be conducted in the first half of September</span><span style="color: #222222; font-family: "Proxima Nova";">Jawaharlal Nehru Technical University, Kakinada, will relase the AP EAMCET 2021 AP EAPCET 2021 Exam Date</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Candidates must check the AP EAMCET AP EAPCET 2021 eligibility criteria before submitting the application form</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">The details related to AP EAMCET or AP EAPCET Application Form 2021 can check below:</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">AP EAMCET OR AP EAPCET Application form 2021 will be available on the website </span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">Applicants can register and fill the application form online mode from the website</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">Aspirants can check the complete procedure of filling the application form from the instruction booklet available on the website.</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">In case applicants want to correct the details of the application form, they can correct the application from </span></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Mode of payment :</span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">Debit and credit card</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">Net banking</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Aspirants must check the AP EAMCET or AP EAPCET Eligibility before applying for the entrance exam:</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Nationality:</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">The candidate should be Indian National or PIO/OCI cardholders.</span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">Engineering Courses:</span></span></p><p><span style="font-size: medium;"><span style="color: #222222; font-family: "Proxima Nova";">Aspirants must have appearing/passed his/her ten plus two(10+2) with subjects of Chemistry ,Physics and Mathematics as an optional or related vocational program in Engineering</span><span style="color: #222222; font-family: "Proxima Nova";"> and Technology fields conducted by BIE, Telangana/AP</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">He/she must belong to Telangana/AP State and must satisfy Non-Local/Local status requirements laid down in Telangana/AP Educational Institutions.</span></span></p><p><span style="font-size: medium;"><span style="color: #222222; font-family: "Proxima Nova";">He/she must have passed the Diploma examination in Engineering organized by the State Board of Technical Education and Training, </span><span style="color: #222222; font-family: "Proxima Nova";">AP/Telangana or its equivalent recognized by the Board.</span></span></p><p><span style="font-size: medium;"><span style="color: #222222; font-family: "Proxima Nova";"> </span><span style="color: #222222; font-family: "Proxima Nova";">o, get ready to prepare the AP EAPCET 2021 OR AP EAPCET 2021 Previous Question Paper Sets A, B,C, D to get Good marks in Final EAPCET OR EAPCET Exams 2021.</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Age : candidates applying for Engineering programs must have completed 16 years of age on 31st December 2021. No upper age limit prescribed.</span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">Subjects: The question paper will include questions from the subjects of Mathematics, Chemistry, and Physics</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;">Language: The exam paper will be in English And Telugu language.</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Time Duration: The time duration will be three</span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;"> 3 hours.</span></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">AP EAPCET – 2021</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">IMPORTANT INSTRUCTIONS TO THE CANDIDATES</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">1)<span style="white-space: pre;"> </span>The Candidates who wish to apply for APEAPCET-2021 are requested to fill the particulars carefully in the ONLINE APPLICATION FORM. The required information should be collected from the relevant documents.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">2)<span style="white-space: pre;"> </span>The Candidates are requested to check the filled in particulars before pressing SUBMIT button during online application process.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">3)<span style="white-space: pre;"> </span>After submission of ONLINE APPLICATION FORM, if any corrections are to be incorporated, candidate has to see the corrections link in Homepage of https://sche.ap.gov.in/eapcet</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">4)<span style="white-space: pre;"> </span>To fill the required details in ONLINE APPLICATION FORM, the following documents may be referred:</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">S.NO<span style="white-space: pre;"> </span>Details Required<span style="white-space: pre;"> </span>Documents to be referred</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">1.<span style="white-space: pre;"> </span>AP Online/ TS Online Transaction Id. (if</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">payment is being made through AP Online/ TS Online)<span style="white-space: pre;"> </span>Receipt form from AP Online / TS Online</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">2.<span style="white-space: pre;"> </span>Qualifying Examination appeared or passed, Hall<span style="white-space: pre;"> </span>ticket<span style="white-space: pre;"> </span>Number<span style="white-space: pre;"> </span>of<span style="white-space: pre;"> </span>Qualifying</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Examination<span style="white-space: pre;"> </span>Marks<span style="white-space: pre;"> </span>Memo<span style="white-space: pre;"> </span>/<span style="white-space: pre;"> </span>Hall<span style="white-space: pre;"> </span>Ticket Intermediate (10+2) / Equivalent<span style="white-space: pre;"> </span>of</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">3.<span style="white-space: pre;"> </span>Stream Applied for (E), (AM), or both (E &</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">AM)<span style="white-space: pre;"> </span>Eligibility Criteria in the APEAPCET-</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">2020 website</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">4.<span style="white-space: pre;"> </span>Date of Birth, Birth District, Birth State<span style="white-space: pre;"> </span>Birth Certificate / SSC or Equivalent</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Certificate</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">5.<span style="white-space: pre;"> </span>Hall Ticket Number of SSC or Equivalent</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">examination Certificate<span style="white-space: pre;"> </span>SSC or Equivalent Certificate</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">6.<span style="white-space: pre;"> </span>Local Status (OU/AU/SVU/ Non- local)<span style="white-space: pre;"> </span>The local candidate certificate issued by</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">MRO or Competent Authority</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">7.<span style="white-space: pre;"> </span>Income of Parents (Income upto Rs.1.00</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Lakh (or) up to Rs.2.00 Lakhs (or) more than Rs. 2.0 lakhs<span style="white-space: pre;"> </span>The<span style="white-space: pre;"> </span>Income<span style="white-space: pre;"> </span>certificate<span style="white-space: pre;"> </span>issued Competent Authority<span style="white-space: pre;"> </span>by</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">8.<span style="white-space: pre;"> </span>STUDY DETAILS<span style="white-space: pre;"> </span>Study<span style="white-space: pre;"> </span>certificates<span style="white-space: pre;"> </span>from<span style="white-space: pre;"> </span>Class</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Intermediate (10+2) / Equivalent<span style="white-space: pre;"> </span>I<span style="white-space: pre;"> </span>to</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">9.<span style="white-space: pre;"> </span>Category (SC, ST, BC, etc.) and Application</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">number of the Caste Certificate<span style="white-space: pre;"> </span>The latest Caste Certificate issued by</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Competent Authority</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">10.<span style="white-space: pre;"> </span>Special Category (NCC, PH, Sports, CAP,</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">etc.)<span style="white-space: pre;"> </span>The Certificate Issued by Competent</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Authority</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">11.<span style="white-space: pre;"> </span>Aadhaar Card details<span style="white-space: pre;"> </span>Aadhaar Card</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">12.<span style="white-space: pre;"> </span>Ration Card details<span style="white-space: pre;"> </span>Ration Card</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">13.<span style="white-space: pre;"> </span>Economically Weaker Sections Certificate</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">details<span style="white-space: pre;"> </span>EWS Certificate</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">5)<span style="white-space: pre;"> </span>Other Information required for filling Online Application</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">a)<span style="white-space: pre;"> </span>Recent passport size digital color photograph (file size less than 30 KB and “.jpg” file format) of candidate for uploading (whose photograph is not available in Intermediate databases)</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;"> </span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">b)<span style="white-space: pre;"> </span>Digital Signature of the candidate (file size less than 15 KB and “.jpg” file format) of candidate or uploading (whose Signature is not available in Intermediate databases.)</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">c)<span style="white-space: pre;"> </span>Regional Center to which candidate wishes to appear for AP EAPCET-2021 examination. d) Gender (Male / Female/Transgender.)</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">e)<span style="white-space: pre;"> </span>Non-Minority / Minority</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">f)<span style="white-space: pre;"> </span>Mobile Number of the candidate.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">g)<span style="white-space: pre;"> </span>E-mail of the candidate.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">h)<span style="white-space: pre;"> </span>Place of Education - Municipality / Corporation or Rural area in SSC and Intermediate.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;"><br /></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">6)<span style="white-space: pre;"> </span>It is advised to visit your allotted Examination Center well before so that you can take examination tension – free.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">7)<span style="white-space: pre;"> </span>The candidate will not be allowed to take the examination even if late by 1minute.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">8)<span style="white-space: pre;"> </span>The candidate does not have option of choosing specific date / session to appear for the AP EAPCET-2021 entrance examination. This information is known to him / her only after downloading Hall Ticket. For any reason if the candidate fails to appear in the given slot, he / she is treated as absent.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">9)<span style="white-space: pre;"> </span>The candidate has to submit the “FILLED IN ONLINE APPLICATION FORM” to the invigilator in the Examination Hall on the day of the AP EAPCET-2021 exam. Also, affix a recent color photograph (3.5cms x 3.5cms) in the box provided (Bottom – Left side) on the FILLED IN ONLINE APPLICATION FORM and get it attested by a Gazetted Officer / Principal of the college where studied.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">10)<span style="white-space: pre;"> </span>The candidate belonging to SC / ST category has to submit the attested “CASTE CERTIFICATE” along with the FILLED IN ONLINE APPLICATION FORM” to the Invigilator on day of the AP EAPCET-2021 exam in the Examination Hall, in case, the Application number of his/her Caste Certificate is not provided at the time of the Online submission of the Application.</span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;"></span></span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">* NOTE: For items 5(a) and 5(b), please don’t paste Photograph and Signature on another paper and scan. Instead scan the photograph and Signature as separate files</span></p><div><br /></div><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">syllabus: The AP EAMCET or AP EAPCET Syllabus 2021 session will prescribe as per the Syllabus introduced by BIE(BOARD OF INTERMEDIATE EDUCATION), AP, for the intermediate level exam.</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Each of the questions will be one mark awarded. There is no negative marking for the right answers</span></p><p><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;"> The entrance exam question will ask to test theintelligent understanding and candidate's knowledge of the subject.</span></p><p><span style="color: #222222; font-family: "Proxima Nova";"><span style="font-size: medium;"> The Syllabus will include various topics from the subjects of Chemistry,Mathematicsand Physics</span></span></p><div><br style="color: #222222; font-size: 13.2px;" /></div></div><div><br /></div><div><br /></div>
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<script><div><span style="font-size: medium;"><br /></span></div><div><span style="font-size: medium;">Andhra Pradesh State Council of Higher Education has released the AP EAPCET 2021 exam dates Apeamcet is now Eapcet . Eapcet likely be conducted from August 19 to August 25 </span></div><div><div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhUlJZBuxHukXvJo9gGYL7lyoFUz-NvGkPQZup85YxMeMOsk6smTy-1hpKM2Kei1jUAsY3vQDnyN-yTdDuWNas4nZ45UtyPVOT6yhGJ9EujwnX8H5pa9nu9xVZHeY00ifHVA_g50lGk_yAI/s1868/eapcet+apply+online.PNG" style="margin-left: 1em; margin-right: 1em;"><img alt="eapcet" border="0" data-original-height="962" data-original-width="1868" height="238" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhUlJZBuxHukXvJo9gGYL7lyoFUz-NvGkPQZup85YxMeMOsk6smTy-1hpKM2Kei1jUAsY3vQDnyN-yTdDuWNas4nZ45UtyPVOT6yhGJ9EujwnX8H5pa9nu9xVZHeY00ifHVA_g50lGk_yAI/w462-h238/eapcet+apply+online.PNG" title="eapcet" width="462" /></a></div><br /><span style="font-size: medium;"><br /></span></div><meta content="829b014c65128a86c83433978f1318a4" name="propeller"></meta>
<div><table align="center" cellpadding="0" cellspacing="0" class="tr-caption-container" style="margin-left: auto; margin-right: auto; text-align: center;"><tbody><tr><td style="text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjg6Eqq3FHLixD6ZxN7nQ9YePiWDbNkr-cnTpR353g-_FfZQMYsiIdcJPb_pky5yhShwbXUWYK2fNbgprxz0CiCS9EuyocOi02jfWiZJxiHQa9S60rH6GNKfbUSWe5goclAszeaoLNxwxu7/s615/EAPCET.jpg" style="margin-left: auto; margin-right: auto;"><img alt="EAPCET" border="0" data-original-height="615" data-original-width="591" height="640" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjg6Eqq3FHLixD6ZxN7nQ9YePiWDbNkr-cnTpR353g-_FfZQMYsiIdcJPb_pky5yhShwbXUWYK2fNbgprxz0CiCS9EuyocOi02jfWiZJxiHQa9S60rH6GNKfbUSWe5goclAszeaoLNxwxu7/w616-h640/EAPCET.jpg" title="EAPCET" width="616" /></a></td></tr><tr><td class="tr-caption" style="text-align: center;">EAPCET 2021</td></tr></tbody></table><br /><span style="font-size: medium;"><br />Engineering agriculture and pharmacy common entrance test 2021 ap eapcet 2021 of andhra pradesh will be conducted through computer based test by jawaharlal nehru technological university kakinada for entry into the first year of the folloing professional courses offered for the academic year 2021-2022 in the state of andhra pradesh </span></div><div><span style="font-size: medium;"><br /></span></div><div><span style="font-size: medium;">a)Engineering ,Bio technology ,B tech(dairy technology),Btech(agr.engg),Btech(food science and technology)</span></div><div><span style="font-size: medium;">b)B.sc(Ag)/B.sc(hort)/B.V.Sc&A.H/B.F.Sc</span></div><div><span style="font-size: medium;">c)B.pharmacy,pharma D</span></div><div><span style="font-size: large;">candidates who wish to apply for AP EAPCET 3</span></div><div><span style="font-size: medium;">2021 shall submit their application through online mode only the detailed information regarding eligibility,age,syllabus related instructions and procedure for online application are available in the website www.sche.ap.gov.in/eapcet</span></div><div><span style="font-size: medium;">dates timing for the the test and details of registration fee </span></div><div><span style="font-size: medium;">Engineering (E) stream exam dates from 19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12 p.m and 3 p.m to 6 p.m registration fee for O C Rs600/- B C Rs550/- S C/S T Rs500/-</span></div><div><span style="font-size: medium;">Agriculture (A) stream exam dates from 19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12 p.m and 3 p.m to 6 p.m registration fee for O C Rs600/- B C Rs550/- S C/S T Rs500/-</span></div><div><span style="font-size: medium;">E and A both streams exam dates from 19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12 p.m and 3 p.m to 6 p.m registration fee for O C Rs1200/- B C Rs110/- S C/S T Rs1000/-</span></div><div><span style="font-size: medium;">Commencement of application submission : 25-06-2021 </span></div><div><span style="font-size: medium;">Last date for submission without late fee 25-07-2021</span></div><div><span style="font-size: medium;">Downloading of halltickets from website 12-08-2021</span></div><div><span style="font-size: medium;"><br /></span></div><div><span style="font-size: medium;">The registration fee may be paid through payment gateway/credit,debit/net banking</span></div><div><span style="font-size: medium;"><br /></span></div><div><span style="font-size: medium;">Last date for submission with late fee </span></div><div><span style="font-size: medium;"><br /></span></div><div><span style="font-size: medium;">Rs500/- 05-08-2021 </span></div><div><span style="font-size: medium;"><br /></span></div><div><span style="font-size: medium;">Rs1000/- 10-08-2021</span></div><div><span style="font-size: medium;"><br /></span></div><div><div><span style="font-size: medium;">Rs 5000/- 16-08-2021</span></div></div><div><span style="font-size: medium;"><br /></span></div><div><div><span style="font-size: medium;">Rs10000/- 18-08-201</span></div></div><div><span style="font-size: medium;"><br /></span></div><div><span style="background-color: white; color: #333333; font-family: inherit; font-size: large;">Engineering Agricultural And Pharmacy Common Entrance Test </span></div><span style="font-size: medium;"></span><head>
<meta content="33aa2634d1fae1798c4169de918b49c18cca" name="a.validate.01"></meta><div><span style="font-family: inherit;"><span style="color: #333333; font-size: medium;"><b>Ap eapcet exam to be held in august </b></span></span></div><div><span style="font-family: inherit;"><span style="color: #333333; font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Ap eapcet 2021 Important dates </b></span></span></div><div><span style="font-family: inherit;"><span style="color: #333333; font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>EApcet 2021 will be conducted from august 19 to 25</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>From this year this entrance test name changed as Eapcet eapcet 2021 notification will be issued on june 24</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet opening date of application : 26-06-2021</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet closing date of application : 25 -07-2021</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet last date to apply with late fee of 500 rupees 26-07-2021 to 05-08-2021 </b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet last date to apply with late fee of 1000 rupees 06-08-2021 to 10-08-2021</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span><span><div style="color: black; font-size: large;"><span style="color: #333333;"><span><b>Eapcet last date to apply with late fee of 5000 rupees 11-08-2021 to 16-08-2021</b></span></span></div><div style="color: black; font-size: large;"><span style="color: #333333;"><span><b><br /></b></span></span></div><div><span><span><div style="color: black; font-size: large;"><span style="color: #333333;"><span><b>Eapcet last date to apply with late fee of 10000 rupees 17-08-2021 to 18-08-2021</b></span></span></div><div style="color: black; font-size: large;"><span style="color: #333333;"><span><b><br /></b></span></span></div><div><span><span><b><span style="color: black; font-size: medium;">Downloading of hall tickets from the website </span></b></span></span></div></span></span></div><div style="color: #333333; font-size: large;"><span style="color: #333333;"><span><b><br /></b></span></span></div></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b><br /></b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><b>Eapcet exam date : 19-08-2021 to 25-08-2021</b></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><br /></span></span></div><div><span style="color: #333333; font-size: medium;"><div class="separator" style="clear: both; text-align: center;"><iframe allowfullscreen="" class="BLOG_video_class" height="266" src="https://www.youtube.com/embed/B95NRvQucX0" width="320" youtube-src-id="B95NRvQucX0"></iframe></div><br /><span><br /></span></span></div><div><span style="color: #333333; font-size: medium;"><div class="separator" style="clear: both; text-align: center;"><iframe allowfullscreen="" class="BLOG_video_class" height="266" src="https://www.youtube.com/embed/nPr-7n0G99Q" width="320" youtube-src-id="nPr-7n0G99Q"></iframe></div><br /><span><br /></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><br /></span></span></div><div><span style="color: #333333;"><span style="font-size: medium;"><br /></span></span></div><span style="font-size: medium;">><span style="color: #333333;">AP EAPCET 2021 is a Entrance Test to get Admission in Engineering and Agriculure and pharma Colleges through out Andhra Pradesh State.</span></span><h4 style="background-color: white; color: #222222; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; text-align: left;"><span style="font-family: inherit; font-size: medium;"><span>candidates will be required to fill out the application form of AP EAMCET 2021 </span><span>AP EAPCET 2021</span></span></h4><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">Education Minister Adimulapu Suresh said the notification would be released on June 24 2021.</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;"><br /></span></span></p><p style="background-color: white;"><span style="font-size: medium;"><span style="color: #222222; font-family: Proxima Nova;"><span>All other common entrance tests like PGECET (Post Graduate Engineering Common Entrance Test for MTech/MPharma),</span></span><span style="color: #222222; font-family: "Proxima Nova";">ECET (Engineering Common Entrance Test, lateral entry for diploma holders), EdCET (Education Common Entrance Test for BEd)</span><span style="color: #222222; font-family: "Proxima Nova";">ICET (Integrated Common Entrance Test for MBA/MCA), </span><span style="color: #222222; font-family: "Proxima Nova";">PECET (Physical Education Common Entrance Test for BPEd/UG DPEd) and Lawcet (Law Common Entrance Test for three- and five-year law courses and for PG Law) </span><span style="color: #222222; font-family: "Proxima Nova";"> are proposed to be conducted in the first half of September</span><span style="color: #222222; font-family: "Proxima Nova";">Jawaharlal Nehru Technical University, Kakinada, will relase the AP EAMCET 2021 AP EAPCET 2021 Exam Date</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Candidates must check the AP EAMCET AP EAPCET 2021 eligibility criteria before submitting the application form</span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">The details related to AP EAMCET or AP EAPCET Application Form 2021 can check below:</span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">AP EAMCET OR AP EAPCET Application form 2021 will be available on the website </span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">Applicants can register and fill the application form online mode from the website</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">Aspirants can check the complete procedure of filling the application form from the instruction booklet available on the website.</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">In case applicants want to correct the details of the application form, they can correct the application from </span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Mode of payment :</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">Debit and credit card</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">Net banking</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Aspirants must check the AP EAMCET or AP EAPCET Eligibility before applying for the entrance exam:</span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Nationality:</span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">The candidate should be Indian National or PIO/OCI cardholders.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">Engineering Courses:</span></span></p><p style="background-color: white;"><span style="font-size: medium;"><span style="color: #222222; font-family: "Proxima Nova";">Aspirants must have appearing/passed his/her ten plus two(10+2) with subjects of Chemistry ,Physics and Mathematics as an optional or related vocational program in Engineering</span><span style="color: #222222; font-family: "Proxima Nova";"> and Technology fields conducted by BIE, Telangana/AP</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">He/she must belong to Telangana/AP State and must satisfy Non-Local/Local status requirements laid down in Telangana/AP Educational Institutions.</span></span></p><p style="background-color: white;"><span style="font-size: medium;"><span style="color: #222222; font-family: "Proxima Nova";">He/she must have passed the Diploma examination in Engineering organized by the State Board of Technical Education and Training, </span><span style="color: #222222; font-family: "Proxima Nova";">AP/Telangana or its equivalent recognized by the Board.</span></span></p><p style="background-color: white;"><span style="font-size: medium;"><span style="color: #222222; font-family: Proxima Nova;"><span> </span></span><span style="color: #222222; font-family: "Proxima Nova";">o, get ready to prepare the AP EAPCET 2021 OR AP EAPCET 2021 Previous Question Paper Sets A, B,C, D to get Good marks in Final EAPCET OR EAPCET Exams 2021.</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Age : candidates applying for Engineering programs must have completed 16 years of age on 31st December 2021. No upper age limit prescribed.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">Subjects: The question paper will include questions from the subjects of Mathematics, Chemistry, and Physics</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;">Language: The exam paper will be in English And Telugu language.</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Time Duration: The time duration will be three</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;"> 3 hours.</span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">AP EAPCET – 2021</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">IMPORTANT INSTRUCTIONS TO THE CANDIDATES</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;"><br /></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;"><br /></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">1)<span style="white-space: pre;"> </span>The Candidates who wish to apply for APEAPCET-2021 are requested to fill the particulars carefully in the ONLINE APPLICATION FORM. The required information should be collected from the relevant documents.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">2)<span style="white-space: pre;"> </span>The Candidates are requested to check the filled in particulars before pressing SUBMIT button during online application process.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">3)<span style="white-space: pre;"> </span>After submission of ONLINE APPLICATION FORM, if any corrections are to be incorporated, candidate has to see the corrections link in Homepage of https://sche.ap.gov.in/eapcet</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">4)<span style="white-space: pre;"> </span>To fill the required details in ONLINE APPLICATION FORM, the following documents may be referred:</span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: large;">S.NO</span><span style="color: #222222; font-family: "Proxima Nova"; font-size: large; white-space: pre;"> </span><span style="color: #222222; font-family: "Proxima Nova"; font-size: large;">Details Required</span><span style="color: #222222; font-family: "Proxima Nova"; font-size: large; white-space: pre;"> </span><span style="color: #222222; font-family: "Proxima Nova"; font-size: large;">Documents to be referred</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">1.<span style="white-space: pre;"> </span>AP Online/ TS Online Transaction Id. (if</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">payment is being made through AP Online/ TS Online)<span style="white-space: pre;"> </span>Receipt form from AP Online / TS Online</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">2.<span style="white-space: pre;"> </span>Qualifying Examination appeared or passed, Hall<span style="white-space: pre;"> </span>ticket<span style="white-space: pre;"> </span>Number<span style="white-space: pre;"> </span>of<span style="white-space: pre;"> </span>Qualifying</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">Examination<span style="white-space: pre;"> </span>Marks<span style="white-space: pre;"> </span>Memo<span style="white-space: pre;"> </span>/<span style="white-space: pre;"> </span>Hall<span style="white-space: pre;"> </span>Ticket Intermediate (10+2) / Equivalent<span style="white-space: pre;"> </span>of</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">3.<span style="white-space: pre;"> </span>Stream Applied for (E), (AM), or both (E &</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">AM)<span style="white-space: pre;"> </span>Eligibility Criteria in the APEAPCET-</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">2020 website</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">4.<span style="white-space: pre;"> </span>Date of Birth, Birth District, Birth State<span style="white-space: pre;"> </span>Birth Certificate / SSC or Equivalent</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">Certificate</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">5.<span style="white-space: pre;"> </span>Hall Ticket Number of SSC or Equivalent</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">examination Certificate<span style="white-space: pre;"> </span>SSC or Equivalent Certificate</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">6.<span style="white-space: pre;"> </span>Local Status (OU/AU/SVU/ Non- local)<span style="white-space: pre;"> </span>The local candidate certificate issued by</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">MRO or Competent Authority</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">7.<span style="white-space: pre;"> </span>Income of Parents (Income upto Rs.1.00</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">Lakh (or) up to Rs.2.00 Lakhs (or) more than Rs. 2.0 lakhs<span style="white-space: pre;"> </span>The<span style="white-space: pre;"> </span>Income<span style="white-space: pre;"> </span>certificate<span style="white-space: pre;"> </span>issued Competent Authority<span style="white-space: pre;"> </span>by</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">8.<span style="white-space: pre;"> </span>STUDY DETAILS<span style="white-space: pre;"> </span>Study<span style="white-space: pre;"> </span>certificates<span style="white-space: pre;"> </span>from<span style="white-space: pre;"> </span>Class</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">Intermediate (10+2) / Equivalent<span style="white-space: pre;"> </span>I<span style="white-space: pre;"> </span>to</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">9.<span style="white-space: pre;"> </span>Category (SC, ST, BC, etc.) and Application</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">number of the Caste Certificate<span style="white-space: pre;"> </span>The latest Caste Certificate issued by</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">Competent Authority</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">10.<span style="white-space: pre;"> </span>Special Category (NCC, PH, Sports, CAP,</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">etc.)<span style="white-space: pre;"> </span>The Certificate Issued by Competent</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">Authority</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">11.<span style="white-space: pre;"> </span>Aadhaar Card details<span style="white-space: pre;"> </span>Aadhaar Card</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">12.<span style="white-space: pre;"> </span>Ration Card details<span style="white-space: pre;"> </span>Ration Card</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">13.<span style="white-space: pre;"> </span>Economically Weaker Sections Certificate</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">details<span style="white-space: pre;"> </span>EWS Certificate</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;"><br /></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">5)<span style="white-space: pre;"> </span>Other Information required for filling Online Application</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">a)<span style="white-space: pre;"> </span>Recent passport size digital color photograph (file size less than 30 KB and “.jpg” file format) of candidate for uploading (whose photograph is not available in Intermediate databases)</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;"> </span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">b)<span style="white-space: pre;"> </span>Digital Signature of the candidate (file size less than 15 KB and “.jpg” file format) of candidate or uploading (whose Signature is not available in Intermediate databases.)</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">c)<span style="white-space: pre;"> </span>Regional Center to which candidate wishes to appear for AP EAPCET-2021 examination. d) Gender (Male / Female/Transgender.)</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">e)<span style="white-space: pre;"> </span>Non-Minority / Minority</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">f)<span style="white-space: pre;"> </span>Mobile Number of the candidate.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">g)<span style="white-space: pre;"> </span>E-mail of the candidate.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">h)<span style="white-space: pre;"> </span>Place of Education - Municipality / Corporation or Rural area in SSC and Intermediate.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;"><br /></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">6)<span style="white-space: pre;"> </span>It is advised to visit your allotted Examination Center well before so that you can take examination tension – free.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">7)<span style="white-space: pre;"> </span>The candidate will not be allowed to take the examination even if late by 1minute.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">8)<span style="white-space: pre;"> </span>The candidate does not have option of choosing specific date / session to appear for the AP EAPCET-2021 entrance examination. This information is known to him / her only after downloading Hall Ticket. For any reason if the candidate fails to appear in the given slot, he / she is treated as absent.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">9)<span style="white-space: pre;"> </span>The candidate has to submit the “FILLED IN ONLINE APPLICATION FORM” to the invigilator in the Examination Hall on the day of the AP EAPCET-2021 exam. Also, affix a recent color photograph (3.5cms x 3.5cms) in the box provided (Bottom – Left side) on the FILLED IN ONLINE APPLICATION FORM and get it attested by a Gazetted Officer / Principal of the college where studied.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">10)<span style="white-space: pre;"> </span>The candidate belonging to SC / ST category has to submit the attested “CASTE CERTIFICATE” along with the FILLED IN ONLINE APPLICATION FORM” to the Invigilator on day of the AP EAPCET-2021 exam in the Examination Hall, in case, the Application number of his/her Caste Certificate is not provided at the time of the Online submission of the Application.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;"></span></span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova; font-size: medium;">* NOTE: For items 5(a) and 5(b), please don’t paste Photograph and Signature on another paper and scan. Instead scan the photograph and Signature as separate files</span></p><div><br /></div><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">syllabus: The AP EAMCET or AP EAPCET Syllabus 2021 session will prescribe as per the Syllabus introduced by BIE(BOARD OF INTERMEDIATE EDUCATION), AP, for the intermediate level exam.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;">Each of the questions will be one mark awarded. There is no negative marking for the right answers</span></p><p style="background-color: white;"><span style="color: #222222; font-family: "Proxima Nova"; font-size: medium;"> The entrance exam question will ask to test theintelligent understanding and candidate's knowledge of the subject.</span></p><p style="background-color: white;"><span style="color: #222222; font-family: Proxima Nova;"><span style="font-size: medium;"> The Syllabus will include various topics from the subjects of Chemistry,Mathematicsand Physics</span></span></p><div><br /></div></script></head></div>Unknownnoreply@blogger.com3India20.593684 78.96288-7.7165498361788458 43.80663 48.903917836178849 114.11913tag:blogger.com,1999:blog-5675036936367608346.post-27753646611017511992021-07-12T03:34:00.013-07:002021-07-14T07:19:45.959-07:00AP EAPCET AP EAMCET 2021 APPLY ONLINE DOWNLOAD HALL TICKET RESULT<p></p><p class="MsoNormal"><span style="background: white; color: #222222; font-size: 20pt; line-height: 107%;">Engineering agriculture and pharmacy common entrance
test 2021 apply online <o:p></o:p></span></p><p class="MsoNormal"><span style="background: white; font-size: 20pt; line-height: 107%;"> <a href="https://sche.ap.gov.in/EAPCET/Eapcet/EAPCET_PaymentGatewaypage.aspx" target="_blank"><span style="color: #04ff00;">APPLY</span></a><br /></span></p>
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</script></body><span style="color: #2b00fe;"></span><p class="MsoNormal"><span style="background: white; color: #222222; font-size: 20pt; line-height: 107%;">Engineering agriculture and pharmacy common entrance
test 2021 ap eapcet 2021 of andhra pradesh will be conducted
through computer based test by jawaharlal nehru technological university
kakinada for entry into the first year of the folloing professional courses
offered for the academic year 2021-2022 in the state of andhra Pradesh<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">candidates who wish to apply for AP EAPCET 3<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">2021 shall submit their application
through online mode only the detailed information regarding
eligibility,age,syllabus related instructions and procedure for online
application are available in the website www.sche.ap.gov.in/eapcet<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">dates timing for the the test and details of
registration fee <o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Engineering (E) stream exam dates from
19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12
p.m and 3 p.m to 6 p.m registration fee for O C Rs600/-
B C Rs550/- S C/S T Rs500/-<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Agriculture (A) stream exam dates
from 19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12
p.m and 3 p.m to 6 p.m registration fee for O C Rs600/-
B C Rs550/- S C/S T Rs500/-<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">E and A both streams exam dates from
19-08-2021 to 25-08-2021 session timings two sessions per day 9a.m to 12
p.m and 3 p.m to 6 p.m registration fee for O C
Rs1200/- B C Rs110/- S C/S T Rs1000/-<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Commencement of application submission :
25-06-2021 <o:p></o:p></span></p>
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<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Last date for submission without late
fee 25-07-2021<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Downloading of halltickets from website
12-08-2021<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">The registration fee may be paid through
payment gateway/credit,debit/net banking<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Last date for submission with late fee <o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Rs500/- 05-08-2021 <o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Rs1000/- 10-08-2021<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Rs 5000/- 16-08-2021<o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Rs10000/- 18-08-201<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: 20pt; line-height: 107%;"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">AP EAPCET – 2021</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">IMPORTANT INSTRUCTIONS TO THE CANDIDATES</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">1)<span style="mso-tab-count: 1;"> </span>The Candidates
who wish to apply for APEAPCET-2021 are requested to fill the particulars
carefully in the ONLINE APPLICATION FORM. The required information should be
collected from the relevant documents.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">2)<span style="mso-tab-count: 1;"> </span>The Candidates
are requested to check the filled in particulars before pressing SUBMIT button
during online application process.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">3)<span style="mso-tab-count: 1;"> </span>After
submission of ONLINE APPLICATION FORM, if any corrections are to be
incorporated, candidate has to see the corrections link in Homepage of https://sche.ap.gov.in/eapcet</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">4)<span style="mso-tab-count: 1;"> </span>To fill the
required details in ONLINE APPLICATION FORM, the following documents may be
referred:</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">S.NO<span style="mso-tab-count: 1;"> </span>Details
Required<span style="mso-tab-count: 1;"> </span>Documents to be referred</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">1.<span style="mso-tab-count: 1;"> </span>AP Online/ TS
Online Transaction Id. (if</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">payment is being made through AP Online/ TS Online)<span style="mso-tab-count: 1;"> </span>Receipt form from AP Online / TS Online</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">2.<span style="mso-tab-count: 1;"> </span>Qualifying
Examination appeared or passed, Hall<span style="mso-tab-count: 1;"> </span>ticket<span style="mso-tab-count: 1;"> </span>Number<span style="mso-tab-count: 1;"> </span>of<span style="mso-tab-count: 1;"> </span>Qualifying</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Examination<span style="mso-tab-count: 1;"> </span>Marks<span style="mso-tab-count: 1;"> </span>Memo<span style="mso-tab-count: 1;"> </span>/<span style="mso-tab-count: 1;"> </span>Hall<span style="mso-tab-count: 1;"> </span>Ticket
Intermediate (10+2) / Equivalent<span style="mso-tab-count: 2;"> </span>of</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">3.<span style="mso-tab-count: 1;"> </span>Stream Applied
for (E), (AM), or both (E &</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">AM)<span style="mso-tab-count: 1;"> </span>Eligibility
Criteria in the APEAPCET-</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">2020 website</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">4.<span style="mso-tab-count: 1;"> </span>Date of Birth,
Birth District, Birth State<span style="mso-tab-count: 1;"> </span>Birth
Certificate / SSC or Equivalent</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Certificate</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">5.<span style="mso-tab-count: 1;"> </span>Hall Ticket
Number of SSC or Equivalent</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">examination Certificate<span style="mso-tab-count: 1;"> </span>SSC
or Equivalent Certificate</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">6.<span style="mso-tab-count: 1;"> </span>Local Status
(OU/AU/SVU/ Non- local)<span style="mso-tab-count: 1;"> </span>The local
candidate certificate issued by</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">MRO or Competent Authority</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">7.<span style="mso-tab-count: 1;"> </span>Income of
Parents (Income upto Rs.1.00</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Lakh (or) up to Rs.2.00 Lakhs (or) more than Rs. 2.0 lakhs<span style="mso-tab-count: 1;"> </span>The<span style="mso-tab-count: 1;"> </span>Income<span style="mso-tab-count: 1;"> </span>certificate<span style="mso-tab-count: 1;"> </span>issued
Competent Authority<span style="mso-tab-count: 1;"> </span><span style="mso-tab-count: 1;"> </span>by</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">8.<span style="mso-tab-count: 1;"> </span>STUDY DETAILS<span style="mso-tab-count: 1;"> </span>Study<span style="mso-tab-count: 1;"> </span>certificates<span style="mso-tab-count: 1;"> </span>from<span style="mso-tab-count: 1;"> </span>Class</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Intermediate (10+2) / Equivalent<span style="mso-tab-count: 1;"> </span>I<span style="mso-tab-count: 1;"> </span>to</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">9.<span style="mso-tab-count: 1;"> </span>Category (SC,
ST, BC, etc.) and Application</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">number of the Caste Certificate<span style="mso-tab-count: 1;"> </span>The latest Caste Certificate issued by</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Competent Authority</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">10.<span style="mso-tab-count: 1;"> </span>Special Category
(NCC, PH, Sports, CAP,</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">etc.)<span style="mso-tab-count: 1;"> </span>The
Certificate Issued by Competent</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Authority</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">11.<span style="mso-tab-count: 1;"> </span>Aadhaar Card
details<span style="mso-tab-count: 1;"> </span>Aadhaar Card</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">12.<span style="mso-tab-count: 1;"> </span>Ration Card
details<span style="mso-tab-count: 1;"> </span>Ration Card</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">13.<span style="mso-tab-count: 1;"> </span>Economically
Weaker Sections Certificate</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">details<span style="mso-tab-count: 1;"> </span>EWS
Certificate</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">5)<span style="mso-tab-count: 1;"> </span>Other Information
required for filling Online Application</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">a)<span style="mso-tab-count: 1;"> </span>Recent passport
size digital color photograph (file size less than 30 KB and “.jpg” file
format) of candidate for uploading (whose photograph is not available in
Intermediate databases)</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";"> </span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">b)<span style="mso-tab-count: 1;"> </span>Digital Signature
of the candidate (file size less than 15 KB and “.jpg” file format)
of candidate or uploading (whose Signature is not available in
Intermediate databases.)</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">c)<span style="mso-tab-count: 1;"> </span>Regional Center
to which candidate wishes to appear for AP EAPCET-2021 examination. d) Gender
(Male / Female/Transgender.)</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">e)<span style="mso-tab-count: 1;"> </span>Non-Minority /
Minority</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">f)<span style="mso-tab-count: 1;"> </span>Mobile Number
of the candidate.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">g)<span style="mso-tab-count: 1;"> </span>E-mail of the
candidate.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">h)<span style="mso-tab-count: 1;"> </span>Place of
Education - Municipality / Corporation or Rural area in SSC and Intermediate.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">6)<span style="mso-tab-count: 1;"> </span>It is advised
to visit your allotted Examination Center well before so that you can take
examination tension – free.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">7)<span style="mso-tab-count: 1;"> </span>The candidate
will not be allowed to take the examination even if late by 1minute.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">8)<span style="mso-tab-count: 1;"> </span>The candidate
does not have option of choosing specific date / session to appear for the AP
EAPCET-2021 entrance examination. This information is known to him / her only
after downloading Hall Ticket. For any reason if the candidate fails to appear
in the given slot, he / she is treated as absent.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">9)<span style="mso-tab-count: 1;"> </span>The candidate
has to submit the “FILLED IN ONLINE APPLICATION FORM” to the invigilator in the
Examination Hall on the day of the AP EAPCET-2021 exam. Also, affix a recent
color photograph (3.5cms x 3.5cms) in the box provided (Bottom – Left side) on
the FILLED IN ONLINE APPLICATION FORM and get it attested by a Gazetted Officer
/ Principal of the college where studied.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">10)<span style="mso-tab-count: 1;"> </span>The candidate
belonging to SC / ST category has to submit the attested “CASTE CERTIFICATE”
along with the FILLED IN ONLINE APPLICATION FORM” to the Invigilator on day of
the AP EAPCET-2021 exam in the Examination Hall, in case, the Application
number of his/her Caste Certificate is not provided at the time of the Online
submission of the Application.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">* NOTE: For items 5(a) and 5(b), please don’t paste
Photograph and Signature on another paper and scan. Instead scan the photograph
and Signature as separate files</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">syllabus: The AP EAMCET or AP EAPCET Syllabus 2021 session
will prescribe as per the Syllabus introduced by BIE(BOARD OF INTERMEDIATE
EDUCATION), AP, for the intermediate level exam.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Each of the questions will be one mark awarded. There is
no negative marking for the right answers</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";"> The entrance exam question will ask to test
theintelligent understanding and candidate's knowledge of the subject.</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span style="color: #222222; font-family: ""Proxima Nova"",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";"> The Syllabus will include various topics from the
subjects of Chemistry,Mathematicsand Physics<o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in; mso-outline-level: 3;"><span style="color: #333333; font-family: "inherit",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Engineering
Agricultural And Pharmacy Common Entrance Test </span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span style="color: #333333; font-family: "inherit",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">Ap eapcet exam to
be held in august </span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Ap eapcet 2021 Important dates </span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">EApcet 2021 will be conducted from
august 19 to 25</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">From this year this entrance test name changed
as Eapcet eapcet 2021 notification will be issued on june 24</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Eapcet opening date of application :
26-06-2021</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Eapcet closing date of application : 25
-07-2021</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Eapcet last date to apply with late fee of 500
rupees 26-07-2021 to 05-08-2021 </span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Eapcet last date to apply with late fee of
1000 rupees 06-08-2021 to 10-08-2021</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Eapcet last date to apply with late fee of
5000 rupees 11-08-2021 to 16-08-2021</span><span face=""Arial",sans-serif" style="color: black; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: black; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">Eapcet last date to apply with late fee of
10000 rupees 17-08-2021 to 18-08-2021</span><span face=""Arial",sans-serif" style="color: black; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in;"><span face=""Arial",sans-serif" style="color: #333333; font-size: 20pt; mso-fareast-font-family: "Times New Roman";">AP EAPCET 2021 is a Entrance Test to get
Admission in Engineering and Agriculure and pharma Colleges through out
Andhra Pradesh State.</span><span face=""Arial",sans-serif" style="color: black; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="line-height: normal; margin-bottom: 0in; mso-outline-level: 4;"><span style="color: #222222; font-family: "inherit",serif; font-size: 20pt; mso-bidi-font-family: Arial; mso-fareast-font-family: "Times New Roman";">candidates will be
required to fill out the application form of AP EAMCET 2021 AP EAPCET 2021</span><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></p>
<p class="MsoNormal" style="background: white; line-height: normal; mso-margin-bottom-alt: auto; mso-margin-top-alt: auto;"><span face=""Arial",sans-serif" style="color: #222222; font-size: 20pt; mso-fareast-font-family: "Times New Roman";"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: 20pt; line-height: 107%;"><o:p> </o:p></span></p><br /><p></p>Unknownnoreply@blogger.com0India20.593684 78.96288-7.7165498361788458 43.80663 48.903917836178849 114.11913tag:blogger.com,1999:blog-5675036936367608346.post-60717246201154595352021-06-25T23:39:00.003-07:002021-07-03T23:59:14.056-07:00AP EAPCET 2021 Syllabus Agriculture and Pharmacy<h1 style="text-align: left;"><span style="font-size: large;"> AP EAPCET 2021 Syllabus Agriculture and Pharmacy</span></h1><h2 style="text-align: left;"><span style="font-size: large;">SUBJECT: BOTANY</span></h2><h3 style="text-align: left;"><span style="font-size: large;">Botany-I: Intermediate First Year</span></h3><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-I:DIVERSITY IN THE LIVING WORLD:</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>The living world: What is living? Diversity in the living world; Taxonomic categories and taxonomical aids.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>Biological Classification: Five kingdom classification - Monera, Protista, Fungi, Plantae and Animalia, Three domains of life (six kingdom classification), Viruses, Viroids, Prions & Lichens.</span></p><head><script data-ad-client="ca-pub-1795821529243874" async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
</head><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>Science of plants– Botany: Origin, Development, Scope of Botany and Branches of Botany.</span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>Plant Kingdom: Salient features, classification and alternation of generations of the plants of the following groups - Algae, Bryophytes, Pteridophytes, Gymnosperms and Angiosperms.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-II:STRUCTURAL ORGANISATION IN PLANTS- MORPHOLOGY:</span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>Morphology of flowering Plants: Vegetative: Parts of a typical Angiospermic plant; Vegetative morphology and modifications- Root, Stem and Leaf- types; Venation, Phyllotaxy.Reproductive: Inflorescence - Racemose, Cymose and special types (in brief). Flower: Parts of a flower and their detailed description; Aestivation, Placentation. Fruits: Types- True, False and parthenocarpic fruits.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-III:REPRODUCTION IN PLANTS:</span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>Modes of Reproduction: A sexual reproduction, binary fission, Sporulation, budding, fragmentation, vegetative propagation in plants, Sexual reproduction-in brief, Overview of angiosperm life cycle.</span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>Sexual Reproduction in Flowering Plants: Stamen, microsporangium, pollen grain. Pistil, megasporangium (ovule) and embryo sac; Development of male and female gametophytes. Pollination - Types, agents, Out breeding devices and Pollen - Pistil interaction. Double Fertilization; Post fertilisation events: Development of endosperm and embryo; development of seed, Structure of Dicotyledonous and Monocotyledonous seeds, Significance of fruit and seed. Special modes - Apomixis, parthenocarpy, polyembryony.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-IV:PLANT SYSTEMATICS:</span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>Taxonomy of angiosperms: Introduction. Types of Systems of classification (In brief). Semi- Technical description of a typical flowering plant. Description of Families: Fabaceae, Solanaceae and Liliaceae.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-V:CELL STRUCTURE AND FUNCTION:</span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>Cell- The Unit of Life: Cell- Cell theory and cell as the basic unit of life- overview of the cell. Prokaryotic and Eukoryotic cells, Ultra Structure of Plant cell (structure in detail and functions in brief), Cell membrane, Cell wall, Cell organelles: Endoplasmic reticulum, Mitochondria, Plastids, Ribosomes, Golgi bodies, Vacuoles, Lysosomes, Microbodies, Centrosome and Centriole, Cilia, Flagella, Cytoskeleton and Nucleus. Chromosomes: Number, structural organization; Nucleosome.</span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>Biomolecules: Structure and function of Proteins, Carbohydrates, Lipids and Nucleic acids.</span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>Cell cycle and Cell Division: Cell cycle, Mitosis, Meiosis - significance.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-VI:INTERNAL ORGANISATION OF PLANTS:</span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>Histology and Anatomy of Flowering Plants: Tissues - Types, structure and functions: Meristematic; Permanent tissues - Simple and Complex tissues. Tissue systems - Types, structure and function: Epidermal, Ground and Vascular tissue systems. Anatomy of Dicotyledonous and Monocotyledonous plants - Root, Stem and Leaf. Secondary growth in Dicot stem and Dicot root.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">UNIT-VII:PLANT ECOLOGY:</span></p><p><span style="font-size: large;">13.<span style="white-space: pre;"> </span>Ecological Adaptations, Succession and Ecological Services: Introduction. Plant communities and Ecological adaptations: Hydrophytes, Mesophytes and Xerophytes. Plant succession. Ecological services-Carbon fixation, Oxygen release and pollination (in brief).</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Botany-II: Intermediate Second Year</span></p><p><span style="font-size: large;">UNIT-I:PLANT PHYSIOLOGY</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>Transport in Plants: Means of Transport- Diffusion, Facilitated Diffusion, Passive symports and antiports, Active Transport, Comparison of Different Transport Processes, Plant-Water Relations- Water Potential, Osmosis, Plasmolysis, Imbibition, Long Distance Transport of Water- Water Movement up a Plant, Root Pressure, Transpiration pull, Transpiration- Opening and Closing of Stomata, Transpiration and Photosynthesis - a compromise Uptake and Transport of Mineral Nutrients- Uptake of Mineral Ions, Translocation of Mineral Ions, Phloem transport: Flow from Source to Sink-The Pressure Flow or Mass Flow Hypothesis.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>Mineral Nutrition: Methods to Study the Mineral Requirements of Plants, Essential Mineral Elements-Criteria for Essentiality, Macronutrients, Micronutrients, Role of Macro- and Micronutrients, Deficiency Symptoms of Essential Elements, Toxicity of Micronutrients, Mechanism of Absorption of Elements, Translocation of Solutes, Soil as Reservoir of Essential Elements, Metabolism of Nitrogen-Nitrogen Cycle, Biological Nitrogen Fixation, Symbiotic nitrogen fixation, Nodule Formation.</span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>Enzymes: Chemical Reactions, Enzymatic Conversions, Nature of Enzyme Action, Factors Affecting Enzyme Activity, Temperature and pH, Concentration of Substrate, Classification and Nomenclature of Enzymes, Co-factors.</span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>Photosynthesis in Higher Plants: Early Experiments, Site of Photosynthesis, Pigments Involved in Photosynthesis, Light Reaction, The Electron Transport-Splitting of Water, Cyclic and Noncyclic Photo-phosphorylation, Chemiosmotic Hypothesis, Biosynthetic phase- The Primary Acceptor of CO2, The Calvin Cycle, The C4 Pathway, Photorespiration, Factors affecting Photosynthesis.</span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>Respiration of Plants: Cellular respiration, Glycolysis, Fermentation, Aerobic Respiration - Tricarboxylic Acid Cycle, Electron Transport System (ETS) and Oxidative Phosphorylation, The Respiratory Balance Sheet, Amphibolic Pathway, Respiratory Quotient.</span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>Plant Growth and Development: Growth- Plant Growth, Phases of Growth, Growth Rates, Conditions for Growth, Differentiation, Dedifferentiation and Redifferentiation, Development, Plant Growth Regulators- Discovery, PhysiologicalEffectsofPlant Growth Regulators, Auxins,Gibberellins, Cytokinins, Ethylene, Abscisic acid, Seed Dormancy, Photoperiodism, Vernalisation</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-II:MICROBIOLOGY:</span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>Bacteria: Morphology of Bacteria, Bacterial cell structure - Nutrition, Reproduction-Sexual Reproduction, Conjugation, Transformation, Transduction, The importance of Bacteria to Humans.</span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>Viruses: Discovery, Classification of Viruses, structure of Viruses, Multiplication of Bacteriophages – The lytic cycle, The Lysogenic Cycle, Viral diseases in Plants, Viral diseases in Humans.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-III:GENETICS:</span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>Principles of Inheritance and Variation: Mendel’s Experiments, Inheritance of one gene (Monohybrid Cross)-Back cross and Test cross, Law of Dominance, Law of Segregation or Law of purity of gametes, Deviations from Mendelian concept of dominance - Incomplete Dominance, Co- dominance, Explanation of the concept of dominance, Inheritance of two genes- Law of Independent Assortment, Chromosomal Theory of Inheritance, Linkage and Recombination, Mutations, Significance of mutations.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">UNIT-IV:MOLECULAR BIOLOGY:</span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>Molecular Basis of inheritance: The DNA- Structure of Polynucleotide Chain, Packaging of DNA-Helix. The Search for Genetic Material, Transforming Principle, Biochemical Characterisation of Transforming Principle, The Genetic Material is DNA, Properties of Genetic Material (DNA versus RNA), RNA World, Replication - The Experimental Proof, The Machinery and the Enzymes, Transcription-Transcription Unit, Transcription Unit and the Gene, Types of RNA and the process of Transcription, Genetic Code-Mutations and Genetic Code, tRNA- the Adapter Molecule, Translation, Regulation of Gene Expression-The Lac operon.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-V:BIOTECHNOLOGY</span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>Principles and processes of Biotechnology: Principles of Biotechnology-Construction of the first artificial recombinant DNA molecule, Tools of Recombinant DNA Technology-Restriction Enzymes, Cloning Vectors, Competent Host (For Transformation with Recombinant DNA), Processes of Recombinant DNA Technology- Isolation of the Genetic Material (DNA), Cutting of DNA at Specific Locations, Separation and isolation of DNA fragments, Insertion of isolated gene into a suitable vector, Amplification of Gene of Interest using PCR, Insertion of Recombinant DNA into the Host, Cell/Organism, Selection of Transformed host cells, Obtaining the Foreign Gene Product, Downstream Processing.</span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>Biotechnology and its applications: Biotechnological Applications in Agriculture-Bt Cotton, Pest Resistant Plants, Other applications of Biotechnology - Insulin, Gene therapy, Molecular Diagnosis, ELISA, DNA fingerprinting, Transgenic plants, Bio-safety and Ethical issues- Biopiracy.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-VI:PLANTS, MICROBES AND HUMAN WELFARE:</span></p><p><span style="font-size: large;">13.<span style="white-space: pre;"> </span>Strategies for enhancement in food production: Plant Breeding- What is Plant Breeding? Wheat and Rice, Sugarcane, Millets, Plant Breeding for Disease Resistance, Methods of breeding for disease resistance, Mutation, Plant Breeding for Developing Resistance to Insect Pests, Plant Breeding for Improved Food Quality, Single Cell Protein (SCP), Tissue Culture.</span></p><p><span style="font-size: large;">14.<span style="white-space: pre;"> </span>Microbes in Human Welfare: Microbes in Household Products, Microbes in Industrial Products- Fermented Beverages, Antibiotics, Chemicals, Enzymes and other Bioactive Molecules,Microbes in Sewage Treatment, Primary treatment, Secondary treatment or Biological treatment, Microbes in Production of Biogas, Microbes as Biocontrol Agents, Biological control of pests and diseases, Microbes as Biofertilisers, Challenges posed by Microbes.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">DELETIONS FROM BOTANY 2nd YEAR INTERMEDIATESYLLABUS:</span></p><p><span style="font-size: large;">2. Mineral Nutrition: Entire Chapter Deleted.</span></p><p><span style="font-size: large;">6. Plant Growth and Development: 6.1: Growth, 6.2: Differentiation, De-differentiate and Re- differentiation, 6.3: Development, 6.5: Seed dormancy, 6.6: Photo-periodism, 6.7: Vernalisation.</span></p><p><span style="font-size: large;">13. Strategies for enhancement in food production: 13.1.2: Plant breeding for disease resistance, 13.1.3: Plant breeding for developing resistance to insect pests, 13.1.4: Plant breeding for improve feed Quality, 13.2: Single cell Proteins (SCP)</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">SUBJECT: ZOOLOGY</span></p><p><span style="font-size: large;">Zoology-I: Intermediate First Year</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-I: ZOOLOGY - Diversity of Living World:</span></p><p><span style="font-size: large;">What is life?; Nature, Scope & meaning of zoology; Branches of Zoology; Need for classification- Zoos as tools for study of taxonomy; Basic principles of Classification: Biological system of classification- (Phylogenetic classification only); Levels or Hierarchy of classification; Nomenclature</span></p><p><span style="font-size: large;">- Bi &Trinominal; Species concept; Kingdom Animalia; Biodiversity- Meaning and distribution, Genetic diversity, Species diversity, Ecosystem diversity(alpha,beta and gama), other attributes of biodiversity, role of biodiversity, threats to biodiveristy, methods of conservation, IUCN Red data books, Conservation of wild life in India -Legislation, Preservation, Organisations, Threatened species.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-II: STRUCTURAL ORGANIZATION IN ANIMALS:</span></p><p><span style="font-size: large;">Levels of organization, Multicellularity: Diploblastic & Triploblastic conditions; Asymmetry,Symmetry: Radial symmetry, and Bilateral symmetry (Brief account giving one example for each type from the representative phyla); Acoelomates, Pseudocoelomates and Eucoelomates: Schizo&Entero coelomates (Brief account of formation of coelom); Tissues: Epithelial, Connective, Muscular and Nervous tissues.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-III: ANIMAL DIVERSITY-I: INVERTEBRATE PHYLA:</span></p><p><span style="font-size: large;">General Characters –Classification up to Classes with two or three examples – (Brief account only). Porifera; Cnidaria; Ctenophora; Platyhelminthes; Nematoda; Annelida (Include Earthworm as a type study adhering to NCERT text book); Arthropoda; Mollusca; Echinodermata; Hemichordata.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-IV: ANIMAL DIVERSITY-II: PHYLUM: CHORDATA:</span></p><p><span style="font-size: large;">General Characters – Classification up to Classes - (Brief account only with two or three examples). Phylum : Chordata; Sub phylum: Urochordata; Sub phylum: Cephalochordata; Sub phylum : Vertebrata; Super class: Agnatha, Class Cyclostomata; Super class: Gnathostomata, Super class pisces, Class: Chondricthyes, Class: Osteichthyes; Tetrapoda, Class: Amphibia (Include Frog as a type study adhering to NCERT text book), Class: Reptilia, Class: Aves, Class: Mammalia.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-V: LOCOMOTION & REPRODUCTION IN PROTOZOA:</span></p><p><span style="font-size: large;">Locomotion: Definition, types of locomotor structures pseudopodia (basic idea of pseudopodia without going into different types), flagella & cilia (Brief account giving two examples each); Flagellar & Ciliary movement- Effective & Recovery strokes in Euglena, Synchronal & Metachronal movements in Paramecium; Reproduction: Definition, types. Asexual Reproduction: Transeverse binary fission in Paramecium & Longitudinal binary fission in Euglena. Multiple fission, Sexual Reproduction.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-VI: BIOLOGY IN HUMAN WELFARE:</span></p><p><span style="font-size: large;">Parasitism and parasitic adaptation; Health and disease: introduction; Life cycle, Pathogenecity, Treatment & Prevention (Brief account only) 1. Entamoeba histolytica 2. Plasmodium vivax 3. Ascaris lumbricoides 4. Wuchereriabancrofti; Brief account ofpathogenecity, treatment & prevention of Typhoid, Pneumonia, Common cold, & Ring worm; Drugs and Alcohol abuse.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-VII: PERIPLANETA AMERICANA (COCKROACH):</span></p><p><span style="font-size: large;">Habitat and habits; External features; Locomotion; Digestive system; Respiratory system; Circulatory system; Excretory system; Nervous system - sense organs, structure of ommatidium; Reproductive system.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-VIII: ECOLOGY & ENVIRONMENT:</span></p><p><span style="font-size: large;">Organisms and Environment: Ecology, population, communities, habitat, niche, biome and ecosphere</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">(definitions only); Ecosystem: Elementary aspects only, Abiotic factors- Light, Temperature & Water (Biological effects only), Ecological adaptations; Population interactions; Ecosystems: Types, Components, Lake ecosystem; Food chains, Food web, Productivity and Energy flow in Ecosystem, Ecological pyramids - Pyramids of numbers, biomass and energy; Nutritient cycling - Carbon, Nitrogen & Phosphorous cycles (Brief account); Population attributes: Growth, Natality and Mortality, Age distribution, Population regulation; Environmental issues.</span></p><p><span style="font-size: large;">Zoology-II: Intermediate Second Year</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-I:HUMAN ANATOMY AND PHYSIOLOGY-I:</span></p><p><span style="font-size: large;">I-A)Digestion and absorption: Alimentary canal and digestive glands; Role of digestive enzymes and gastrointestinal hormones; Peristalsis, digestion, absorption and assimilation of proteins, carbohydrates and fats, egestion,Calorific value of proteins, carbohydrates and fats; Nutritional disorders: Protein Energy Malnutrition (PEM), Disorders of digestive system- indigestion, constipation, vomiting, jaundice, diarrhea, kwashiorkor.</span></p><p><span style="font-size: large;">I-B) Breathing and Respiration: Respiratory organs in animals; Respiratory system in humans; Mechanism of breathing and its regulation in humans - Exchange of gases, transport of gases and regulation of respiration, Respiratory volumes; Respiratory disorders: Asthma, Emphysema, Occupational respiratory disorders - Asbestosis, Silicosis, Siderosis, Black Lung Disease in coal miners.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-II:HUMAN ANATOMY AND PHYSIOLOGY-II:</span></p><p><span style="font-size: large;">II-A) Body Fluids and Circulation: Clotting of blood; Human circulatory system - structure of human heart and blood vessels; Cardiac cycle, cardiac output, double circulation, regulation of cardiac activity; Disorders of circulatory system: Hypertension, coronary artery disease, angina pectoris, heart failure.</span></p><p><span style="font-size: large;">II-B) Excretory products and their elimination: Modes of excretion- Ammonotelism, Ureotelism, Uricotelism, Human excretory system - structure of kidney and nephron; Urine formation, osmoregulation; Regulation of kidney function -Renin-Angiotensin - Aldosterone system, Atrial Natriuretic Factor, ADH and diabetes insipidus; Role of other organs in excretion; Disorders: Uraemia, renal failure, renal calculi, nephritis, dialysis using artificial kidney.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-III:HUMAN ANATOMY AND PHYSIOLOGY-III:</span></p><p><span style="font-size: large;">III-A)Muscular and Skeletal system: Skeletal muscle - ultra structure; Contractile proteins & muscle contraction, Skeletal system and its functions; Joints. Disorders of the muscular and skeletal system: myasthenia gravis, tetany, muscular dystrophy, arthritis, osteoporosis, gout, regormortis.</span></p><p><span style="font-size: large;">III-B) Neural control and co-ordination: Nervous system in human beings - Central nervous system, Peripheral nervous system and Visceral nervous system, Generation and conduction of nerve impulse; Reflex action; Sensory perception; Sense organs; Brief description of other receptors; Elementary structure and functioning of eye and ear.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-IV:HUMAN ANATOMY AND PHYSIOLOGY-IV:</span></p><p><span style="font-size: large;">IV-A) Endocrine system and chemical co-ordination: Endocrine glands and hormones; Human endocrine system - Hypothalamus, Pituitary, Pineal, Thyroid, Parathyroid, Adrenal, Pancreas, Gonads; Mechanism of hormone action, Role of hormones as messengers and regulators; Hypo and Hyper activity and related disorders: Common disorders - Dwarfism, acromegaly, cretinism, goiter, exophthalmic goiter, diabetes, Addison’s disease, Cushing’s syndrome.</span></p><p><span style="font-size: large;">IV-B) Immune system: Basic concepts of Immunology - Types of Immunity - Innate Immunity, Acquired Immunity, Active and Passive Immunity, Cell mediated Immunity and Humoral Immunity, Interferon, HIV and AIDS.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-V:HUMAN REPRODUCTION:</span></p><p><span style="font-size: large;">V-A) Human Reproductive System: Male and female reproductive systems; Microscopic anatomy of testis & ovary; Gametogenesis, Spermatogenesis & Oogenesis; Menstrual cycle;</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">Fertilization, Embryo development upto blastocyst formation, Implantation; Pregnancy, placenta formation, Parturition, Lactation.</span></p><p><span style="font-size: large;">V-B) Reproductive Health: Need for reproductive health and prevention of sexually transmitted diseases (STD); Birth control - Need and methods, contraception and Pharmacy termination of pregnancy (MTP); Amniocentesis; infertility and assisted reproductive technologies - IVF-ET, ZIFT, GIFT.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-VI:GENETICS:</span></p><p><span style="font-size: large;">Heredity and variations. Mendel’s laws of inheritance with reference to Drosopila(Drosophila melanogaster- Grey, Black body colour; Long, Vestigial wings), Pleiotropy, Multiple alleles and inheritance blood groups, Rh-factor, Codominance ( Blood groups as example), elementary idea of polygenic inheritance, skin colour in humans, sex- determination- in humans, birds, Fumea, genic balance theory of sex detrmination, Haplodiploidy in honey bees; Sex linked inheritance- Haemophilia and colorblindness, Mendelian disorders in humans- Thalassemia, Haemophilia, Sickle cell anaemia, cystic fibrosis, Phenylketonuria, Alkaptonuria; Chromosomal disorders- Down syndrome, Turner’s syndrome, Kleinfiltersyndrome; Genome, Human genome project, and DNA finger printing.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-VII:ORGANIC EVOLUTION:</span></p><p><span style="font-size: large;">Origin of Life, Biological evolution and Evidences for biological evolution (palaeontological, comparative anatomical, embryological and molecular evidences); Theories of evolution: Lamarckism, Darwin’s theory of Evolution-Natural Selection with example (Kettlewell’s experiments on Bistonbetularia), Mutation Theory of Hugo De Vries; Modern synthetic theory of Evolution - Hardy Weinberg law, Evolutionary forces, Types of Natural Selection; Gene flow and genetic drift; Variations (mutations and genetic recombination); Adaptive radiation-viz., Darwin’s finches and adaptive radiation in marsupials Human evolution; Speciation - Allopatric, sympatric; Reproductive isolation.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">UNIT-VIII:APPLIED BIOLOGY:</span></p><p><span style="font-size: large;">Apiculture, Animal Husbandry, Pisciculture, Poultry management, Dairy management, Animal breeding, Bio-Pharmacy Technology, Diagnostic Imaging (X-ray, CT scan, MRI), ECG, EEG, Application of Biotechnology in health, Human insulin and vaccine production; Gene Therapy; Transgenic animals; ELISA; Vaccines, MABs, Cancer biology, stem cells.</span></p><p><span style="font-size: large;">DELETIONS FROM ZOOLOGY 2nd YEARINTERMEDIATE SYLLABUS:</span></p><p><span style="font-size: large;">UNIT-I:HUMAN ANATOMY AND PHYSIOLOGY-I:</span></p><p><span style="font-size: large;">I-A)Digestion and absorption: Entire Chapter Deleted.</span></p><p><span style="font-size: large;">UNIT-III: HUMAN ANATOMY AND PHYSIOLOGY-III:</span></p><p><span style="font-size: large;">III-A) Muscular and Skeletal system: 3.2- The Skeleton, 3.3- Joints, 3.4- Disorders of Muscular and Skeletal system.</span></p><p><span style="font-size: large;">III-B) Neural control and co-ordination: 3.7- Reflex action and Reflex Arc, 3.8- Sensory Reception and Processing, 3.8.1- The Eye, 3.8.2- Mechanism of vision, 3.8.3- The Ear (The stato-Acoustic Receptor), 3.8.4- Mechanism of Hearing only (Except disorders of Human Neural system).</span></p><p><span style="font-size: large;">UNIT-VII: ORGANIC EVOLUTION:Entire Chapter Deleted.</span></p><p><span style="font-size: large;">UNIT-VIII: APPLIED BIOLOGY:8.1- Animal Husbandry, 8.2- Poultry Farm management, 8.3- Bee Keeping, 8.4- Fishery management</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">SUBJECT: PHYSICS</span></p><p><span style="font-size: large;">Physics-I: Intermediate First Year</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>PHYSICAL WORLD: What is physics? Scope and excitement of physics. Physics, technology and society Fundamental forces in nature. Nature of physical laws</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>UNITS AND MEASUREMENTS: The international system of units, Measurement of Length, Measurement of Large Distances, Estimation of Very Small Distances, Size of a Molecule, Range of Lengths, Measurement of Mass, Range of Masses, Measurement of time, Accuracy, precision of instruments and errors in measurement, Systematic errors, random errors, least count error, Absolute Error, Relative Error and Percentage Error, Combination of Errors, Significant figures, Rules for Arithmetic Operations with Significant Figures, Rounding off the Uncertain Digits, Rules for Determining the Uncertainty in the Results of Arithmetic Calculations, Dimensions of Physical Quantities, Dimensional Formulae and dimensional equations, Dimensional Analysis and its Applications, Checking the Dimensional Consistency of Equations, Deducing Relation among the Physical Quantities.</span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>MOTION IN A STRAIGHT LINE: Position, path length and displacement, average velocity and average speed, instantaneous velocity and speed, acceleration, kinematic equations for uniformly accelerated motion, relative velocity.</span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>MOTION IN A PLANE: Scalars and vectors, position and displacement vectors, equality of vectors, multiplication of vectors by real numbers, addition and subtraction of vectors - graphical method, resolution of vectors, vector addition - analytical method, motion in a plane, position vector and displacement, velocity, acceleration, motion in a plane with constant acceleration, relative velocity in two dimensions, projectile motion, equation of path of a projectile, time of maximumheight,maximumheightofaprojectile,horizontalrangeofprojectile,uniformcircularmotion.</span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>LAWS OF MOTION: Aristotle’s fallacy, The law of inertia, Newton’s first law of motion, Newton’s second law of motion, momentum, Impulse, Newton’s third law of motion, Conservation of momentum, Equilibrium of a particle, Common forces in mechanics, friction, types of friction, static, kinetic and rolling frictions, Circular motion, Motion of a car on a level road, Motion of a car on a banked road, solving problems in mechanics.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>WORK, ENERGY AND POWER: The Scalar Product, Notions of work and kinetic energy, The work-energy theorem, Work, Kinetic energy, Work done by a variable force, The work-energy theorem for a variable force, The concept of Potential Energy, The conservation of Mechanical Energy, The Potential Energy of a spring, Various forms of energy, Heat, Chemical Energy, Electrical Energy, The Equivalence of Mass and Energy, Nuclear Energy, The Principle of Conservation of Energy, Power, Collisions, Elastic and Inelastic Collisions, Collisions in one dimension, Coefficient of Restitution and its determination, Collisions in TwoDimensions.</span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>SYSTEMS OF PARTICLES AND ROTATIONAL MOTION: Rigid body motion, Centre of mass, Centre of Gravity, Motion of centre of mass, Linear momentum of a system of particles, Vector product of two vectors, Angular velocity and its relation with linear velocity, Angular acceleration, Kinematics of rotational motion about a fixed axis, Moment of force (Torque), Angular momentum of particle, Torque and angular momentum for a system of a particles, conservation of angular momentum, Equilibrium of a rigid body, Principle of moments, Moment of inertia, Theorems of perpendicular and parallel axes, Dynamics of rotational motion about a fixed axis, Angular momentum in case of rotation about a fixed axis, Rolling motion, Kinetic Energy of RollingMotion.</span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>OSCILLATIONS: Periodic and oscillatory motions, Period and frequency, Displacement, Simple harmonic motion (S.H.M.), Simple harmonic motion and uniform circular motion, Velocity and acceleration in simple harmonic motion, Force law for Simple harmonic Motion, Energy in simple harmonic motion, some systems executing Simple Harmonic Motion,Oscillations due to a spring, The Simple Pendulum, damped simple harmonic motion, Forced oscillations and resonance.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>GRAVITATION: Kepler’s laws, Universal law of gravitation, central forces, the gravitational constant, Acceleration due to gravity of the earth, Acceleration due to gravity below and above the surface of earth, Gravitational potential energy, Escape speed, Orbital Speed, Earth satellites, Energy of an orbiting satellite, Geostationary and polar satellites, Weightlessness.</span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>MECHANICAL PROPERTIES OF SOLIDS: Elastic behavior of solids, Stress and strain, Hooke’s law, Stress-strain curve, Elastic moduli, Young’s Modulus, Determination of Young’s Modulus of the Material of a Wire, Shear Modulus, Bulk Modulus, Poisson’s Ratio, Elastic Potential Energy in a Stretched wire, Applications of elastic behavior of materials.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>MECHANICAL PROPERTIES OF FLUIDS: Pressure, Pascal’s Law, Variation of Pressure with Depth, Atmospheric Pressure and Gauge Pressure, Hydraulic Machines, Archimedes’ Principle, Streamline flow, Bernoulli’s principle, Speed of Efflux, Torricelli’s Law, Venturi- meter, Blood Flow and Heart Attack, Dynamic Lift, Viscosity, Variation of Viscosity of fluids with temperature, Stokes’ Law, Reynolds number, Critical Velocity, Surface tension and Surface Energy, Angle of Contact, Drops and Bubbles, Capillary Rise, Detergents and Surface Tension.</span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>THERMAL PROPERTIES OF MATTER: Temperature and heat, Measurement of temperature, Ideal-gas equation and absolute temperature, Thermal expansion, Specific heat capacity, Calorimetry, Change of state, Triple Point, Regelation, Latent Heat, Heat transfer, Conduction, Convection, Radiation, Black body Radiation, Greenhouse Effect, Newton’s law of cooling and its experimental verification.</span></p><p><span style="font-size: large;">13.<span style="white-space: pre;"> </span>THERMODYNAMICS: Thermal equilibrium, Zeroth law of thermodynamics, Heat, Internal Energy and work, First law of thermodynamics, Specific heat capacity, Specific heat capacity of water, Thermodynamic state variables and equation of State, Thermodynamic processes, Quasi-static process, Isothermal Process, Adiabatic Process, Isochoric Process, Isobaric process, Cyclic process, Heat engines, Refrigerators and heat pumps, Second law of thermodynamics, Reversible and irreversible processes, Carnot engine, Carnot’s theorem.</span></p><p><span style="font-size: large;">14.<span style="white-space: pre;"> </span>KINETIC THEORY: Molecular nature of matter, Behaviour of gases, Boyle’s Law, Charles’ Law, Kinetic theory of an ideal gas, Pressure of an Ideal Gas, Kinetic interpretation of temperature, Law of equipartition of energy, Specific heat capacity, Monatomic Gases, Diatomic Gases, Polyatomic Gases, Specific Heat Capacity of Solids, Specific Heat Capacity of Water, Mean freepath.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Physics-II: Intermediate Second Year</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>WAVES: Transverse and longitudinal waves, displacement relation in a progressive wave, amplitude and phase, wavelength and angular wave number, period, angular frequency and frequency, the speed of a travelling wave, speed of a transverse wave on stretched string, speed of a longitudinal wave (speed of sound), the principle of superposition of waves, reflection of waves, standing waves and normal modes, beats, Doppler effect: source moving and observer stationary, observer moving and source stationary, both source and observer moving.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>RAY OPTICS AND OPTICAL INSTRUMENTS: Reflection of light by spherical mirrors, sign convention, focal length of spherical mirrors, the mirror equation, refraction, total internal reflection, total internal reflection in nature and its technological applications, refraction at spherical surfaces and by lenses, power of a lens, combination of thin lenses in contact, refraction through a prism, dispersion by a prism, some natural phenomena due to sunlight, the rainbow, scattering of light, optical instruments, the eye, the simple and compound microscopes, refracting telescope and Cassegrain reflecting telescope.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>WAVE OPTICS: Huygens principle, refraction and reflection of plane waves using Huygens principle, refraction in a rarer medium (at the denser medium boundary), reflection of a plane wave by</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">a plane surface, the Doppler effect, coherent and incoherent addition of waves, interference of light waves and Young‘s experiment, diffraction, the single slit diffraction, resolving power of optical instruments, the validity of ray optics, polarisation, polarisation by scattering, polarisation by reflection.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>ELECTRIC CHARGES AND FIELDS: Electric charge, conductors and insulators, charging by induction, basic properties of electric charges, additivity of charges, conservation of charge, quantization of charge, Coulomb’s law, forces between multiple charges, electric field, electric field due to a system of charges, physical significance of electric field, electric field lines, electric flux, electric dipole, the field of an electric dipole for points on the axial line and on the equatorial plane, physical significance of dipoles, dipole in a uniform external field, continuous charge distribution, Gauss’s law, applications of Gauss’s law, field due to an infinitely long straight uniformly charged wire, field due to a uniformly charged infinite plane sheet, field due to a uniformly charged thin spherical shell.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>ELECTROSTATIC POTENTIAL AND CAPACITANCE: Electrostatic potential, potential due to a point charge, potential due to an electric dipole, potential due to a system of charges, equipotential surfaces, relation between field and potential, potential energy of a system of charges, potential energy in an external field, potential energy of a single charge, potential energy of a system of two charges in an external field, potential energy of a dipole in an external field, electrostatics of conductors, electrostatic shielding, dielectrics and polarisation, electric displacement, capacitors and capacitance, the parallel plate capacitor, effect of dielectric on capacitance, combination of capacitors, capacitors in series, capacitors in parallel, energy stored in a capacitor, Van de Graaff generator.</span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>CURRENT ELECTRICITY: Electric current, electric current in conductors, Ohm’s law, drift of electrons and the origin of resistivity, mobility, limitations of Ohm’s law, resistivity of various materials, colour code of resistors, Temperature dependence of resistivity, electrical energy, power, combination of resistors – series and parallel. Cells, EMF, internal resistance, cells in series and in parallel, Kirchhoff’s rules, Wheatstone Bridge, Meter Bridge,Potentiometer.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>MOVING CHARGES AND MAGNETISM: Magnetic force, sources and fields, magnetic field, Lorentz force, magnetic force on a current carrying conductor, motion in a magnetic field, helical motion of charged particles, motion in combined electric and magnetic fields, velocity selector, Cyclotron, magnetic field due to a current element, Biot – Savart’s law, Magnetic field on the axis of a circular current loop, Ampere’s circuital law, the solenoid and the toroid, force between two parallel current carrying conductors, the ampere (UNIT), torque on current loop, magnetic dipole, torque on a rectangular current loop in a uniform magnetic field, circular current loop as a magnetic dipole, the magnetic dipole moment of a revolving electron, the Moving Coil Galvanometer; conversion into ammeter and voltmeter.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>MAGNETISM AND MATTER: The bar magnet, the magnetic field lines, bar magnet as an equivalent solenoid, The dipole in a uniform magnetic field, the electrostatic analog, Magnetism and Gauss’s Law, The Earth’s magnetism, magnetic declination and dip, magnetisation and magnetic intensity, susceptibility, magnetic properties of materials; Diamagnetism, Paramagnetism, Ferromagnetism, Hysteresis loop, permanent magnets and electromagnets.</span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>ELECTROMAGNETIC INDUCTION: The experiments of Faraday and Henry, magnetic flux, Faraday’s Law of induction, Lenz’s law and conservation of energy, motional electromotive force, energy consideration - a quantitative study, Eddy currents, inductance, mutual inductance, self- inductance, AC generator.</span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>ALTERNATING CURRENT: AC voltage applied to a resistor, representation of AC current and voltage by rotating vectors - Phasors, AC voltage applied to an inductor, AC voltage applied to a capacitor, AC voltage applied to a series LCR circuit, Phasor – diagram solution, analytical solution, resonance, sharpness of resonance, power in AC circuit, the power factor, LC</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">oscillations,transformers.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>ELECTROMAGNETIC WAVES: Displacement current, Maxwell’s equations, electromagnetic waves, sources of electromagnetic waves, nature of electromagnetic waves, electromagnetic spectrum: radio waves, microwaves, infrared waves, visible rays, ultraviolet rays, X-rays, gamma rays.</span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>DUAL NATURE OF RADIATION AND MATTER: Electron emission, Photoelectric Effect, Hertz’s observations, Hallwachs and Lenard’s observations, experimental study of photoelectric effect, effect of intensity of light on photocurrent, effect of potential on photoelectric current, effect of frequency of incident radiation on stopping potential, Photoelectric effect and Wave theory of Light, Einstein’s Photoelectric equation, Energy Quantum of Radiation, particle nature of light, the photon, wave nature of matter, photocell, Davisson and Germer experiment.</span></p><p><span style="font-size: large;">13.<span style="white-space: pre;"> </span>ATOMS: Alpha particle scattering and Rutherford’s nuclear model of atom, alpha particle trajectory, electron orbits, atomic spectra, spectral series, Bohr model of the hydrogen atom, energy levels,<span style="white-space: pre;"> </span>Franck<span style="white-space: pre;"> </span>–<span style="white-space: pre;"> </span>Hertz<span style="white-space: pre;"> </span>experiment,<span style="white-space: pre;"> </span>the<span style="white-space: pre;"> </span>line spectraofthehydrogenatom,deBroglie’sexplanationofBohr’ssecondpostulateofquantization,LASERligh t.</span></p><p><span style="font-size: large;">14.<span style="white-space: pre;"> </span>NUCLEI: Atomic masses and composition of nucleus, discovery of neutron, size of the nucleus, Mass - Energy and Nuclear Binding Energy, Nuclear Force, Radioactivity, Law of radioactive decay, Alpha decay, Beta decay, Gamma decay, Nuclear Energy, Fission, Nuclear reactor, nuclear fusion, energy generation in stars, controlled thermonuclear fusion.</span></p><p><span style="font-size: large;">15.<span style="white-space: pre;"> </span>SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS: Classification of metals, conductors, and semiconductors on the basis of conductivity and energy bands, Band theory of solids, Intrinsic semiconductor, Extrinsic semiconductor, p-type semiconductor, n-type semiconductor, p-n junction formation, semiconductor diode, p-n junction diode under forward bias, p-n junction diode under reverse bias, Application of junction diode as a rectifier, special purpose p-n junction diodes, Zener diode, Zener diode as voltage regulator, Optoelectronic junction devices, Photodiode, light emitting diode, solar cell. Junction transistor, structure and action, Basic transistor circuit configurations and transistor characteristics, transistor as a switch and as an amplifier (CE – Configuration), Feedback amplifier and transistor oscillator, Digital Electronics and Logic gates, NOT, OR, AND, NAND and NOR Gates,Integrated circuits.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">16.<span style="white-space: pre;"> </span>COMMUNICATION SYSTEMS: Elements of a Communication system, basic terminology used in electronic communication systems, bandwidth of signals, bandwidth of transmission medium, propagation of electromagnetic waves, ground waves, sky waves, space wave, modulation and its necessity, size of the antenna or aerial, effective power radiated by an antenna, mixing up of signals from different transmitters, amplitude modulation, production of amplitude modulated wave, detection of amplitude modulated wave.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">DELETIONS FROM PHYSICS 2nd YEAR INTERMEDIATE SYLLABUS:</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>WAVES: Doppler effected and its two situations.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>RAY OPTICS AND OPTICAL INSTRUMENTS: Reflection of light by spherical mirrors, the mirror equation. Scattering of light reddish appearance of the sun at sunrise and sunset and blue colors of sky.</span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>WAVE OPTICS: Diffraction: Resolving power of optical instruments (microscope and astronomical telescope). Polarisation: Polarisation of reflection (Brewster’s law) plane polarized light (uses) polaroids, polarization by scattering.</span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>ELECTRIC CHARGES AND FIELDS: Application of Gauss’s law: Field due to uniformly charged thin spherical shell (field inside and outside).</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>CURRENT ELECTRICITY: Colour code for carbon resistors, series and parallel Combinations of resistors.</span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>MOVING CHARGES AND MAGNETISM: Cyclofron.</span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>MAGNETISM AND MATTER: Magnetic field intensity due to a magnetic dipole (Bar magnet) along its axis and perpendicular to its axis (Bar magnet as an equivalent solenoid), the dipole in a uniform magnet field Magnetic property of materials (Para, dia and ferro) and its examples, permanent magnets and electromagnets</span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>ALTERNATING CURRENT: Power in AC circuit–The power factor, wattles current.</span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>ELECTROMAGNETIC WAVES: Displacement current.</span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>DUAL NATURE OF RADIATION AND MATTER: Davisson and Germer experiment.</span></p><p><span style="font-size: large;">14.<span style="white-space: pre;"> </span>NUCLEI: Radio activity (alpha, beta and gamma particles and their properties) Law of radioactive decay, half-life and mean life of a Radioactive material, Binding energy per nucleon and its variation with mass number.</span></p><p><span style="font-size: large;">15.<span style="white-space: pre;"> </span>SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS: Purpose of P-N junction diode 1. Zener diode and their characteristics 2. Zener diode as a voltage regulator.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">SUBJECT: CHEMISTRY</span></p><p><span style="font-size: large;">Chemistry-I: IntermediateFirst Year</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>ATOMIC STRUCTURE: Sub- atomic particles; Atomic models –Rutherford’s Nuclear model of atom; Developments to the Bohr’s model of atom; Nature of electromagnetic radiation; Particle nature of electromagnetic radiation- Planck’s quantum theory; Bohr’s model for Hydrogen atom; Explanation of line spectrum of hydrogen; Limitations of Bohr’s model; Quantum mechanical considerations of sub atomic particles; Dual behaviour of matter; Heisenberg’s uncertainty principle; Quantum mechanical model of an atom. Important features of Quantum mechanical model of atom; Orbitals and quantum numbers; Shapes of atomic orbitals; Energies of orbitals; Filling of orbitals in atoms. Aufbau Principle, Pauli’s exclusion Principle and Hund’s rule of maximum multiplicity; Electronic configurations of atoms; Stability of half-filled and completely filledorbitals.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES: Need to classify elements; Genesis of periodic classification; Modern periodic law and present form of the periodic table; Nomenclature of elements with atomic number greater than 100; Electronic configuration<span style="white-space: pre;"> </span>of<span style="white-space: pre;"> </span>elements<span style="white-space: pre;"> </span>and theperiodictable;Electronicconfigurationandtypesofelementss,p,d.andfblocks;Trendsinphysicalproperti es:(a) Atomic radius, (b) Ionic radius (c) Variation of size in inner transition elements, (d) Ionization enthalpy,(e) Electron gain enthalpy, (f) Electro negativity; Periodic trends in chemical properties: (a) Valence or Oxidation states, (b) Anomalous properties of second period elements - diagonal relationship; Periodic trends and chemical reactivity.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>CHEMICAL BONDING AND MOLECULAR STRUCTURE: Kossel - Lewis approach to chemical bonding, Octet rule, Representation of simple molecules, formal charges, limitations of octet rule; Ionic or electrovalent bond - Factors favourable for the formation of ionic compounds- Crystal structure of sodium chloride, General properties of ionic compounds; Bond Parameters - bond length, bond angle, and bond enthalpy, bond order, resonance-Polarity of bonds dipole moment-Fajan rules; Valence Shell Electron Pair Repulsion (VSEPR) theory; Predicting the geometry of simple molecules; Valence bond theory-Orbital overlap concept-Directional properties of bonds-overlapping of atomic orbitals-types of overlapping and nature of covalent bonds-strength of sigma and pi bonds-Factors favouring the formation of covalent bonds; Hybridisation- different types of hybridization involving s, p and d orbitals- shapes of simple covalent molecules; Coordinate bond - definition with examples; Molecular orbital theory - Formation of molecular orbitals, Linear combination of atomic orbitals (LCAO)-conditions for combination of atomic orbitals - Energy level diagrams for molecular orbitals</span></p><p><span style="font-size: large;">-Bonding in some homo nuclear diatomic molecules- H2, He2, Li2, B2, C2, N2 and O2; Hydrogen bonding-cause of formation of hydrogen bond - Types of hydrogen bonds-inter and intra molecular- General properties of hydrogen bonds.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>STATES OF MATTER: GASES AND LIQUIDS: Intermolecular forces; Thermal Energy; Intermolecular forces Vs Thermal interactions; The Gaseous State; The Gas Laws; Ideal gas equation; Graham’s law of diffusion - Dalton’s Law of partial pressures; Kinetic molecular theory of gases; Kinetic gas equation of an ideal gas (No derivation) deduction of gas laws from Kinetic gas equation; Distribution of molecular speeds - rms, average and most probable speeds-Kinetic energy of gas molecules; Behaviour of real gases - Deviation from Ideal gas behaviour - Compressibility factor Vs Pressure diagrams of real gases; Liquefaction of gases; Liquid State - Properties of Liquids in terms of Inter molecular interactions - Vapour pressure, Viscosity and Surface tension (Qualitative idea only. No mathematical derivation).</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>STOICHIOMETRY: Some Basic Concepts - Properties of matter - uncertainty in Measurement- significant figures, dimensional analysis; Laws of Chemical Combinations - Law of Conservation of Mass, Law of Definite Proportions, Law of Multiple Proportions, Gay Lussac’s Law of Gaseous Volumes, Dalton’s Atomic Theory, Avogadro Law, Examples; Atomic and molecular masses- mole concept and molar mass. Concept of equivalent weight; Percentage composition of compounds and</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">calculations of empirical and molecular formulae of compounds; Stoichiometry and stoichiometriccalculations-limiting reagent; Methods of Expressing concentrations of solutions-mass percent, mole fraction, molarity, molality and normality; Redox reactions-classical idea of redox reactions, oxidation and reduction reactions-redox reactions in terms of electron transfer; Oxidation number concept; Types of Redox reactions- combination, decomposition, displacement and disproportionation reactions; Balancing of redox reactions - oxidation number method Half reaction (ion-electron) method; Redox reactions inTitrimetry.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>THERMODYNAMICS: Thermodynamic Terms; The system and the surroundings; Types of systems and surroundings; The state of the system; The Internal Energy as a State Function. (a) Work</span></p><p><span style="font-size: large;">(b) Heat (c) The general case, the first law of Thermodynamics; Applications; Work; Enthalpy, H- a useful new state function; Extensive and intensive properties; Heat capacity; The relationship between Cp and Cv; Measurement of U and H: Calorimetry; Enthalpy change, rH of reactions - reaction Enthalpy (a) Standard enthalpy of reactions, (b) Enthalpy changes during transformations, (c) Standard enthalpy of formation, (d) Thermo chemical equations (e) Hess’s law of constant Heat summation; Enthalpies for different types of reactions. (a) Standard enthalpy of combustion (∆cH),</span></p><p><span style="font-size: large;">(b) Enthalpy of atomization (∆aH), phase transition, sublimation and ionization, (c) Bond Enthalpy (∆bondH), (d) Enthalpy of solution (∆solH) and dilution-lattice enthalpy; Spontaneity. (a) Is decrease in enthalpy a criterion for spontaneity? (b) Entropy and spontaneity, the second law of thermodynamics, (c) Gibbs Energy and spontaneity; Gibbs Energy change and equilibrium; Absolute entropy and the third law ofthermodynamics.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>CHEMICAL EQUILIBRIUM AND ACIDS-BASES: Equilibrium in Physical process; Equilibrium in chemical process - Dynamic Equilibrium; Law of chemical Equilibrium - Law of mass action and Equilibrium constant; Homogeneous Equilibria, Equilibrium constant in gaseous systems. Relationship between KP and Kc; Heterogeneous Equilibria; Applications of Equilibrium constant; Relationship between Equilibrium constant K, reaction quotient Q and Gibbs energy G; Factors affecting Equilibria.-Le-chatlier principle application to industrial synthesis of Ammonia and Sulphur trioxide; Ionic Equilibrium in solutions; Acids, bases and salts- Arrhenius, Bronsted-Lowry and Lewis concepts of acids and bases; Ionisation of Acids and Bases - Ionisation constant of water and its ionic product- pH scale-ionisation constants of weak acids-ionisation of weak bases-relation between Ka and Kb-Di and poly basic acids and di and poly acidic Bases-Factors affecting acid strength- Common ion effect in the ionization of acids and bases-Hydrolysis of salts and pH of their solutions; Buffer solutions- designing of buffer solution-Preparation of Acidic buffer; Solubility Equilibria of sparingly soluble salts. Solubility product constant Common ion effect on solubility of Ionic salts.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>HYDROGEN AND ITS COMPOUNDS: Position of hydrogen in the periodic table; Dihydrogen- Occurrence and Isotopes; Preparation of Dihydrogen; Properties of Dihydrogen; Hydrides: Ionic, covalent, and non-stoichiometric hydrides; Water: Physical properties; structure of water, ice. Chemical properties of water; hard and soft water, Temporary and permanent hardness of water; Hydrogen peroxide: Preparation; Physical properties; structure and chemical properties; storage and uses; Heavy Water; Hydrogen as a fuel.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>THE s - BLOCK ELEMENTS (ALKALI AND ALKALINE EARTH METALS):</span></p><p><span style="font-size: large;">Group 1 Elements : Alkali metals; Electronic configurations; Atomic and Ionic radii; Ionization enthalpy; Hydration enthalpy; Physical properties; Chemical properties; Uses; General characteristics of the compounds of the alkali metals: Oxides; Halides; Salts of oxo Acids; Anomalous properties of Lithium: Differences and similarities with other alkali metals, Diagonal relationship; similarities between Lithium and Magnesium; Some important compounds of Sodium: Sodium Carbonate; Sodium Chloride; Sodium Hydroxide; Sodium hydrogen carbonate; Biological importance of Sodium andPotassium.</span></p><p><span style="font-size: large;">Group 2 Elements: Alkaline earth elements; Electronic configuration; Ionization enthalpy; Hydration enthalpy; Physical properties, Chemical properties; Uses; General characteristics of compounds of the Alkaline Earth Metals: Oxides, hydroxides, halides, salts of oxoacids (Carbonates; Sulphates and Nitrates); Anomalous behavior of Beryllium; its diagonal relationship with Aluminium; Some</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">important compounds of calcium: Preparation and uses of Calcium Oxide; Calcium Hydroxide; Calcium Carbonate; Plaster of Paris; Cement; Biological importance of Calcium andMagnesium.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>p- BLOCK ELEMENTS GROUP 13 (BORON FAMILY): General introduction - Electronic configuration, Atomic radii, Ionization enthalpy, Electro negativity; Physical & Chemical properties; Important trends and anomalous properties of boron; Some important compounds of boron - Borax, Ortho boric acid, diborane; Uses of boron, aluminium and their compounds.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>p-BLOCK ELEMENTS - GROUP 14 (CARBON FAMILY): General introduction - Electronic configuration, Atomic radii, Ionization enthalpy, Electro negativity; Physical & Chemical properties; Important trends and anomalous properties of carbon; Allotropes of carbon; Uses of carbon; Some important compounds of carbon and silicon - carbon monoxide, carbon dioxide, Silica, silicones, silicates and zeolites.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>ENVIRONMENTAL CHEMISTRY: Definition of terms: Air, Water and Soil Pollutions; Environmental Pollution; Atmospheric pollution; Tropospheric Pollution; Gaseous Air Pollutants (Oxides of Sulphur; Oxides of Nitrogen; Hydrocarbons; Oxides of Carbon (CO, CO2). Global warming and Greenhouse effect; Acid Rain- Particulate Pollutants- Smog; Stratospheric Pollution: Formation and breakdown of Ozone- Ozone hole- effects of depletion of the Ozone Layer; Water Pollution: Causes of Water Pollution; International standards for drinking water; Soil Pollution: Pesticides, Industrial Wastes; Strategies to control environmental pollution- waste Management- collection and disposal; Green Chemistry: Green chemistry in day-to-day life; Dry cleaning of clothes; Bleaching of paper; Synthesis ofchemicals.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">13.<span style="white-space: pre;"> </span>ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES AND HYDROCARBONS: General introduction; Tetravalency of Carbon: shapes of organic compounds; Structural representations of organic compounds; Classification of organic compounds; Nomenclature of organic compounds; Isomerism; Fundamental concepts in organic reaction mechanisms; Fission of covalent bond; Nucleophiles and electrophiles; Electron movements in organic reactions; Electron displacement effects in covalent bonds: inductive effect, resonance, resonance effect, electromeric effect, hyper conjugation; Types of Organic reactions; Methods of purification of organic compounds; Qualitative elemental analysis of organic compounds; Quantitative elemental analysis of organiccompounds.</span></p><p><span style="font-size: large;">Hydrocarbons: Classification of Hydrocarbons; Alkanes - Nomenclature, isomerism (structural and conformations of ethane only); Preparation of alkanes; Properties - Physical properties and chemical Reactivity, Substitution reactions - Halogenation(free radical mechanism), Combustion, Controlled Oxidation, Isomerisation, Aromatization, reaction with steam and Pyrolysis; Alkenes- Nomenclature, structure of ethene, Isomerism (structural and geometrical); Methods of preparation; Properties- Physical and chemical reactions: Addition of Hydrogen, halogen, water, sulphuric acid, Hydrogen halides (Mechanism- ionic and peroxide effect, Markovnikov’s, anti-Markovnikov’s or Kharasch effect). Oxidation, Ozonolysis and Polymerization; Alkynes - Nomenclature and isomerism, structure of acetylene. Methods of preparation of acetylene; Physical properties, Chemical reactions- acidic character of acetylene, addition reactions- of hydrogen, Halogen, Hydrogen halides and water. Polymerization; Aromatic Hydrocarbons: Nomenclature and isomerism, Structure of benzene, Resonance and aromaticity; Preparation of benzene. Physical properties. Chemical properties: Mechanism of electrophilic substitution. Electrophilic substitution reactions- Nitration, Sulphonation, Halogenation, Friedel-Craft’ alkylation and acylation; Directive influence of functional groups in mono substituted benzene, Carcinogenicity andtoxicity.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Chemistry-II: Intermediate Second Year</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>SOLID STATE: General characteristics of solid state; Amorphous andcrystalline solids; Classification of crystallinesolids based on different binding forces (molecular, ionic, metallic and covalent solids); Probing the structure of solids: X-ray crystallography; Crystal lattices and unit cells.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">Bravais lattices primitive and centered unit cells; Number of atoms in a unit cell (primitive, body centered and face centered cubic unit cell); Close packed structures: Close packing in one dimension, in two dimensions and in three dimensions- tetrahedral and octahedral voids- formula of a compound and number of voids filled- locating tetrahedral and octahedral voids; Packing efficiency in simple cubic, bcc and in hcp, ccp lattice; Calculations involving unit cell dimensions-density of the unit cell; Imperfections in solids-types of point defects-stoichiometric and non-stoichiometric defects; Electrical properties-conduction of electricity in metals, semiconductors and insulators- band theory of metals;Magnetic properties.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>SOLUTIONS: Types of solutions; Expressing concentration of solutions - mass percentage, volume percentage, mass by volume percentage, parts per million, mole fraction, molarity and molality; Solubility: Solubility of a solid in a liquid, solubility of a gas in a liquid, Henry’s law; Vapour pressure of liquid solutions: vapour pressure of liquid- liquid solutions. Raoult’s law as a special case of Henry’s law -vapour pressure of solutions of solids in liquids; Ideal and non-ideal solutions; Colligative properties and determination of molar mass-relative lowering of vapour pressure- elevation of boiling point-depression of freezing point-osmosis and osmotic pressure- reverse osmosis and water purification; Abnormal molar masses-van’t Hofffactor.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>ELECTROCHEMISTRY AND CHEMICAL KINETICS:</span></p><p><span style="font-size: large;">Electrochemistry: Electrochemical cells; Galvanic cells: measurement of electrode potentials; Nernst equation- equilibrium constant from Nernst equation- electrochemical cell and Gibbs energy of the cell reaction; Conductance of electrolytic solutions- measurement of the conductivity of ionic solutions-variation of conductivity and molar conductivity with concentration-strong electrolytes and weak electrolytes-applications of Kohlrausch’s law; Electrolytic cells and electrolysis: Faraday’s laws of electrolysis-products of electrolysis; Batteries: primary batteries and secondary batteries; Fuel cells; Corrosion ofmetals-Hydrogen economy.</span></p><p><span style="font-size: large;">Chemical Kinetics: Rate of a chemical reaction; Factors influencing rate of a reaction: dependence of rate on concentration- rate expression and rate constant- order of a reaction, molecularity of a reaction; Integrated rate equations-zero order reactions-first order reactions- half-life of a reaction; Pseudo first order reaction; Temperature dependence of the rate of a reaction -effect of catalyst; Collision theory of chemical reactionrates.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>SURFACE CHEMISTRY: Adsorption : Distinction between adsorption and absorption- mechanism of adsorption-types of adsorption- characteristics of physisorption-characteristics of chemisorption-adsorption isotherms-adsorption from solution phase-applications of adsorption; Catalysis: Catalysts, promoters and poisons-auto catalysis- homogeneous and heterogeneous catalysis-adsorption theory of heterogeneous catalysis-important features of solid catalysts: (a)activity (b)selectivity-shape-selective catalysis by zeolites-enzyme catalysis-characteristics and mechanism- catalysts in industry; Colloids; Classification of colloids: Classification based on physical state of dispersed phase and dispersion medium- classification based on nature of interaction between dispersed phase and dispersion medium- classification based on type of particles of the dispersed phase- multi molecular, macromolecular and associated colloids- cleansing action of soaps- preparation of colloids-purification of colloidal solutions-properties of colloidal solutions: Colligative properties, Tyndal effect, colour, Brownian movement-charge on colloidal particles, electrophoresis; coagulation-precipitation methods-coagulation of lyophilic sols and protection of colloids- Emulsions; Colloids around us- application ofcolloids.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>GENERAL PRINCIPLES OF METALLURGY: Occurrence of metals; Concentration of ores- levigation, magnetic separation, froth floatation, leaching; Extraction of crude metal from concentrated ore-conversion to oxide, reduction of oxide to the metal; Thermodynamic principles of metallurgy – Ellingham diagram-limitations-applications-extraction of iron, copper and zinc from their oxides; Electrochemical principles of metallurgy; Oxidation and reduction; Refining of crude metal-distillation, liquation poling, electrolytic refining, zone refining and vapour phase refining; Uses of aluminium, copper, zinc and iron.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>p-BLOCK ELEMENTS:</span></p><p><span style="font-size: large;">Group-15 Elements: Occurrence- electronic configuration, atomic and ionic radii, ionisation enthalpy, electronegativity, physical and chemical properties; Dinitrogen-preparation, properties and uses; Compounds of nitrogen-preparation, properties and uses of ammonia; Oxides of nitrogen; Preparation and properties of nitric acid; Phosphorous-allotropic forms; Phosphine-preparation, properties and uses; Phosphorous halides; Oxoacids of phosphorous</span></p><p><span style="font-size: large;">Group-16 Elements: Occurrence- electronic configuration, atomic and ionic radii, ionisation</span></p><p><span style="font-size: large;">enthalpy, electron gain enthalpy,electronegativity,physical and chemical<span style="white-space: pre;"> </span>properties; manufacture, properties anduses.</span></p><p><span style="font-size: large;">Group-17 Elements: Occurrence, electronic configuration, atomic and ionic radii, ionisation enthalpy, electron gain enthalpy, electro negativity, physical and chemical properties; Chlorine- preparation, properties and uses;Hydrogen chloride- preparation, properties and uses; Oxoacids of halogens; Interhalogen compounds- preparation, properties and uses.</span></p><p><span style="font-size: large;">Group-18 Elements: Occurrence, electronic configuration, ionization enthalpy, atomic radii, electron gain enthalpy, physical and chemical properties(a) Xenon-fluorine compounds- XeF2,XeF4 and XeF6 - preparation, hydrolysis and formation of fluoro anions-structures of XeF2, XeF4 and XeF6 (b) Xenon- oxygen compounds XeO3 and XeOF4 - their formation and structures-uses of noblegases.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>d AND f BLOCK ELEMENTS & COORDINATIONCOMPOUNDS:</span></p><p><span style="font-size: large;">d and f block elements: Position in the periodic table; Electronic configuration of the d-block elements; General properties of the transition elements (d-block) -physical properties, variation in atomic and ionic sizes of transition series, ionisation enthalpies, oxidation states, trends in the M²+/M and M³+/M²+ standard electrode potentials, trends in stability of higher oxidation states, chemical reactivity and Eθ values, magnetic properties, formation of coloured ions, formation of complex compounds, catalytic properties, formation of interstitial compounds, alloy formation; Some important compounds of transition elements-oxides and oxoanions of metals-preparation, properties and uses of potassium dichromate and potassium permanganate-structures of chromate, dichromate, manganate and permanganate ions; Inner transition elements(f-block)-lanthanoids- electronic configuration-atomic and ionic sizes-oxidation states- general characteristics; Actinoids-electronic configuration atomic and ionic sizes, oxidation states, general characteristics and comparison with lanthanoids; Some applications of d and f block elements.</span></p><p><span style="font-size: large;">Coordination compounds: Werner’s theory of coordination compounds; Definitions of some terms used in coordination compounds; Nomenclature of coordination compounds-IUPAC nomenclature; Isomerism in coordination compounds- (a)Stereo Isomerism-Geometrical and optical isomerism (b)Structural isomerism-linkage, coordination, ionisation and hydrate isomerism; Bonding in coordination compounds. (a)Valence bond theory - magnetic properties of coordination compounds- limitations of valence bond theory (b) Crystal field theory (i) Crystal field splitting in octahedral and tetrahedral coordination entities (ii) Colour in coordination compounds- limitations of crystal field theory; Bonding in metal carbonyls; Stability of coordination compounds; Importance and applications of coordinationcompounds.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>POLYMERS: Classification of Polymers -Classification based on source, structure, mode of polymerization, molecular forces and growth polymerization; Types of polymerization reactions- addition polymerization or chain growth polymerization-ionic polymerization, free radical mechanism-preparation of addition polymers-polythene, teflon and polyacrylonitrile-condensation polymerization or step growth polymerization-polyamides-preparation of Nylon 6,6 and nylon 6- poly esters-terylene-bakelite, melamine-formaldehyde polymers; copolymerization- Rubber- natural rubber-vulcanisation of rubber-Synthetic rubbers-preparation of neoprene and buna-N; Molecular mass of polymers-number average and weight average molecular masses- poly dispersity index(PDI); Biodegradable polymers-PHBV, Nylon 2-nylon 6; Polymers of commercial importance-polypropene, polystyrene, polyvinylchloride (PVC), urea-formaldehyde resin, glyptal and bakelite - their monomers, structures anduses.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>BIOMOLECULES: Carbohydrates - Classification of carbohydrates- Monosaccharides: preparation of glucose from sucrose and starch- Properties and structure of glucose- D,L</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">configurations and (+), (-) notations of glucose-Structure of fructose; Disaccharides: Sucrose- preparation, structure; Invert sugar- Structures of maltose and lactose- Polysaccharides: Structures of starch, cellulose and glycogen- Importance of carbohydrates; Proteins- Aminoacids: Natural aminoacids-classification of aminoacids - structures and D and L forms-Zwitter ions; Proteins: Structures, classification, fibrous and globular- primary, secondary, tertiary and quarternary structures of proteins- Denaturation of proteins; Enzymes: Enzymes, mechanism of enzyme action; Vitamins: Explanation-names- classification of vitamins - sources of vitamins-deficiency diseases of different types of vitamins; Nucleic acids: chemical composition of nucleic acids, structures of nucleic acids, DNA finger printing biological functions of nucleic acids; Hormones: Definition, different types of hormones, their production, biological activity, diseases due to their abnormalactivities.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>CHEMISTRY IN EVERYDAY LIFE: Drugs and their classification: (a) Classification of drugs on the basis of pharmacological effect (b) Classification of drugs on the basis of drug action (c) Classification of drugs on the basis of chemical structure (d) Classification of drugs on the basis of molecular targets; Drug-Target Interaction-Enzymes as drug targets (a) Catalytic action ofenzymes (b) Drug-enzyme interaction, receptors as drug targets; Therapeutic action of different classes of drugs: antacids, antihistamines, neurologically active drugs: tranquilizers, analgesics-non-narcotic, narcotic analgesics, antimicrobials-antibiotics, antiseptics and disinfectants- antifertility drugs; Chemicals in food-artificial sweetening agents, food preservatives, antioxidants in food; Cleansing agents-soaps and synthetic detergents – types and examples.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>HALOALKANES AND HALOARENES: Classification and nomenclature; Nature of C-X bond; Methods of preparation: Alkyl halides and aryl halides- from alcohols, from hydrocarbons</span></p><p><span style="font-size: large;">(a) by free radical halogenation (b) by electrophilic substitution (c) by replacement of diazonium group(Sandmeyer reaction) (d) by the addition of hydrogen halides and halogens to alkenes-by halogen exchange reactions; Physical properties-melting and boiling points, density and solubility; Chemical reactions: Reactions of haloalkanes (i)Nucleophilic substitution reactions (a) SN² mechanism (b)SN¹ mechanism (c) stereochemical aspects of nucleophilic substitution reactions- optical activity (ii) Eliminationreactions</span></p><p><span style="font-size: large;">(iii) Reaction with metals-Reactions of haloarenes: (i) Nucleophilic substitution (ii)Electrophilic substitution and (iii) Reaction with metals; Polyhalogen compounds: Uses and environmental effects of dichloro methane, trichloromethanetriiodomethane, tetrachloro methane, freons andDDT.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>ORGANIC COMPOUNDS CONTAINING C, H AND O (ALCOHOLS, PHENOLS, ETHERS, ALDEHYDES, KETONES</span></p><p><span style="font-size: large;">AND CARBOXYLIC ACIDS):</span></p><p><span style="font-size: large;">Alcohols, Phenols and Ethers:Alcohols, phenols and ethers -classification; Nomenclature: (a)Alcohols, (b)phenols and (c) ethers; Structures of hydroxy and ether functional groups; Methods of preparation: Alcoholsfrom alkenes and carbonyl compounds, from Grignard reagents; Phenolsfrom haloarenes, benzene sulphonic acid, diazonium salts, cumene; Physical properties of alcohols and phenols; Chemical reactions of alcohols and phenols (i) Reactions involving cleavage of O-H bond in alcohols-Acidity of alcohols and phenols, esterification (ii) Reactions involving cleavage of C- O bond- reactions with HX, PX3, dehydration and oxidation (iii) Reactions of phenols- electrophilic aromatic substitution, Kolbe’s reaction, Reimer - Tiemann reaction, reaction with zinc dust, oxidation; Commercially important alcohols (methanol,ethanol); Ethers-Methods of preparation: By dehydration of alcohols, Williamson synthesis- Physical properties-Chemical reactions: Cleavage of C-O bond and electrophilic substitution of aromatic ethers(anisole).</span></p><p><span style="font-size: large;">Aldehydes and Ketones:Nomenclature and structure of carbonyl group; Preparation of aldehydes and ketones-(1) by oxidation of alcohols (2) by dehydrogenation of alcohols (3) from hydrocarbons -Preparation of aldehydes (1) from acyl chlorides (2) from nitriles and esters(3) from hydrocarbons-Preparation of ketones(1) from acyl chlorides (2)from nitriles (3)from benzene or substituted benzenes; Physical properties of aldehydes and ketones; Chemical reactions of aldehydes and ketones-nucleophilic addition, reduction, oxidation, reactions due toα-</span></p><p><span style="font-size: large;">Hydrogen and other reactions (Cannizzaro reaction,electrophilic substitution reaction); Uses of aldehydes and ketones.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">Carboxylic acids: Nomenclature and structure of carboxylgroup; Methods of preparation of carboxylic acids (1)from primary alcohols and aldehydes (2) from alkylbenzenes(3)from nitriles and amides (4)from Grignard reagents (5) from acyl halides and anhydrides (6) from esters; Physical properties; Chemical reactions: (i) Reactions involving cleavage of O-H bond-acidity, reactions with metals and alkalies (ii) Reactions involving cleavage of C-OH bond- formation of anhydride, reactions with PCl5, PCl3, SOCl2, esterification and reaction with ammonia (iii) Reactions involving- COOH group-reduction, decarboxylation (iv) Substitution reactions in the hydrocarbon part - halogenation and ring substitution; Uses ofcarboxylicacids.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">13.<span style="white-space: pre;"> </span>ORGANIC COMPOUNDS CONTAINING NITROGEN:</span></p><p><span style="font-size: large;">Amines: Structure of amines; Classification; Nomenclature; Preparation of amines: reduction of nitro compounds, ammonolysis of alkyl halides, reduction of nitriles, reduction of amides, Gabriel phthalimide synthesis and Hoffmann bromamide degradation reaction; Physical properties; Chemical reactions: basic character of amines, alkylation, acylation, carbyl amine reaction, reaction with nitrous acid, reaction with aryl sulphonyl chloride, electrophilic substitution of aromatic amines (aniline)- bromination, nitration and sulphonation.</span></p><p><span style="font-size: large;">Diazonium Salts:Methods of preparation of diazonium salts (by diazotization) Physical properties; Chemical reactions: Reactionsinvolving displacement of Nitrogen; Sandmeyer reaction, Gatterman reaction, replacement by i) iodiode and fluoride ions ii) hydrogen, hydroxyl and Nitro groups; reactions involving retention of diazo group; coupling reactions; Importance of diazonium salts in synthesis of aromatic compounds.</span></p><p><span style="font-size: large;">Cyanides and Isocyanides:</span></p><p><span style="font-size: large;">Structure and nomenclature of cyanides and isocyanides; Preparation, physical properties and chemical reactions of cyanides and isocyanide</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">DELETIONS FROM CHEMISTRY 2nd YEAR INTERMEDIATE SYLLABUS:</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>SOLID STATE: (1.11) Electrical properties. (1.12) Magnetic properties</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>SOLUTIONS: (2.7) Abnormal molar masses</span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>ELECTROCHEMISTRY AND CHEMICAL KINETICS: Electrochemistry: (3.6) Batteries, (3.7) Fuel cells, (3.8) Corrosion Chemical Kinetics: (3.14) Collision theory of chemical reaction rates.</span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>SURFACE CHEMISTRY: (4.2) Catalysis, (4.5) Emulsions</span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>GENERAL PRINCIPLES OF METALLURGY: Entire Chapter Deleted.</span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>p-BLOCK ELEMENTS:</span></p><p><span style="font-size: large;">Group-15 Elements:(6.4) Oxides of Nitrogen- structures only. (6.6) Phosphorus allotropic forms. (6.7) Preparation & Properties of Phosphene. (6.8) Preparation & Properties of and (6.9) Phosphorus Halides & Oxo-acids (elementary idea only)</span></p><p><span style="font-size: large;">Group-16 Elements: (6.17) Sulphuric acid – Industrial process of manufacture</span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>d AND f BLOCK ELEMENTS & COORDINATIONCOMPOUNDS:(7.4) Some important Compounds of Transition elements (Preparation & Properties of KMnO4 and K2Cr2O7) (7.5) Chemical reactivity of Lanthanoids (7.6) Actinoids – Electronic configuration, Oxidation states and Comparison with Lanthanoids (7.11) Isomerism in Co-ordination Compounds (7.15) Importance of Co-ordination Compounds</span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>POLYMERS: Entire Chapter Deleted.</span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>BIOMOLECULES: (9.1) –(i) Sucrose, lactose, maltose importance Polysaccharides (starch, carbohydrates) importance (9.3) Enzymes (9.6) Harmones</span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>CHEMISTRY IN EVERYDAY LIFE: Entire Chapter Deleted.</span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>HALOALKANES AND HALOARENES: (11.6) Poly Halogen Compounds.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>ORGANIC COMPOUNDS CONTAINING C, H AND O (ALCOHOLS, PHENOLS, ETHERS, ALDEHYDES, KETONES</span></p><p><span style="font-size: large;">AND CARBOXYLIC ACIDS):(12.7) Some Commercially important alcohols</span></p><p><span style="font-size: large;">13.<span style="white-space: pre;"> </span>ORGANIC COMPOUNDS CONTAINING NITROGEN:Entire Chapter Deleted.</span></p><div><br /></div>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-7454971202855453032021-06-25T07:51:00.009-07:002021-07-06T08:25:58.806-07:00Andhra pradesh high court jobs notification 2021 <h1 style="text-align: left;">Andhra pradesh high court jobs notification 2021 court masters and personal personal secretaries to the judges and registrars</h1><p><span style="font-size: x-large;"><span face="Gautami, sans-serif">ఆంధ్ర ప్రదేశ్ హై కోర్టు లో కోర్టు మాస్టర్స్ మరియు
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</span><span style="mso-spacerun: yes;"> </span></span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;">Bc <span lang="TE">–</span>b <span lang="TE"><span style="mso-spacerun: yes;"> </span>02(1 </span>women
<span lang="TE">)</span><o:p></o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;"><span style="mso-spacerun: yes;"> </span></span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;">Bc <span lang="TE">–</span>c <span lang="TE"><span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>1 </span><o:p></o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;"><span style="mso-spacerun: yes;"> </span></span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;">Bc <span lang="TE">–</span>d <span lang="TE"><span style="mso-spacerun: yes;"> </span>01 (1 </span>women
<span lang="TE">)</span><o:p></o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;"><span style="mso-spacerun: yes;"> </span></span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;">Bc <span lang="TE">–</span>e<span style="mso-spacerun: yes;"> </span><span lang="TE"><span style="mso-spacerun: yes;"> </span>01 (1 </span>women
<span lang="TE">)</span><o:p></o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;"><span style="mso-spacerun: yes;"> </span></span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;">Sc <span style="mso-spacerun: yes;"> </span><span lang="TE"><span style="mso-spacerun: yes;"> </span>04 (2<span style="mso-spacerun: yes;"> </span></span>women <span lang="TE">)</span><o:p></o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;"><span style="mso-spacerun: yes;"> </span></span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;">St <span style="mso-spacerun: yes;"> </span><span lang="TE"><span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>02(1 </span>women <span lang="TE">)</span><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: x-large;"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;">ఈ ఉద్యోగాలకు ఎంపిక అయిన వారికి వేతనం 37100/- వరకు
చెల్లిస్తారు </span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: x-large;"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;">ఈ ఉద్యోగాలకు ఎంపిక అయిన వారు 2 సంవత్సరాల వరకు
కొనసాగుతారు<span style="mso-spacerun: yes;"> </span>వారియొక్క పర్ఫార్మన్స్
బాగుంటే ఇంకొక సంవత్సరం కొనసాగిస్తారు ఒక నెల ముందు నోటీస్ ఇచ్చి ఏ సమయం లో నయిన
ఉద్యోగం నుంచి తీసివేసే అధికారం కోర్టుకి కలదు ఉద్యోగి కూడా కోర్టుకి ఒక నెల ముందు
నోటీస్ ఇచ్చి ఏ సమయం లో నయిన<span style="mso-spacerun: yes;"> </span>ఉద్యోగ
భాద్యత నుంచి తప్పుకోవచ్చు </span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: x-large;"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;">ఇద్దరు వ్యక్తుల విట్నెస్ తో 110 రూపాయల స్టాంప్ పేపర్ మీద
తమ అంగీకార తెలపవలెను</span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p></o:p></span></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" style="font-size: x-large; mso-bidi-language: TE;">Oc <span lang="TE"><span style="mso-spacerun: yes;"> </span>మరియు </span>bc <span lang="TE">క్యా టగిరి <span style="mso-spacerun: yes;"> </span>ఆబ్యర్దులకు 750
రూపాయలు </span>sc <span lang="TE">మరియు </span>st <span lang="TE"><span style="mso-spacerun: yes;"> </span>ఆబ్యర్దులకు 350 రూపాయలు పీజు గా
చెల్లించవలయును </span><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: x-large;"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;">పీజు ను డిమాండ్ డ్రాఫ్ట్ రూపం లో చెల్లించవలెను<span style="mso-spacerun: yes;"> </span></span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: x-large;"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;">మూడు పాస్పోర్ట్ సైజ్ పోటో గ్రాఫ్ లతో అప్లికేషన్ సబ్మిట్
చేయవలెను </span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;">gazetted <span lang="TE">ఆఫీసర్ సంతకం తో </span><o:p></o:p></span></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" style="font-size: x-large; mso-bidi-language: TE;">Enclouser <span lang="TE"><span style="mso-spacerun: yes;"> </span>లేని
అప్లికేషన్ రిజెక్ట్ చేయబడును </span><o:p></o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" style="font-size: x-large; mso-bidi-language: TE;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;"><span style="mso-spacerun: yes;"> </span></span><span face=""Gautami","sans-serif"" style="mso-bidi-language: TE;"><o:p></o:p></span></p>
<p class="MsoNormal"><span face=""Gautami","sans-serif"" lang="TE" style="mso-bidi-language: TE;"><span style="mso-spacerun: yes;"> </span></span><o:p></o:p></p>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-90698378555469333922021-06-24T06:47:00.001-07:002021-06-28T02:52:03.386-07:00Automatic storage classes arrays in programming language number system <h1 style="text-align: left;"><span style="font-size: large;"> Automatic storage classes arrays in programming language number system eapcet engineering stream material</span></h1><h2 style="text-align: left;"><span style="font-size: large;"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;">AUTOMATIC STORAGE CLASSES:<span style="mso-spacerun: yes;"> </span></span></b></span></h2>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Module scope/code blocked scope<o:p></o:p></span></p>
<head>
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<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Storage on system memory<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Auto keyword<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Validity upto invoking the block+++<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpLast"><span style="font-size: large; line-height: 115%;">Default storage data unpredictable<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syntax:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Auto
<data type><identifier> =<value>;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Auto int x;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All the
elements are individual<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">There is no
dependent elements<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Elements are
identified by the indexes<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To find the
elements in a matrix format by useingthe index point of row and column<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Array is
called as related elements but same datatype , homogeneous data elements<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">DYNAMIC
MEMORY ALLOCATION<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">MALLOC
()<span style="mso-spacerun: yes;"> </span>REALLOC()<span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>CALLOC()<span style="mso-spacerun: yes;"> </span>FREE()<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">MALLOC()<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is used
to allocate single block of memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syntax :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><ptr
location>=<type declaration?malloc<pointer or buffer size><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Dynamic
memory allocation methods available<span style="mso-spacerun: yes;">
</span>stdlib.h<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ptr=<int*>malloc(size
of(int));<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">CALLOC<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To allocate
multiple blocks of memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syntax :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><ptr
location>= <type conversion> calloc(n,buffer size);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ptr=<int
*> calloc(3,size of(int)))<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">POINTERS:<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pointers are
used to identify the address of another variable<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">This
variable is stored in memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pointers
also one type of variable / identifier<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pointers are
identify the asterisk operator<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Address is
also stored on some other address in the memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pointer
terms<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large;"><span style="line-height: 115%;">*---------</span><span style="font-family: Wingdings; line-height: 115%; mso-ascii-font-family: Calibri; mso-ascii-theme-font: minor-latin; mso-char-type: symbol; mso-hansi-font-family: Calibri; mso-hansi-theme-font: minor-latin; mso-symbol-font-family: Wingdings;"><span style="mso-char-type: symbol; mso-symbol-font-family: Wingdings;">à</span></span><span style="line-height: 115%;"> pointer<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">&…………..>
address<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">*(*)…………>actual
value (pointer of pointer)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">*(&)…………..>
actual value (address of pointer)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
declare pointers<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pointers are
declared by the primitive data types<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Primitive
data types followed by the initial name<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pointer is a
prefix of the variable<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><data
type > *<literal name><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int * p;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int x,*p;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">X=5<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">P=&x;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pr(“%d”,*p);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">ARRAYS IN PROGRAMMING LANGUAGE :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Collection
of related data items or collection of same data items stored in a common
memory (shared memory)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Homogeneous
data items<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Arrays are
used to implement sequential memory allocation<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Key terms :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Default
index starts with zero<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Array
indexes must be integer<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Group of
indexes called as indices<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">L bound of
array zero<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Bootimg
index zero<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">U bound
(n-1) some times it is called asterminated index<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Last index
(n-1)<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Components of an array<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Data type
array name size<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Datatype
……………… user defined<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>Predefined <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syntax :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Declaration
of an array<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><data
type > <array name[ size];<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int x [5]<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
initialize the array :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">We can
assign<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Based on
assignment operator<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Association
based on right to left<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><array
name> [index] =<value><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex : x(0) =
10;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Array name
index =0 value 10<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Types of
array initialization:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">First form
notation<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Second form
notation<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">R to l<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">By using
index<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex :<span style="mso-spacerun: yes;"> </span>int x[5]<span style="mso-spacerun: yes;">
</span>first form<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">X[0]=10<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Second form
:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Right to
left<span style="mso-spacerun: yes;"> </span>*without proper space ‘<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Without
index<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int x[5]
={10,20,30,40};<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Number are
elements which are mentioned in the curly brace in size of array <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
access the array elements :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">By using
loops<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int x[]
=(10,20,30,40,50);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int I;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">For(i=0
i<x.length; i++}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pf(“%d”,x[i]);<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">While loop <o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a
entry controlled loop <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Note: cursor
checks for the condition before execteing the statements<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syntax :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int ;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">While cond<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">-----<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">While is
called as entry controlled<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
following loop is called as entry controlled …………while<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Do-while<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Exit
controlled loop<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Do<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">-----<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">++/--;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">While(cond);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int i=0;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Do<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Printf(‘%d”,i);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">I++<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}while(i<5);<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Structure<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Declare a data
structure format in multiple data types declaration is based on keyword struct
followed by the structure name<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct
<structure name ><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">We can
access numbers from the structure by using the keyword or user defined tags<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct
<sname><tag name><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">In c++ java
it is called as object<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Structure
test t :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To create
relationship between structure members and tag by using period operator (.)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><tag name
>.<structure member><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex: t.htno;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">We can
assign the values to the structure members by using assignment operator(=)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syntax :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><tag name
>.<member name >=<value><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">t.acc number
=”12345”<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">how to
declare structure <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">struct
<structure name><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">----------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">-------------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><data
members of the structure><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct
employee<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int emp id <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Char ename
[15]<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">};<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">How to declare structure with in a
structure :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Nested
structures <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To declare1
structure tag in another is called as nested structures<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct tesgt
1{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int account
number <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct test
2 {<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct test
1 T1;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int mobile
number <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">};<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct test
2 T2;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">N nested
structure declaration is also possible in nested structures<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
declare arrays to the structures <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">What is the
main use of<span style="mso-spacerun: yes;"> </span>arrays with structures<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To store
multiple records in structure --- arrays<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
create tables in c --- structures<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct
customer {<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int cid<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Char cname
[20]<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int number ;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">};<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct with
arrayare used to create relationship structures<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct
<sname><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">--------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">----------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct
<s.name>< tag name> [size]<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It can
support n arrays<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct
customer {<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int cid;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Char cname
[20]<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">};<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Struct
customer c[5];<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Note :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
access multiple records from array with structures<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">By using
loops<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">C[0].cifd=123<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">UNION<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Union are
used to find the random memory location<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Unions are
declared by using the “union” followed by union name<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Wec can
access the members from the union by using tag<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To create a
relationship between union tag and the union members by using period operator
(.)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syn:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Union<union
name><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">…………<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">…………<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">};<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Union test {<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int number ;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">};<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To access
the number from the union<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Union test
t{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">t.number
=12345<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">UNION ARRAYS<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is not
possible to implement nested union<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Reason :
randomization allocation<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Nested
unions are not possible in<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">UNION TEST {<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">INT number<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">};<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Uniton tesy
t[5];<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To access
union array loops<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If the
structure ofunion contains n indexes loops are must be in the nesyed format<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large;"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;">Registers</span></b><span style="line-height: 115%;"> :<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Module/code
block scope<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Register<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Data storage
on processor register<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Invoking<span style="mso-spacerun: yes;"> </span>default value unpredictable <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syntax :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Register
<data type><name>=<value><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Register int
r;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Static :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Module or
functional or code block scope<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Static
keyword default size zero<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">System
memory storage allocation<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Syntax:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Static
<data type> <identifier name > =<value><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Static int
s;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">External :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Global
scope,unpredictable,extern,system memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Extern<data
type><identifier>=<value><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Operator
over loading:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To solve the
complex problems<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Data
authentication data secrecy complex problems<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><data
type> operator<symbol><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">……<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">…..<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void
operator +()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">…….<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">……..<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Count 10+20;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which
symbols are not allowed operator over loading<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">(,),{,},[,],,,:,;,-<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All
arithmetic relational bitwise conditional operators allowed<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Note :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To invoke
the operations in operator overloading by using the prefix of the object<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Class test<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Algorithms
in programming language :<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Step by step
description allowed in algorithms step by step description to solve real world
task to identify the solving descriptions of the real world data<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a
procedure used to solve the problems in a step by step manner<o:p></o:p></span></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">COMMANDS IN THE ALGORITHM<o:p></o:p></span></b></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">COMMAND
PURPOSE<o:p></o:p></span></b></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">START
-------------- To begin the algorithm<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Begin
…………………to activate the algorithm<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Process……………..
to execute the algorithm<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Compute…………..to
execute the statement<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cond………………….to
find the conditions<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Lt………………….lessthan<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ltq………………lessthan
or equalsto<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Gt……………….greater
than<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Gtq……………greater
than or equals to<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Eq/eql………………….comparison<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Comp……………comparison<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Stop……………to
terminate the algorithm<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">End……………to
terminate the algorithm<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;"> </span></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">NUMBER SYSTEM<o:p></o:p></span></b></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">BINARY
NUMBER SYSTEM<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">DECIMAL
NUMBER SYSTEM<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">OCTAL NUMBER
SYSTEM<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">HEXA DECIMAL
NUMBER SYSTEM<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Binary
number system :<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is used
to identify the electronic storage data in binary number system base value 2
range 0,1<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Decimal
number system :<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Find human
readable numbers<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Base value
10 range 0------9<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Octal number
system :<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To display
the data on digital circuit boards<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Symbol base
value range<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Hexa decimal
number system :<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Mainly used
for identifying the memory address<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Address
based on alpha numbers<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">16 base
valuerange 0---------9 A------------F<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Bcd
conversion :<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">0+0 =0 0+1 =1
1+0 =1 1+1=1 <o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">0 is result
1 is carryforward<o:p></o:p></span></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">Data transfer :<o:p></o:p></span></b></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void display
(5,6)<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void
display(int,int)<o:p></o:p></span></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">Types of functions<o:p></o:p></span></b></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">Predefined functions <o:p></o:p></span></b></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">A function
which are defined in programme or platform header files are preprocessors or
packages or apis are called as pre defined functions<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">These are
called as system defined functions inbuilt functions existing functions<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Header file
registered functions <o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Api---
application programming interface<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><sgtdio.h>
<iostream.h> java.io.*<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">User defined
:<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">These
functions are declared defined by the user according to his programme
requirements<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">No—no<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">No—with<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">With—no<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">With---with<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large;"><b><span style="line-height: 115%;">Components of the method</span></b><span style="line-height: 115%;">(parts of the method)<o:p></o:p></span></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Data type
,method type, parameters ,body<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
following is a mandatory component for the user defined function data type
return type<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which part
of a method is option parameters<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Function
----- to create code blocks<o:p></o:p></span></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">Default arguments or default parameters<o:p></o:p></span></b></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To ignore
the user inputs<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void
display(int x,int y=20)<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">What are the
types of functions in pure object oriented programming<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Bascic
functions<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Mutator
functions<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Accessor
functions<o:p></o:p></span></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">Mutator functions<o:p></o:p></span></b></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is also
called as setters it is also used to assign the values to literals<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is used
to invoke instant variables<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is used
to implement the keyword<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Operator is
set assignment operator it is used to return the values<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">A function
contains more than one function a class contatins more than 1 class<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Function
names are same and return type is also same but number of parameters are
different ------over loading<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Importance :
buffer reusability mechanism<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;"> Class test <o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void display
(int x )<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void display
(int x int y)<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void display
(int x int y int z);<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Method over
loading is a polymorphism<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">
</span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Polymorphism
is a memory reusability<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void
operator +()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">……………..<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">……………<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void main ()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Test T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">+T;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Algorithms
in programming language :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Step by step
description allowed in algorithms step by step description to solve real world
task to identify the solving descriptions of the real world data<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a
procedure used to solve the problems in a step by step manner<o:p></o:p></span></p><p class="MsoNormal"><span style="line-height: 115%;"></span></p><p class="MsoNormal"><span style="line-height: 115%;"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;"><span style="font-size: large;">COMMANDS IN THE ALGORITHM<o:p></o:p></span></span></b></span></p><span style="line-height: 115%;">
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;"><span style="font-size: large;">COMMAND<span style="mso-spacerun: yes;">
</span>PURPOSE<o:p></o:p></span></span></b></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">START
-------------- To begin the algorithm<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Begin
…………………to activate the algorithm<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Process……………..
to execute the algorithm<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Compute…………..to
execute the statement<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Cond………………….to
find the conditions<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Lt………………….lessthan<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Ltq………………lessthan
or equalsto<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Gt……………….greater
than<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Gtq……………greater
than or equals to<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Eq/eql………………….comparison<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Comp……………comparison<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Stop……………to
terminate the algorithm<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">End……………to
terminate the algorithm<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><o:p><span style="font-size: large;"> </span></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;"><span style="font-size: large;">NUMBER SYSTEM<o:p></o:p></span></span></b></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">BINARY
NUMBER SYSTEM<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">DECIMAL
NUMBER SYSTEM<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">OCTAL NUMBER
SYSTEM<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">HEXA DECIMAL
NUMBER SYSTEM<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Binary
number system :<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">It is used
to identify the electronic storage data in binary number system base value 2
range 0,1<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Decimal
number system :<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Find human
readable numbers<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Base value
10 range 0------9<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Octal number
system :<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">To display
the data on digital circuit boards<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Symbol base
value range<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Hexa decimal
number system :<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Mainly used
for identifying the memory address<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Address
based on alpha numbers<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">16 base
valuerange 0---------9 A------------F<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Bcd
conversion :<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">0+0 =0<span style="mso-spacerun: yes;"> </span>0+1 =1<span style="mso-spacerun: yes;">
</span>1+0 =1 1+1=1 <o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">0 is result
1 is carryforward<o:p></o:p></span></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;"><span style="font-size: large;">Data transfer :<o:p></o:p></span></span></b></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Void display
(5,6)<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Void
display(int,int)<o:p></o:p></span></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;"><span style="font-size: large;">Types of functions<o:p></o:p></span></span></b></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;"><span style="font-size: large;">Predefined functions <o:p></o:p></span></span></b></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">A function
which are defined in programme or platform header files are preprocessors or
packages or apis are called as pre defined functions<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">These are
called as system defined functions inbuilt functions existing functions<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Header file
registered functions <o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Api---
application programming interface<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;"><sgtdio.h>
<iostream.h> java.io.*<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">User defined
:<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">These
functions are declared defined by the user according to his programme
requirements<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">No—no<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">No—with<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">With—no<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">With---with<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: large;"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;">Components of the method</span></b><span style="line-height: 115%;">(parts of the method)<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Data type
,method type, parameters ,body<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Which of the
following is a mandatory component for the user defined function data type
return type<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Which part
of a method is option parameters<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Function
----- to create code blocks<o:p></o:p></span></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;"><span style="font-size: large;">Default arguments<span style="mso-spacerun: yes;"> </span>or default parameters<o:p></o:p></span></span></b></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">To ignore
the user inputs<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Void
display(int x,int y=20)<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">What are the
types of functions in pure object oriented programming<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Bascic
functions<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Mutator
functions<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Accessor
functions<o:p></o:p></span></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;"><span style="font-size: large;">Mutator functions<o:p></o:p></span></span></b></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">It is also
called as setters it is also used to assign the values to literals<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">It is used
to invoke instant variables<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">It is used
to implement the keyword<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Operator is
set assignment operator it is used to return the values<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">A function
contains more than one function a class contatins more than 1 class<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Function
names are same and return type is also same but number of parameters are
different ------over loading<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Importance :
buffer reusability mechanism<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;"><span style="mso-spacerun: yes;"> </span>Class test <o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">{<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Void display
(int x )<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">{<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">}<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Void display
(int x int y)<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">}<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Void display
(int x int y int z);<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">}<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Method over
loading is<span style="mso-spacerun: yes;"> </span>a polymorphism<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="line-height: 115%;"><span style="font-size: large;">Polymorphism
is a memory reusability<o:p></o:p></span></span></p><br /></span><p></p>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-32998090995876479152021-06-22T05:38:00.017-07:002021-06-25T19:48:13.881-07:00Cache memory basics of raid decrement operator relational operator logical operators <h1 style="text-align: left;"><span style="font-size: large;"> Cache memory basics of raid decrement operator relational operator logical operators flow control statements break and continue loop control statements eapcet material</span></h1><h2 style="text-align: left;"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">CACHE MEMORY : </span></b></h2>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is an
interface memory in between processor and the main memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Always cache
memory state is zero<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It holds the
data when the processor and ram is buzy<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">RAM is
volatile<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Characteristics
of memory:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Location ,
capacity, unit of transfer, Access method ,<span style="mso-spacerun: yes;">
</span>performance, physical type ,physical characteristic ,organization<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Location :
cup storage (memory unit)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>Internal storage (main
memory)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>Processor registers<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>External storage(HD)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Capacity :
number of words are<span style="mso-spacerun: yes;"> </span>transmitted per
second either in data bus or <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>system bus <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>word (code word or data word)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">unit of
transfer :<span style="mso-spacerun: yes;"> </span>it is used to identify the
destination point of memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Access
methods :<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpFirst" style="mso-list: l0 level1 lfo1; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">1.<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">Serial access<o:p></o:p></span></span></p>
<p class="MsoListParagraphCxSpMiddle" style="mso-list: l0 level1 lfo1; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">2.<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">Random<o:p></o:p></span></span></p>
<p class="MsoListParagraphCxSpLast" style="mso-list: l0 level1 lfo1; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">3.<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">Dynamic<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Performance
: number of cycles per second (to identify)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Physical
type : to identify the memory(physical location of the memory)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Physical
characteristic : volatile or non volatile<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Organization
----- location same<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Locality of
reference :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">A data which
is available on the main memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">The main
memory address for the file is called as locality reference<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Is is a
temporary address<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ram memory
address<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Loops and
sub routines related to locality reference<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Nearby
memory<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">BASICS OF RAID :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Redundant
array of independent disks<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">(Inexpensive
disks)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is used
to implement mirror copy’s identical to the permanent storage <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It works
with placing data on multiple disks<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Raid works
with raid controller<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It can be
used as level of obstruction between the os and the physical disks<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">MODES OF I/O DATA TRANSFER <o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Transferring
of information between internal storage and external input and out put devices<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Programmed
input and out put<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Interrupted
input and out put<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Direct
memory access<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Programmed input and out put :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cpu requests
I/O<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">IO Module perform
operations<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is used
to implement sets start bit for the resources<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Note:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">There are
two states for every device<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">0 and 1
0-off<span style="mso-spacerun: yes;"> </span>1<span style="mso-spacerun: yes;"> </span>ready<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cpu checks
start bits periodically for all devices<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Each device
contains 1 unique identifier number<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cpu commands
contains unique identifier<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
following operation of I/O data transfer checks for the start bit of the
devices <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Programmed
I/o<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which
operation is used to identify the unique identifier number for cpu commands <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Programmed
I/O<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">INTERRUPTED DRIVEN I/O :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cpu issues
read command to the devices<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It gets data
from the peripherals<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cpu requests
for data<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">The module
uses identify the interrupted<span style="mso-spacerun: yes;">
</span>instructions/devices<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which
operation is used to requests data and gets the data from the peripherals ---
interrupted driven I/O<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large;"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;">DIRECT MEMORY ACCESS</span></b><span style="line-height: 115%;"> :<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Transfer
rate is limited<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cpu is tied
up for manageing data transfers<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Dma module
must use the bus only(system bus)<span style="mso-spacerun: yes;"> </span>when the
processor(cpu) does not need it<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">DMA OPERATION :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Read and
write operations<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">RECOGNIZE AND ALLOCATE DEVICE ADDRESS
:<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It sets the
amount of data to be transferred<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pcb control
receives signal/request from the client/user or some other device who will
allocate address --- dma<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">General key
points :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cpu carry’s
the signals from dma/receivers<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Dma
controller sends system call to cpu<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">In what type
of situations dma will sends system call to processor?<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">When dma
receives instruction from other client/user<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Main functionality
of dma controller ----it acts as an interface between main memory and the
processor<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Key points :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All IO
operations are connected to IO bus<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">One chip set
is required to transfer the data from all IO devices to the mother board<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">IOP also
called as scsi<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">SCSI : small
computer system interface<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">DECREMENT OPERATOR :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>To decrease the value by 1<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Main ()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int i=5;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pf(“id”,i--)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Main()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">(<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int i=5<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">--i<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">=4<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">RELATIONAL OPERATORS:<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>To implement conditions <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex :
>,<,>=,<=,==,!=<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex :
10>20<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">The written
value in the relational operator either true or false <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">What is
association of data in comparison operator?<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Left to
right<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
following is true about the relational operators?<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is an
operator used to implement conditions<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">LOGICAL OPERATOR :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Logical
operators are used to implement multiple conditions in a single expression<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex : logical
and (&&)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>Logical or <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>Logical not(!)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>Ip1<span style="mso-spacerun: yes;"> </span>ip2<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>T<span style="mso-spacerun: yes;"> </span>T<span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>T<span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span>F<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>F<span style="mso-spacerun: yes;"> </span>T<span style="mso-spacerun: yes;"> </span>F<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>F<span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>F<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">LOGICAL AND <o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All i/p are
true then o/p true<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If the input
1 is negation of negation of true N(N(T)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">N(n(t) and
i/p 2 is n(t) then what is the o/p of logical and<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">OR GATE :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Logical OR<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Any one is
true or all are true<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>I1<span style="mso-spacerun: yes;"> </span>i2<span style="mso-spacerun: yes;"> </span>o/p<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>T<span style="mso-spacerun: yes;"> </span>T<span style="mso-spacerun: yes;"> </span>T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>T<span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span>T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span>T<span style="mso-spacerun: yes;"> </span>F<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;">
</span>F<span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If the i/p 1
is not a true and o/p is false then <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">What is the
o/pof or gate false <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">OR gate :
Logical OR <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Any one is
true or all are true <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>I1<span style="mso-spacerun: yes;"> </span>I2<span style="mso-spacerun: yes;"> </span>O/P<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>T<span style="mso-spacerun: yes;"> </span>T<span style="mso-spacerun: yes;"> </span>T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>T<span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span>T<span style="mso-spacerun: yes;"> </span>T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span>F<span style="mso-spacerun: yes;"> </span>T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If the i/p 1
is not a true and o/p is false then<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">What is the
o/p of or gate false<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Note :<span style="mso-spacerun: yes;"> </span>T---F<span style="mso-spacerun: yes;">
</span>F---T<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Conditional
operators :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To implement
conditionals statements<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex: int x =
(10>20)?<span style="mso-spacerun: yes;"> </span>10 : 20<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">The o/p of
conditional statement is 20<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;"></span></p><p class="MsoNormal"><span style="line-height: 115%;"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">FLOW CONTROL STATEMENTS :<o:p></o:p></span></b></span></p><span style="line-height: 115%;"><span style="font-size: large;">
</span><p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">IF<span style="mso-spacerun: yes;"> </span>IF ELSE IF<span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>SWITCH<o:p></o:p></span></b></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">IF<span style="mso-spacerun: yes;">
</span>ELSE<span style="mso-spacerun: yes;">
</span>NESTED IF<o:p></o:p></span></b></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">IF :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Single
condition code block <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Only one
state output<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">(cond) <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">--------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Single
condition code block identified in ----- if<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">HINT :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Identifier
is always greater than zero<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If(x<0)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Printf(“hello”);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">IF ELSE :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a
single condition block based on<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">T OR F OR
else output<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If(cond)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">---------------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">-----------------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Else<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">---------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex : if
(10>20)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>Printf(“digital assistant”);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>Else<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>Printf(“ap”)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Else block
is called as false statement<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
following is the false block in if else -------------else<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">What are the
condition states of if else ? a b both either a or b<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">When the
false block is executed<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Condition is
not true<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Condition is
false<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">IF ELSE IF <o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Some times
it is called as else if ladder<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is based
on multiple conditions & multiple true statements<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Multiple
false statements<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Last else is
called as false<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If cond(1)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">True stmt 2<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Else cond 2<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">True stme 2<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Else if cond
n<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">NESTED IF :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Arrange the
if conditions in AND gate<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All the
conditions are based on only one block<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If (cond 1)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If (cond 2)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If(cond n)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">True (stmt)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">There is no
separate else block<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Multiple
condition blocks are based on single statement or single o/p<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Is called as
nested if<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">In nested if
last block is called as true statement or block out put<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">SWITCH<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is
identified by the switch block <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Switch()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It can be
devided into individual blocks named as cases<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Case 1<span style="mso-spacerun: yes;"> </span>case2 ….. casen<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">The syntax
is related to if else if<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Last else is
called as default<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Each case
block terminated by the break statement<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Switch(expr)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Case (i)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Break<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Case (i)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">------<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Break<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Case n<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">………<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Break<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Default<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">…….<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Break
statement is used to terminate the case blocks<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Swith syntax
is related to if else if<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">BREAK AND CONTINUE:<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Terminate
from code block<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
terminate the cursor from the method<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
terminate cursor from the loop <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ans : break<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To terminate
the cursor from the conditional code block break<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Note : block
statement is used on condition <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Int x = 2<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void
display()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">If(x==3)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Break ;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Printf(“hello”);<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">CONTINUE :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>To move the cursor from its continuous
statement to previous<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Note :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">No
statements are executed after continue<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Void display
()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Continue <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Printf(“test”);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">o/p : emply
or blank<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">GOTO<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Abnormal
conditional implementation<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is used to
implement unconditional code block based on “label”<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Programme
label is called as block identifier<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Label is
identified by the (:) operator<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Main()<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">{<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Test:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Printf(“Guntur”);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Go to test ;<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">}<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to
implement abnormal condition loop --------------goto<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How to implement
unconditional code block -------------------goto<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Label is
called as block identifier<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Goto is
based in label<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">LOOP CONTROL STATEMENTS<o:p></o:p></span></b></p><p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">LOOP CONTROL STATEMENTS<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Toexecute
the statements more than once <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Continuous
execution of statements based on specified condition<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpFirst" style="mso-list: l0 level1 lfo1; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">1.<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">Terminated loop---- inner loop ,
outer loop<o:p></o:p></span></span></p>
<p class="MsoListParagraphCxSpMiddle" style="mso-list: l0 level1 lfo1; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">2.<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">Unterminated loop –
goto,break,continue<o:p></o:p></span></span></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">FOR<span style="mso-spacerun: yes;"> </span>WHILE<span style="mso-spacerun: yes;"> </span>CONTINUE<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">FOR :<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">It is a multi statement loop<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">It is also called as statement loop code block<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">PARTS OF FOR LOOP<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Initialization<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Test condition<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Increment or decrement<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">INITIALIZATION<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">To identify the booting index of the loop or initial index or starting
index of the loop<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">L bond of the loop initialization<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Initialization default value zero<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">TEST CONDITION<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">It is used to find the last index of loop<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">To find terminated index, to find last inded<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">To increase value by 1 or decrease value by 1<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">REALLOC:<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">To resize the declare(already allocated buffer)<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Syntax :<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;"><ptr location> =<type declaration>realloc(buffer size);<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Already declare buffer<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Ptr =<int *>realloc(size of(int));<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">The ptr already declared(existing ) buffer<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">FREE<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">To release the already allocated memory<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Free (<ptr name>);<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">Free(ptr);<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">C TOKENS<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">IDENTIFIERS<span style="mso-spacerun: yes;">
</span>ALPHABETS<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">KEYWORDS<span style="mso-spacerun: yes;">
</span>NUMBERS<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">CODE BLOCKS<span style="mso-spacerun: yes;">
</span>SPECIAL OPERATORS<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpMiddle"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">STATIC CLASSES<o:p></o:p></span></b></p>
<p class="MsoListParagraphCxSpMiddle"><span style="font-size: large; line-height: 115%;">AUTO<span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>STATIC<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpLast"><span style="font-size: large; line-height: 115%;">EXTERN<span style="mso-spacerun: yes;">
</span>REGISTER<span style="mso-spacerun: yes;"> </span><o:p></o:p></span></p><br /></span><p></p>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-528907416666437482021-06-21T05:35:00.003-07:002021-07-03T23:28:41.698-07:00latest percentages simple shortcut material<p><span style="font-size: large;"> </span></p><div class="post-body" id="post-6173897235194367728" style="margin: 0px; padding: 0px;"><div dir="ltr" style="margin: 0px; padding: 0px;" trbidi="on"><h1 style="margin: 0px; padding: 0px; text-align: left;"><span style="font-size: large;"> latest material on percentages </span></h1><div class="cleanuphtml-1" dir="ltr" style="margin: 0px; padding: 0px;" trbidi="on"><span style="font-size: large;"><br /></span></div><div class="cleanuphtml-1" dir="ltr" style="margin: 0px; padding: 0px;" trbidi="on"><h2 style="text-align: left;"><span style="font-size: large;">To convert fraction into percentage multiple the given fraction with 100%</span></h2><span style="font-size: large;">50% = 50/100 = 1/2<br />1/2 = 1/2(100%) = 50%<br />EX:<br />convert the folowing percentages into fraction<br />1) 60% = 60/100 = 3/5<br />2) 12.5 % = 12.5/100 = 5/40 = 1/8<br />3) 33 (1/3)% = 100/3 = 1/3<br />4) 16(2/3)% = 50/(3*100) = 1/6<br /><br style="margin: 0px; padding: 0px;" />EX:<br />convert the following fractions into percentage<br />1) (3/4)*100 = 75 %<br />2) (4/5) * 100 = 80%<br />3) (2/3) * 100 = 200/3 = 66(2/3)%<br />4) (1/5) *100 = 20%<br />5) (1/12)*100 = 25/3 % = 8 (1/3)%<br />NOTE:<br />50% = 1/2<br />25% = 1/4<br />12(1/2)% = 1/8<br />6(1/4)% = 1/16<br />66 (2/3)% = 2/3<br />33(1/3)% = 1/3<br />16(2/3) % = 1/6<br />8(1/3)% = 1/12<br />75% = 3/4<br />14 (2/7)% = 1/7<br />11(1/9)% = 1/9<br />9 (1/11)% = 1/11<br />NOTE:<br />1/1 = 100%<br />1/2 = 50%<br />1/3 = 75%<br />1/4 = 25%<br />1/5 = 20%<br />1/6 = 16 (2/3)%<br />1/7 = 14(2/7)%<br />1/8 = 12(1/2)%<br />1/4 = 11(1/4)%<br />1/10 = 10%<br />1/11 = 9(1/11)%<br />1/12 = 8(1/3)%<br />FORMULAE:<br />1 x%y = (x/100)y<br />(xy)/100<br />2 x is what percentage of y<br />what = (100%x)/y<br />is/of just remember<br />EG:<br />IN 250 FIND 30 % VALUE?<br />10% = 25<br />30 % = 75<br />EG:<br />IN 360 FIND 15%<br />10% = 36<br />5% = 18<br />15% = 54<br />EG:<br />IN 450 FIND 22 % VALUE?<br />10% = 45<br />20% = 90<br />2% = 9<br />......<br />99<br />IN 240 FIND 19%?<br />20% 48<br />-1% 2.4<br />........<br />45.6<br />EG:<br />30 % OF 120 = 36<br />EG:<br />IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys<br />total 5 parts<br />boys (3/5) * 100 = 60%<br />girls (2/5) *100 = 40%<br />METHOD 2<br />5 - 100<br />2 ?<br />5---100<br />3 ?<br />EG:<br />IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys<br />boys what percentage more that girls?<br />(1/2) * 100 = 50%<br />EG:<br />IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys<br />girls what percentage more than boys ?<br />(1/3)* 100 = 33(1/3)%<br />EG:<br />IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys<br />Boys is what percentage of girls?<br />(3/2)100 = 150%<br />EG:<br />IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys<br />girls is what percentage of Boys ?<br />(2/5)*100 = 200/3 = 66(2/3) %<br />MODEL :<br />EG:<br />A Salary is 20 % less than b salary then b salary is what % more than a salary?<br />4 : 5<br />(1/4) 100 = 25%<br />short cut formulae<br />(X/(100±X))*100%<br />MORE - PLUS<br />DECREASE OR LESS -- MINUS<br />COMPARE ABOVE PROBLEM<br />(20/(100-20))*100<br />(20/80)*100 = 25%<br />EG:<br />A rectangle length increased by 10 % by what percentage breadth has to be decrease sothat no change in its area?<br />(10/(100+10))*100<br />(10/110)*100<br />9(1/11)%<br />EG:<br />price of a article decreased by 30% by what percentage it sales has to be increase so that these is no effect in revenue?<br />(30/70)*100<br />300/7<br />42(6/7)%<br />EG:<br />price of a sugar increased by 20% by what percentage it consumption has to be decreased sothat there is no change<br />(20/120)*100%<br />16(2/3)%<br />MODEL:<br />EG:<br />Population of a town is 5000 in the first year it is increased by 10 % and then 2nd year it decreased by 20 % find the<br />find the population after 2 years and the overall percentage<br />population first year 10% increased so 110/100<br />population second year 20% decreased 80/100<br />5000 *(110/100) * (80/100)<br />550*8<br />4400<br />(600/5000)*100<br />12% decreased<br />METHOD 2:<br />+10% -20%<br />ONLY ON TWO PERCENTAGE CHANGES ONLY<br />((X+Y+(XY/100)) %<br />(10-20-200/100)%<br />-12% DECREASED<br />EG:<br />A rectangle length is decreased by 10% and bredth decreased by 10 %<br />find the effect on its area?<br />(-10-20+(200/100)%<br />-28% decrease<br />EG:<br />thrice of a article first increased by 10% and again increased by 20 % then decrease by 25 %?<br />100*(110/100)* (75/100)<br />99%<br />1 percentage decreased<br />MODEL 3:<br />EG:<br />population of a town first increased by 10 %and then decreased by 205 if the final population is 4400 initial population?<br />increased by 10% so 100/110<br />decreased by 20% so 100/80<br />4400*(100/110)*(100/80)<br />5000<br />EG:<br />A man spends 85% of his income per household items and out of the remaining 50% per transport if he finally saves 900 find his income?<br />900*(100/15)*(100/50)<br />12500<br />EG:<br />In a college 30% are arts graduates out of the remaining 40% are science graduates out of the remaining 50% are computer<br />graduates find total no of students?<br />-30% -40% -50%<br />210*(100/70)*(100/60)*(100/50)<br />EG:<br />The ratio between a ,b,c is 3 :4 :5 a increased by 20% and b increased by 25% and c reduced by 10% then find new ratio?<br />300 : 400 : 500<br />360 : 400 : 500<br />36 : 50 :45<br />EG:<br />Total votes polled in a election is 1200 votes difference between the winning and loosing candidate is 20%<br />then find how much votes that winning candidate got?<br />100%<br />20% 80%<br />differcnce 60% = 1200<br />1% = 20 votes<br />80% = 1600 votes<br />EG:<br />IN A ELECTION BETWEEN TWO CANDIDATES ONE CANDIDATE GOT 60% VOTES AND WON BY 500 VOTES THEN FIND TOTAL VOTES?<br />100%<br />40% 60%<br />DIFFERENCE 20% = 500<br />1% = 25 VOTES<br />TORAL = 100*25 = 2500 VOTES<br />EG:<br />TO pass in an exam every guy need 40% marks but one candidate got 40 marks and then failed by 40 marks then<br />total marks in that exam?<br />pass : 40 + 40<br />80<br />so pass percentage 40% = 80marks<br />1% = 2 marks<br />100% = 200 marks<br />EG:<br />to pass in an exam students need 30 % marks but one student got 100 marks<br />he got 10 marks more than pass mark then total marks in that exam?<br />pass % pass marks<br />30% 100marks - 10 marks<br />30% 90 marks<br />1% 3 marks<br />100% = 300 marks<br />Eg<br />in an exam a got 32% marks and failed by 9 marks<br />b got 40% marks and pass by 15 marks then find total marks in that exam?<br />a 32% -9marks<br />b 40% 15 marks<br />difference 15-(-9)<br />24<br />8% 24 marks<br />1% ?<br />1 percent 3 marks<br />total marks 300</span></div><div><br /></div></div></div>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-12077710605093204882021-06-20T05:29:00.000-07:002021-06-28T02:43:03.428-07:00Fundamentals of computer components of a computer system system software application software ram rom eapcet material<h1 style="text-align: left;"><span style="font-size: large;"> Fundamentals of computer components of a computer system system software application software ram rom eapcet material</span></h1><p align="center" class="MsoNormal" style="text-align: center;"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;"><br /></span></b></p><h2 style="text-align: center;"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">COMPUTER ORGANIZATION</span></b></h2>
<p class="MsoNormal"><o:p><span style="font-size: large;"> </span></o:p></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Fundamentals
of computer <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is based
on a binary circuit EBCDIC logic<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Extended
binary code for decimal interxhange code<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Supporting
ASCII<span style="mso-spacerun: yes;"> </span>logic standard <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Computer and
remaining electronic device difference --- memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
following is the major difference between computer and remaining electronic
device ---cloud repository<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Functional
units of the system <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size: large;"><span style="line-height: 115%;"><span style="mso-spacerun: yes;"> </span>Input ---</span><span style="font-family: Wingdings; line-height: 115%; mso-ascii-font-family: Calibri; mso-ascii-theme-font: minor-latin; mso-char-type: symbol; mso-hansi-font-family: Calibri; mso-hansi-theme-font: minor-latin; mso-symbol-font-family: Wingdings;"><span style="mso-char-type: symbol; mso-symbol-font-family: Wingdings;">à</span></span><span style="line-height: 115%;"> processing unit…..> output<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Component
which is used to insert the data to the system – input peripheral<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex:
keyboard, mouse,joystic,omr,ocr,micr,scanner,voice records,graphic table,light
pen,voice recorder,touch pad,<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
following is the primary input device?<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpFirst" style="mso-list: l1 level1 lfo1; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">a)<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">Mouse b)keyboard c) both d) none<o:p></o:p></span></span></p>
<p class="MsoListParagraphCxSpLast"><span style="font-size: large; line-height: 115%;">keyboard<o:p></o:p></span></p>
<p class="MsoNormal" style="margin-left: 18pt;"><span style="font-size: large; line-height: 115%;">Which of the following is used to identify thehologram
signalling and barcode readers ?<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpFirst" style="mso-list: l2 level1 lfo2; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">a)<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">Scanner b) keyboard c)ocr d)micr<o:p></o:p></span></span></p>
<p class="MsoListParagraphCxSpLast"><span style="font-size: large; line-height: 115%;">Micr <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which device
is used to detect<span style="mso-spacerun: yes;"> </span>the analog waves of
human body ?<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Graphic
tablet<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Component
which is used to display<span style="mso-spacerun: yes;"> </span>the processed
data?<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Output
peripherals<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Moniter ,
printer, speakers,projector screen<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
following is a stdout device monitor<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which
peripheral component is used to convert hardcopy to softcopy ?<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Scanner<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Raw data to
png --- scanner<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Zigzag to
mp4 format … videocam input<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pdf file to
raw data ---- printer <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Soft copy to
hardcopy – printer<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which device
is used to convert pdf to zip ? processor<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Processor is
one component to convert raw data to digital data<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Raw data to
system signal (system calls)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><span style="mso-spacerun: yes;"> </span>Data bus<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To recognize
all the peripherals<span style="mso-spacerun: yes;"> </span>which are connected
to the machine<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To detect
network signals<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To detect
cmos/bios internal tools<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To identify
pci/isa slot data<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">In processor
component contains 3 internal parts<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Memory unit<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Control unit<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Arithmetic
logic unit<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Memory unit : <o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To identify
internal and external memory resources <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">And it plans
for job scheduling<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Sequence
scheduling<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Control unit :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Monitors all
the peripherals which are connected to machine and it controls the instructions
by the support of system software it controls the signals by system bus and
data bus<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Arithmetic logic unit :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It performs
the instructions which are monitored by cu <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Broths
algorithm based on performs operations<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">(8086 scsi
controller)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Small
computer system interface<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Components of a computer system :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Peripheral/
hardware of the system <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cabinet<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Mother board<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All i/o
devices<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Network
interface code<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cmos<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;"><o:p> </o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Mother board :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Internal
memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pci slots<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Isa slots<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Jumper
settings<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Cmos battery<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Keyboard and
monitor connector<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Power
conector<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Chip sets<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Socket 7
(processor solt)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Chip sets :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">North bridge<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">South bridge<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Types of softwares :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Software :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a
program to coordinate raw data and system resources<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Buit of
statements (system calls) (instructions)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Post primary
functions to load the os from secondary memory to ram<o:p></o:p></span></p>
<p class="MsoListParagraphCxSpFirst" style="mso-list: l0 level1 lfo3; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">1)<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">System software<o:p></o:p></span></span></p>
<p class="MsoListParagraphCxSpLast" style="mso-list: l0 level1 lfo3; text-indent: -18pt;"><span style="font-size: large;"><!--[if !supportLists]--><span style="line-height: 115%; mso-bidi-font-family: Calibri; mso-bidi-theme-font: minor-latin;"><span style="mso-list: Ignore;">2)<span style="font-family: "Times New Roman"; font-stretch: normal; font-style: normal; font-variant: normal; font-weight: normal; line-height: normal;"> </span></span></span><!--[endif]--><span style="line-height: 115%;">Application software<o:p></o:p></span></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">System software : <o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is mainly
interacts with hardware resources<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Its also
interacts with existing system architectures<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It also
interacts with some raw data<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex : loader,
linkers,assembles,device drivers,encoder,decoder,system calls<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Dma system
calls<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Application software :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It interacts
with user data or human readable data<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Note :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All the
installed software’s except os & device drivers<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ex : c ,
java,programming language,office tools,chrome browser<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">( IE ,
safari ----- inbuilt browsers)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All the IDES
(integrated dev environment) :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">How the
application software works :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">By the
support of system software and os<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Schema map :
<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a
temporary base table format<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Used to identify
the available os resources<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Path means :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a
secobdary storage data<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Storage
location<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Both<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">None<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Ans : both<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">System calls
are related to :<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Software and
system software<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Bsic
functions of the application software<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Easy to
implement user data<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Who will operate
application software <o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Both user
and os and system software<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Which of the
interface layer between user and operating system<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Application
software<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;"></span></p><p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Utility softwares :<span style="mso-spacerun: yes;"> </span><o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All the
utility softwares all called as inbuilt instructions or inbuilt methods<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">DLLS :
(dynamic link library fields)<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">. jar files , .dll files :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">API -----
utility software<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To resolve
the interrupts<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Main memory and its types<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Except
secondary memory all main memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Main memory
some times<span style="mso-spacerun: yes;"> </span>we will call as<span style="mso-spacerun: yes;"> </span><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Primary
memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">System
memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Inbuilt memory
(except ram)<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">Basic functionality of main memory :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It
recognizes all the system calls to store data temporarily<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is
volatile and nonvolatile<span style="mso-spacerun: yes;"> </span><o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It detects
system buses and data buses<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Is is used
to establish a connection between one resource to another resource<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">ROM :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Read only
memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a non
volatile memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It always
supports to the processor<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It always
interacts with control unit and memory unit of the processor<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Is supports
to the temporary instruction buffer (system call)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To the all
activated devices<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is
indirectly BIOS chip set (Basic input and out put system) to the all activated
devices<o:p></o:p></span></p>
<p class="MsoNormal"><b style="mso-bidi-font-weight: normal;"><span style="font-size: large; line-height: 115%;">PROM :<o:p></o:p></span></b></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Programmable
ROM<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Is is not a
part of ROM<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">There is
three logical parts of memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Auto exe.bat
file stored in prom<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It is a
programme used to write the instructions or data on a temporary<span style="mso-spacerun: yes;"> </span>memory and permanent memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Write the
instructions to the disk<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">PROM
supports RAID(data bucket)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Mirror disks
also non non volatile<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">EPROM:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Erasable
programmable read only<span style="mso-spacerun: yes;"> </span>memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To read the
data from cylinders<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To erase the
data on the cylinders<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">The fix the
bad clusters (unformatted space on the cylinders)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large;"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;">EEPROM</span></b><span style="line-height: 115%;"> :<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Electrically
erasable programmable read only memory<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Non volatile
when EEPROM<span style="mso-spacerun: yes;"> </span>is the active state it is
automatically activated to recover the problem<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size: large;"><b style="mso-bidi-font-weight: normal;"><span style="line-height: 115%;">RAM </span></b><span style="line-height: 115%;">:<o:p></o:p></span></span></p>
<p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Random
access memory<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Volatile –
when power gone data lose<o:p></o:p></span></p><p></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">To store
data on temporary basis this memory is used to maintain page table temporary
basis<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">PARTS OF RAM
:<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">SRAM DRAM
SDRAM<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large;"><b><span style="line-height: 115%;">SRAM</span></b><span style="line-height: 115%;"> :<o:p></o:p></span></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Static ram <o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">All
temporary applications stored in this memory<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It holds the
current cursor location file<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Pcb (
programmable control block) isrelated to SRAM<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">DRAM :<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Dynamic ram <o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">It creates
execution link for an application from permanent installed location to te
temporary available location<o:p></o:p></span></p><p class="MsoNormal"><b><span style="font-size: large; line-height: 115%;">SDRAM :<o:p></o:p></span></b></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">Synchronous
dynamic ram<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">
</span></p><p class="MsoNormal"><span style="font-size: large; line-height: 115%;">When the
sram and dram are in the interrupt stage sd ram memory is automatically
activate<o:p></o:p></span></p><p class="MsoNormal"><span style="font-size: 14pt; line-height: 115%;"><br /></span></p>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-56274739824075942682021-06-19T05:34:00.000-07:002021-06-28T02:43:22.271-07:00computer practice quiz and reasoning quiz quant and reasoning material<p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><h1><span style="color: #666666;"><span style="font-size: large; letter-spacing: 0.133333px;">computer practice quiz and reasoning quiz quant and reasoning material</span></span></h1><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) In a lottery, there are 5 prizes and 10 blanks in tickets. A ticket is drawn at random. What is the probability of getting a prize? <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1 1/7- <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) 2/7 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) 1/3 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) 2/3 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) None of these <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that one girl and two boys are selected is <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) 4/25 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) 25/117 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) 1/3 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) 21/46 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) None of these <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) The price of 8 chairs is equal to 3 tables. The price of 12 chairs and 5 tables together is Rs. 1,520. What is the total price of 10 chairs and 5 tables? <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) Rs. 1500 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) Rs. 1480 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) Rs. 1400 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) Rs. 1360 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) None of these <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) Rohit starts a business with Rs. 6,500 and after 8 months Shyam joins Rohit as his partner. After 4 years the profit is divided in the ratio of 13 : 12. What is Shyam's contribution in the capital?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) Rs. 7400 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) Rs. 7200 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) Rs. 7250 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) Rs.7630 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) Rs.7480 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) The speed of a boat in still water is 20 kmph and the rate of current is 4 kmph. The distance travelled by the boat downstream in 30 minutes is <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) 8km <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2)10km <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3)12km <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4)14 km <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5)16km <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">6) Rs. 2000 is invested at 10% p.a. on simple interest. If that interest is added to the principal after every 20 years, the amount will become Rs. 14,000 after <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) 15 years <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) 331/3 years <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) 16 2/3 years <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) 40 years <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) None of these <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">7) Two trains 128 meters and 122 meters long are running towards each other on parallel lines at 48 kmph and 42 kmph respectively. In what time will they clear off each other from the moment they meet? <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) 10 seconds <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) 12 seconds <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) 18 seconds <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) 14 seconds <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) 9 seconds <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">8) A boat running downstream covers 28 km in 7 hours. While for covering the same distance upstream it takes 14 hours. What is the speed of the boat in still water? <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) 4 kmph <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) 3 kmph <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) 4.2 kmph <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) 5 kmph <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) 6 kmph<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">9) The daily wage is increased by 50% and a person now gets Rs. 30 per day. What was his daily wage before the increment? <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) Rs. 12 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) Rs. 18 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) Rs. 20 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) Rs. 24 <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) None of these <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">10) Ram sells a car to Mohan at a profit of 16% and Mohan sells it to Shyam at a profit of 25%. How much profit % Ram would have got if he had sold the car directly to Shyam at the price Shyam bought it? <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1) 41% <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2) 42% <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3) 45% <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4) 50% <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5) None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1. The government has extended UK Sinha's term as the chairman of Securities and Exchange Board of India (SEBI) till ___________ <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">1.March 01, 2018<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">2. April 01, 2018<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">3.March 01, 2017<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">4. April 01, 2017<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">5. None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">Ans. March 01, 2017<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""arial" , "sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt;">UK Sinha will continue to lead India's capital and commodities market regulator for one more year. The government extended Sinha's term as the chairman of Securities and Exchange Board of India (Sebi) till March 01, 2017.The Bihar-cadre IAS officer becomes the second-longest serving chief in Sebi's over two-decade history after DR Mehta.Sinha took over as Sebi chairman in 2011 with a three-year term. After that he was given a two-year extension.<o:p></o:p></span></div><h3 style="line-height: 27pt; margin-bottom: 0.1in; vertical-align: baseline;"><span style="font-size: large;"><span style="color: #222222; font-family: "Roboto Condensed","serif"; mso-bidi-font-family: "Times New Roman"; mso-fareast-font-family: "Times New Roman"; text-transform: uppercase;">COMPUTER PRACTICE QUIZ & </span><span style="color: #222222; font-family: 'Roboto Condensed', serif; line-height: 27pt; text-transform: uppercase;">REASONING PRACTICE QUIZ</span></span></h3><div class="MsoNormal"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">1. The ascending order of a data hierarchy is -----------<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) Bit-byte-record-field-file-database<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) Byte-bit-field-record-file-database<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) Bit-byte-field-record-file-database<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) Byte-bit-record-file-field-database<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) None of these.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">2. A spiral shape track formatting is present in ………<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) Floppy Disk<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) Optical Disk<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) Hard Disk<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) Half-inch Tape Cartridge<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">3. Which of the following groups contains graphical file extensions?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) JPG, CPX, GCM<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) GIF, TCF, WMF<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) TCP, JPG, BMP<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) JPG, GIF, BMP<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">4. VPN stands for -------<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) Virtual Personal Network<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) Very Private Network<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) Virtual Private Network<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) Vicious Personal Network<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">5. Which of the following is true about Dial-up internet access?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) It utilizes the existing telephone services<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) It uses a router for security<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) It utilizes the broadband technology<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) Modem speeds are very fast<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) All of the above<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">6. If a memory chip is volatile, it will .......<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) explode if exposed to high temperatures<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) lose its contents if current is turned off<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) be used for data storage only<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) be used to both read and write data<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">7. During the ____________ operation, the control unit determines what the program is telling the computer to do.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) fetch<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) execute<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) decode<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) arithmetic<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">8. A plotter is ---------<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) An input device to produce good quality graphics<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) An output device to produce drawings and graphics<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) A fast output device using camera lenses<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) All of the above<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) None of these.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">9. Which of the following is a graphical package?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) CorelDraw<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) MS-Excel<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) MS-Word<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) all of the above<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) Noneof these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">10. MICR is exclusively used in -------------<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) Libraries<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) Super markets<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) Stock markets<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) Banking Industry<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><b><span style="border: 1pt none windowtext; color: #666666; font-family: "inherit","serif"; letter-spacing: 0.1pt; mso-bidi-font-family: Arial; mso-border-alt: none windowtext 0in; mso-fareast-font-family: "Times New Roman"; padding: 0in;">Answers:</span></b><span face=""Arial","sans-serif"" style="color: #666666; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">1. c<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">2. b<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">3. d<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">4. c<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">5. a<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">6. b<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">7. c<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">8. b<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">9. a<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">10. d<o:p></o:p></span></div><div class="MsoNormal"><span style="font-size: large;"><br /></span></div><h3 style="line-height: 27pt; margin-bottom: .1in; margin-left: 0in; margin-right: 0in; margin-top: 0in; margin: 0in 0in 0.1in; vertical-align: baseline;"><span style="font-size: large;"><br /></span></h3><div class="MsoNormal"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Directions (Q.1-5): Read the information given below and then answer the questions given below:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Eight friends Aero, Boom, Chris, Dale, Elina, Francos, Gayle and Hippa are sitting around a circle in such a way that three of them are facing outside and rest of them are facing the centre.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Elina is 2nd to the left of Hippa, who is facing outside. Dale is second to the left of Francos and third to the right of Elina, who is facing the centre. Boom is third to the left of Gayle and faces outside. Gayle is third to the left of Aero, who is not an immediate neighbour of Elina and Francos. The friends facing outside are not adjacent.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">1. Which of the following group is facing outside?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(a) Boom,Hippa,Elina<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><span style="border: 1pt none windowtext; color: #cc0000; font-family: "inherit","serif"; letter-spacing: 0.1pt; mso-bidi-font-family: Arial; mso-border-alt: none windowtext 0in; mso-fareast-font-family: "Times New Roman"; padding: 0in;">(b) Chris,Boom,Hippa</span><span face=""Arial","sans-serif"" style="color: #666666; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(c) Chris,Dale,Hippa <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(d) cannot be determined<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(e) None of these<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">2. What is Dale’s position with respect to Aero?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><span style="border: 1pt none windowtext; color: #cc0000; font-family: "inherit","serif"; letter-spacing: 0.1pt; mso-bidi-font-family: Arial; mso-border-alt: none windowtext 0in; mso-fareast-font-family: "Times New Roman"; padding: 0in;">(a) Immediate right</span><span face=""Arial","sans-serif"" style="color: #666666; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(b) 3rd to the left<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(c) Opposite <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(d) 2nd to the right<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(e) Immediate left<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">3. Who is 2nd to the right of Boom?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(a) Hippa<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(b) Gayle<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(c) Chris <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><span style="border: 1pt none windowtext; color: #cc0000; font-family: "inherit","serif"; letter-spacing: 0.1pt; mso-bidi-font-family: Arial; mso-border-alt: none windowtext 0in; mso-fareast-font-family: "Times New Roman"; padding: 0in;">(d) Aero</span><span face=""Arial","sans-serif"" style="color: #666666; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(e) Dale <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">4. If all the friends change their respective position to immediate right place then who are still facing inside the centre?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(a) Aero and Elina<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(b) Francos and Dale<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(c) Francos and Gayle <o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(d) Aero and Dale<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><span style="border: 1pt none windowtext; color: #cc0000; font-family: "inherit","serif"; letter-spacing: 0.1pt; mso-bidi-font-family: Arial; mso-border-alt: none windowtext 0in; mso-fareast-font-family: "Times New Roman"; padding: 0in;">(e) Gayle and Aero</span><span face=""Arial","sans-serif"" style="color: #666666; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">5. Which of the following is true about the given information?<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(a) Chris and Francos are facing each other.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(b) Elina is third to the left of Francos.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(c) Chris is third to the left of Boom.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><span style="border: 1pt none windowtext; color: #cc0000; font-family: "inherit","serif"; letter-spacing: 0.1pt; mso-bidi-font-family: Arial; mso-border-alt: none windowtext 0in; mso-fareast-font-family: "Times New Roman"; padding: 0in;">(d) Gayle and Aero are two places away from each other, if counted in clock wise direction from Aero.</span><span face=""Arial","sans-serif"" style="color: #666666; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";"><o:p></o:p></span></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">(e) None of these.<o:p></o:p></span></div><div class="MsoNormal"><span style="font-size: large;"><br /></span></div><div class="MsoNormal"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Directions (6-10): In each of the following questions two statements are given and these statements are followed by two conclusions numbered (I) and (II). You have to take the given two statements to be true even if they seem to be at variance from commonly known facts. Read the conclusions and then decide which of the given conclusions logically follows from the two given statements, disregarding commonly known facts. Give answer:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">a) if only conclusion I is true.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">b) if only conclusion II is true.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">c) if either conclusion I or conclusion II is true.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">d) if neither conclusion I nor conclusion II is true.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">e) if both conclusions I and II are true.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">6. Statements: All table are desk.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Some desk are chair.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Conclusions:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">I. Some chair are table.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">II. All table are chair.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Answer-d<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">7. Statements:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Some pagal are mad.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">No mad is cool.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Conclusions:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">I. Some pagal are cool.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">II. No pagal is cool.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Answer-c<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">8. Statements:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Some hot are yak.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Some bold are hot.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Conclusions:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">I. Some hot are bold.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">II. Some bold are yak.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Answer-a<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">9. Statements:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">All the stairs are ball.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Some zebra are ball.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Conclusions:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">I. Some ball are stairs.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">II. No stairs is a zebra.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Answer-a<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span style="font-size: large;"><br /></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">10. Statements:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Some shop are malls.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Some malls are roof.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Conclusions:<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">I. All shop are roof.<o:p></o:p></span></div><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">II. Some roof are shop.<o:p></o:p></span></div><span style="font-size: large;"><br /></span><div class="MsoNormal" style="background: white; line-height: 18.3pt; margin-bottom: 0in; text-align: justify; text-justify: inter-ideograph; vertical-align: baseline;"><span face=""Arial","sans-serif"" style="color: #666666; font-size: large; letter-spacing: 0.1pt; mso-fareast-font-family: "Times New Roman";">Answer-d</span></div>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-53335950167567209172021-06-18T05:31:00.000-07:002021-06-28T02:43:55.855-07:00PROFIT AND LOSS ARTHMETIC MATERIAL<h1 style="text-align: left;"><span style="font-size: large;"> PROFIT AND LOSS ARTHMETIC MATERIAL</span></h1><h4 style="text-align: left;"><span style="font-size: large;"> PROFIT AND LOSS</span></h4><p><span style="font-size: large;"> .....................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF SP > CP</span></p><p><span style="font-size: large;">PROFIT = SP-CP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF CP > SP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">LOSS = CP - SP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PROFIT % = (PROFIT/CP)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">LOSS % = (LOSS/CP )* 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN BOUGHT A BOOK FOR 200 RS AND SELLS IT FOR 240 RS WHAT IS HIS GAIN PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> GAIN = 240-200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT % = (40/200)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOPKEEPER PURCHASED A BOX FOR RS 300 AT WHAT PRICE HE HAS TO SELL TO GET A GAIN OF 15%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15% = (P/300)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = (15/100)*300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT +CP = 300+45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 345</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">METHOD 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT 15%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%.....................300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 115%....................?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 345</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BY SELLING A HAT FOR 500 RS A PROFIT OF 25% IS MADE FIND THE COST PRICE OF THE HAT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> PROFIT 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SO 125% ......... 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100% .........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IMPORTANT TABLE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT % COST PRICE PROFIT/LOSS SELLING PRICE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% 100 25 125</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15% 100 15 115</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 35% 100 35 135</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -10% 100 -10 90</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -45% 100 -45 55</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BY SELLING AN ARTICLE FOR RS 640 A LOSS OF 20% IS MADE FIND THE COST PRICE OF THE ARTICLE ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80% ..........640</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%...........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100*640)/80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BY SELLING A BOOK FOR 540 RS A GAIN OF 20% IS MADE IF IT IS SOLD TO LOSS OF 20% WHAT WILL BE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SELLING PRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120 % --------540</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80%...........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (80*540)/120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 360</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A GAIN OF 30% IS MADE BY SELLING A BOOK FOR RS 520 RS AT WHAT PRICE IT SOLD TO GAT A GAIN OF 60%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 130%---------520</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 160%...........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (160*520)/130</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 640</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BY SELLING A WATCH FOR 480 RS A PROFIT OF 20% IS MADE WHAT IS THE GAIN OR LOSS PERCENTAGE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF IT IS SOLD FOR RS 380?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120%--------480</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ? ........380</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (120*380)/480</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 95%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100-95</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5% LOSS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MR RAMU SOLD A PEN AT 12% PROFIT HAD HE SOLD IT FOR 24RS MORE HE WOULD HAVE GAINED 18% </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT IS THE COST PRICE OF PEN?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18-12 = 6%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6% ...........24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100% ---?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">RAJESH SOLA AN ARTICLE AT 10% LOSS IF HE HAD TAKEN 98 RS MORE HE WOULD HAVE GAINED 4% WHAT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IS THE COST PRICE OF THE ARTICLE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10-(-4)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 14%..........98</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%...............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100*98)/14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 700</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SURYA PURCHASES 2 BOOKS AT 300 RS HE SOLD ONE BOOK AT 10% GAIN AND OTHER BOOK AT 10% LOSS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT IS THE TOTAL LOSS OR GAIN PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP 100 .....300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 110....?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 330</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP 100.......300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90.......?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 270</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP1 +CP2 = 330+270 = 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300+300 = 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> BOTH SAME SO NO PROFIT AND NO LOSS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A COMPANY SELLS TWO CELLPHONES AT 24000 EACH ON ONE HE GAINED 20% AND OTHER LOSS 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT IS THE OVERALL GAIN OR LOSS PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> CP1 :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120 ------- 24000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100 ..........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP2 :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80 ...........24000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100...........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP1+CP2 = 20000+30000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP1+SP2 = 24000+24000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 48000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 48000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ..............</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (2000/50000)/100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4% LOSS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF THE COST PRICE OF THE TWO ARTICLES ARE EQUAL AND A LOSS OF X PERCENT ON 1 IS EQUAL TO A</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">GAIN OF X PERCENT ON OTHERTHAN OVERALL TRANSACTION THERE WILL BE NO LOSS OR NO PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF SELLING PRICE OF TWO ARTICLES ARE SAME AND A GAIN OF X PERCENTAGE ON ONE ARTICLE IS EQUAL TO ALOSS OF X% ON THE OTHER THEN </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN OVERALL TRANSACTION THEIR WILL BE ALWAYS LOSS OF (X*X)/100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOPKEEPER SELLS TWO BOOKS FOR 520 RS EACH ONE HE GAINS 30% ON THE FIRST AND LOSES 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ON THE OTHER WHAT IS THE GAIN OR LOSS PERCENTAGE IN THE OVERALL TRANSACTION?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> CP1 130 -------520</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100 ........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80-------520</span></p><p><span style="font-size: large;"> CP2</span></p><p><span style="font-size: large;"> 100..........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 650</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> SP = 520+520 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1040</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP = 650+400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1050</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (10/1050)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF THE RATIO OF COST PRICE AND SELLING PRICE IS 5 : 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND THE GAIN PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 -------100</span></p><p><span style="font-size: large;"> ..................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 .......120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT % = (P/CP)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (1/5)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN BUYS AN ARTICLE FOR 10% LESSTHAN ITS VALUE AND SELLS IT FOR RS 10% MORE THAN ITS VALUE HIS GAIN OR LOSS PERCENTAGE IS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A) LESS THAN 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">B) MORE THAN 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">C) 20% PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">D) CAN NOT BE DETERMAINED</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90 .......100........110</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP SP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20/90)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 22(2/9)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ANS B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> BY SELLING AN ARTICLE PER RS 960 A PROFIT OF 20% IS MADE FIND THE COSTPRICE OF THE ARTICLE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 960.......120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ?.........100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (960*100)/(120)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF THE COST PRICE OF 20 ARTICLES IS EQUALS TO SELLING PRICE OF 16 ARTICLES WHAT IS THEW GAIN OR LOSS %?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP(20) = SP(16)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP 20 = SP 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP/SP = 16/20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4/5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P% = (1/4)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE COST PRICE OF 10 TABLES IS EQUALS IS EQUALS TO SELLING PRICE OF 20 TABLES WHAT IS THE LOSS PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP(10) = SP(20)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP/SP = 1/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> LOSS PERCENTAGE = (1/2)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BY SELLING 33 METERS OF CLOTH THE MAN GAINS THE SELLING PRICE OF 11 METERS OF CLOTH FIND HIS GAIN</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OR LOSS PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP = CP +PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP(1) = CP(1) +PROFIT(1)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP(33) = CP(33) +PROFIT(33)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP(22) = CP(33)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP/CP = 33/22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT PERCENTAGE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (11/22)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BY SELLING 33 APPLES A MAN GAINS COSTPRICE OF 11 APPLES FIND HIS GAIN PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP = CP+PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP(33) = CP(33) +CP(11)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP/CP = 44/33</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/3)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 33(1/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF PENCILS ARE PURCHASED AT 5 PER A RUPEE HOW MANY MUST BE SOLD FOR RS 1 TO GET PROFIT OF 25%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1......5 CP/SP = 1/5 = 20P</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> P% = 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP ......100% .......20P 1/5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 125%.........? 1/4 100/25 = 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOPKEEPER BUYS PENS AT 9 PER 10 RS AND SELLS THEM AT 10 PER RS 9 WHAT IS HIS LOSS OR GAIN PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 PENS 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90 PENS 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 PENS 9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90 PENS 81</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100 TO 81 DECREASED -19%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A PERSON BUYS AN ITEM 5 PER 4 RS AND SELLS 4 PER 5 GAIN PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20 ........16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20...........25</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9% PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT PERCENTAGE (9/16)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 56(1/4)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN BUYS EGGS AT 2PER 1 RS AND AN EQUAL NUMBER AT 3 PER RS 2 ANBD SELLS THE WHOLE AT 5 PER 3 RE FIND</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HIS GAIN OR LOSS PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> COSTING</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 EGGS 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 EGGS 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SELLING</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 EGGS 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> LCM 30 (2,3,5)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 30 ...15 5......3</span></p><p><span style="font-size: large;"> *12 *12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30 ...20 60.....36</span></p><p><span style="font-size: large;"> .........................</span></p><p><span style="font-size: large;"> 60 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P% = (1/35)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE LOSS OBTAINED BY SELLING AN ARTICLE PER 70 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SAME AS THE GAIN OBTAINED BY SELLING IT FOR 120 RS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP = 70</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SP = 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP-X = 70</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP+X = 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2CP = 190</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP = 95</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">DAVID SELLS A BICYCLE TO RAJU AT 40% PROFIT RAJU SELLS IT TO MOHAN AT 10% LOSS IF MOHAN</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PAYS 2520 PER HIM AT WHAT PRICE DID DAVID BUY IT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40% -10%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100 DAVID............> RAJU..................> MOHAN</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> *20</span></p><p><span style="font-size: large;"> ........... 140 140-14 = 126</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2000 * 20</span></p><p><span style="font-size: large;"> .............</span></p><p><span style="font-size: large;"> 2520</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A DISHONEST DEALER PROMISES TO SELL SUGAR AT THE COST PRICE BUT USES A WEIGHT OF 900 GRMS INSTEAD OF 1KG WHAT IS HIS GAIN PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10000</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> CP PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 900 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1000-900</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (PROFIT/CP)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ( 100/900)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 11(1/9)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> FOR CUSTOMER IT IS A LOSS OF 10%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF GOODS ARE PURCHASED FOR 6000 RS 1/4 TH IS SOLD AT A LOSS OF 20% AND THE REMAINING WERE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SOLA AT 10% PROFIT WHAT IS THE OVERALL GAIN OR LOSS PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL 6000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1/4 3/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -20% +10%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1500 4500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -300 450</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ......................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1200 4950</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6150-600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (150/6000)*100 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2.5%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOPKEEPER MARKS HIS GOODS 20% ABOVE THE COST PRICE BUT ALLOWS A DISCOUNT OF 10% WHAT IS HISS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">GIAN OR LOSS PERCENT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MP 10% DISC</span></p><p><span style="font-size: large;"> 100......>120......>108</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MARKED PRICE 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">DISCOUNT 120-12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 108</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A CLOTH MERCHANT ALLOWS TWO SUCCESSIVE DISCOUNTS OF 20% and 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">find his discount after two successive changes?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100..........>80.................>64</span></p><p><span style="font-size: large;"> 20 -16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> successive changes</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> if x% and y % are two successive changes on a single article then overall change is given by </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x+y+(xy)/100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> -20-20+(20*20)/100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -40+4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -36%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> discount % = (discount/market price )*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER DELETING COMISSION OF 5% A TV SET COST 9595 FIND ITS MRP?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9595.......95%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ?..........100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (9595*110)/(95)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOP KEEPER SELLS A TV ON DISCOUNT 8% ON PRINTED PRICE AND GAINS 25% IF PRINTED PRICE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WAS 20000 RS THEN FIND ITS COST PRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRINTED PRICE 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> DISCOUNT 8% =1600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> .......................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18400...........125</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ?.................100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 14720</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHOPKEEPER MARKS HIS GOODS 20% ABOVE THE COST PRICE AND ALLOWS THE PURCHASE FOR A DISCOUNT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF 10% FOR CASH PAYMENT FIND PROFIT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MP TO SP ...........> DISCOUNT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP TO MP.............> PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> +20 -10</span></p><p><span style="font-size: large;"> CP.........> MP..........>SP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100 120 108</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8% PROFIT </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOPKEEPER OFFERS 10% DISCOUNT ON AN ARTICLE AND STILL MAKES A PROFIT OF 20% TO HIM</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT IS THE ANNUAL COST OF THE ARTICLE MARKED 500 RS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10% DISCOUNT ON 500 450</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120% ...........450</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100% .........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 375</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOPKEEPER SOLD AN ARTICLE OFFERING A DISCOUNT OF 5% AND EARNED A PROFIT OF 23.5%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT WOULD HAVE BEEN THE PERCENTAGE OF PROTIF EARNED IF THE NO DISCOUNT HAS BEEN OFFERED?</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> -10%</span></p><p><span style="font-size: large;"> CP ............> MP ...........>SP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 23.5%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">NO DISCOUNT ALLOWED MEANS WE HAVE TO FIND THE PERCENTAGE OF MARK PRICE ABOVE THE COST PRICE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP...........SP........MP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 95%MP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 125%CP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 95%MP.............123.5%CP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%MP.............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (100*123.5)/95</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 130%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOPKEEPER OBTAINS A PROFIT OF 20% AFTER ALLOWING A DISCOUNT OF 10% ON MARKED PRICE HOW </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MUCH PERCENTAGE ABOVE THE COST PRICE IS THE MARKED PRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% 10%</span></p><p><span style="font-size: large;"> CP<........SP<.........100</span></p><p><span style="font-size: large;"> 100%CP 90%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120%CP = 90%OF MP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ?CP = 100%OF MP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (120*100)/90</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 133(1/3)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> METHOD 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X - 10-(10X/100) = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9X/10 = 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 300/9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SHOPKEEPER EARNS A PROFIT OF 15% AFTER SELLING A BOOK AT 20% DISCOUNT ON THE PRINTED PRICE THE RATIO</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF THE COST PRICE AND PRINTED PRICE OF THE BOOK?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20%</span></p><p><span style="font-size: large;"> CP ..........SP..........MP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 115%CP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80%MP</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP/MP = 80/115</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16/23</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE MARKED PRICE OF A ARTICLES IN A SHOP ARE 20%MORE THAN COST PRICE THE SHOPKEEPER GIVES A DISCOUNT OF 40 RS ON PURCHASE OF 960</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT IS THE NET PROFIT %?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CP........MP........SP</span></p><p><span style="font-size: large;"> 800 +20% 960 -40 920</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 920-800 = 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE DIFFERENCE BETWEEN A DISCOUNT OF 35% AND TWO SUCCESSIVE DISCOUNT OF 20% AND 205 ON A CERTAIN BILL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WAS 22 RS FIND AMOUNT OF BILL?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -20-20+(400/100)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> DIFF 35 TO 36 = 1%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% .....22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%.....?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE DIFFERENCE BETWEEN SUCCESSIVE DISCOUNTS OF 40% FOLLOWD BY 30% AND 45% FOLLOWED BY 20% ON THE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MARKED PRICE OF A SHIRT IS 12 RS WHAT IS THE MARKED PRICE OF THE SHIRT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -40-30+12 = -58</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -45-20+9 = -56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2%..........12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%...........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100*12)/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND A SINGLE DISCOUNT IS EQUALS TO SERIED DISCOUNTS OF 10% 20% AND 40%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -10 -20 -40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -10 -20+2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -28 -40+ 11.2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -68+11.2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -56.8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">METHOD 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100................90.........72.........56.8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -20 -40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A MAN BAUGHT A BOOK FOR 500 RS AND SOLD IT FOR 20% PROFIT FIND SELLING PRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> SP = CP + PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 500 + (20% OF 500)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN BAUGHT AN ITEM FOR 600 RS AND SOLD IT FOR 10% LOSS THEN FIND SELLING PRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10% OF LOSS IN 600 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (10/100)*600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600-60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 540</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BY SELLING AN ITEM FOR 600 RS A PROFIT OF 20 % MADE FIND COST PRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> COST PRICE = 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SELLING PRICE = 100% +20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 120% -------600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1%..........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (600/120)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> PROFIT = 600-500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BY SELLING AN ITEM FOR 360 RS A LOSS OF 10% MADE FIND LOSS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 % LOSS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SO 90% SP - 360</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 % ..?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%......400RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> LOSS : 400 - 360</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN SOLD AN ITEM FOR 5 % PROFIT HAD HE SOLD IT FOR 24RS MORE HE WOULD HAVE GAINED 8 % PROFIT FIND </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">COST PRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> DIFFERENCE 8%-5% = 3%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3%...........24 RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1%............8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%.....800RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN SOLD AN ITEM FOR 5% LOSS HAD HE SOLD IT FOR 30RS MORE HE WOULD HAVE GAINED 10% PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND COST PRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> DIFFENECE (10%- (_5%)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15%''</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 15%-----30RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1%......2RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%......200RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN SOLD AN ITEM FOR 5% LOSS HAD HE SOLD IT FOR 40RS MORE HE WOULD HAVE GAINED 5% PROFIT FIND COSTPRICE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -5 TO 5 % = 10%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10% --- 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1%......?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%........400RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3 : 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE FIND BOYS PERCENTAGE (3/5)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND GIRLS PERCENTAGE (2/5)*100 = 40%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BOYS ARE HOW MUCH PERCENTAGE MORE THAN GIRLS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (NUMBER OF BOYS - NUMBER OF GIRLS)/NUMBER OF GIRLS *100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (3-2)/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/2)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">GIRLS ARE HOW MUCH PERCENTAGE MORE THAN BOYS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (NUMBER OF GIRLS - NUMBER OF BOYS)/NUMBER OF BOYS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/3)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 33(1/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">COMPARE BOYS WITH GIRLS THEN FIND PERCENTAGE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (3/2)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 150%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">COMPARE GIRLS WITH BOYS THEN FIND PERCENTAGE ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (2/3)* 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 200/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 66(2/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN WEIGHT INCREASED FROM 60 KGS TO 72 KGS THEN FIND PERCENTAGE OF INCREASE IN WEIGHT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 72-60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> INCREASE ALWAYS COMPARE WITH INITIAL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">INITIAL = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (12/60)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN WEIGHT DECREASE FROM 60 TO 51 KGS THEN FIND DECREASE PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 60 - 51</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> INITIAL 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (9/60)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SALARY IS 20% LESS THAN B SALARY THEN FIND B SALARY IS HOW MUCH MORE THAN A SALARY?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20/80)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> SHORT CUT FORMULAE :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (X/(X+100))*100% INCREASE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X/(X-100))*100% DECREASE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20/(100-20))*100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20/80)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ONE VALUE FIRST INCREASED TO 25% THEN HOW MUCH MUCH IT WILL BE REDUCED TO GET THE INITIAL VALUE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (25/125)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A RECTANGLE LENGTH INCREASED BY 20% HOW MUCH ITS BREADTH WILL BE DECREASED TO</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">NO CHANG IN AREA?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20/120)*100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16(2/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT PERCENTAGE : (DIFFERNECE)/(LOWEST VALUE) *100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> LOSS PERCENTAGE = (DIFFERENCE)/(HIGHEST VALUE)*100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ONE ITEM BOUGHT FOR 500 RS AND SOLD IT FOR 60 RS THEN FIND PROFIT PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100/500)*100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ONE ITEM BAUGHT FOR 500 RA AND SOLD IT FOR 425 RS THEN FIND LOSS PERCENTAGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (75/500)*100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15%</span></p><p><span style="font-size: large;"> Allegation</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A CLASS AVERAGE AGE OF 60 STUDENTS IS 15 YEARS AVERAGE AGE OF BOYS IS 13 YEARS AND GIRLS IS 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">YEARS FIND NO OF BOYS AND NO OF GIRLS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> BOYS GIRLS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 13 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16-15= 1 15-13 = 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1 PART ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 60/3 = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 2*20 = 40 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20,40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A SOLUTION THERE IS 20% FINISHED </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN ANOTHER THERE IS 30% FINISHED </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HOW MANY LITERS OF FIRST SOLUTION IS MIXED WITH 60 LITERS OF SECOND SOLUTION SO THAT THERE IS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">24% IN THE MIXURE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 20 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 30-24 = 6 24-20 = 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SO 3 :2 </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 2 PARTS 60 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS 90</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN BOUGHT 2 ARTICLES FOR RS 600 ONE ARTICLE IS SOLD AT 10% PROFIT AND ANOTHER ARTICLE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SOLD AT 5% LOSS OVERALL THERE IS NO LOSS OR NO GAIN FIND THE COST OF EACH ARTICLE ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> SAY PERCENTAGE 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 110 95</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 3 ----------600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 .........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 200,400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN BORROWED RS 60,000 IN 2PARTS ONE AT 3% AND ANOTHER AT 6% RATE OF INTERESTIF TOTAL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SIMPLE INTEREST FOR 1 YEAR IS RS 3000 FIND THE MONEY LENDED 2% PER ANUM?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%........60,000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1%..........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3% 6%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600 1200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3.....60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 ......?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60000/3 = 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">POPULATION OF A TOWN IS 10000 IF MALES INCREASED BY 3% AND FEMALE INCREASED BY 8% THEN THE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OVERALL POPULATION BECOMES 10,500 FIND NO OF FEMALES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% .........100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300 800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5............10000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:IN A BAG THERE ARE 80 COINS PARTIY OF 50 PAISE AND PARTLY OF 25 PAISE THE TOTAL AMOUNT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN THE BAG 36 RA FIND THE TOTAL NO OF 50 PAISEAND NO OF 25 PAISE COINS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50P 20P</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5 .............80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (4*80)/5</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 64</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN AN EXAM THERE ARE 40 QUESTIONS A STUDENT GET 3 MARKS FOR EVERY CORRECT ANSWER</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1 CMARK DEDUCTION FOR EVERY WRONG ANSWER A STUDENT ATTENDED ALL THE QUESTIONS AND GOT 88 MARKS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">CORRECT ANS ? WRONG ANS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120 - 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 88</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 128 32</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5..........40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1......?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40/5 = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> WRONG 8 CORRECT 32</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> METHOD 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 3C-1W = 88</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C+W = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ..................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4C = 128</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C = 32</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> W = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A GARDEN THERE ARE SOME PIGEONS AND RABBITS TOTAL NUMBER OF HEADS 60 TOTAL NO OF LEGS 150 FIND</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE NO OF PIGEONS AND RABBITS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P R</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120L 240</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4.........60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3......?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (3*60)/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">COST OF 1 VARIETYRICE IS 16 PER KG</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AND ANOTHER RICE IS RS 20 PER KG</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND IN WHICH RATIO THERE ARE MIXED SO THAT BY SELLING THE MIXURE AT RUPEES 19.80 PER KG </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THERE IS A PROFIT OF 10%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1,2 @10% OF PROFIT = 19.80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16 10% = 16.0</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1.6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> .......</span></p><p><span style="font-size: large;"> 17.6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">20 10% = 20.0</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2.0</span></p><p><span style="font-size: large;"> ..........</span></p><p><span style="font-size: large;"> 22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 17.60 22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 19.80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2.20 2.20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">COST OF 1 LETER PURE MILK IS RS 30 AFTER MIXING WATER IN THAT DILUTED MILK IS SOLDED </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AT RS 30 THERE MILK AND WATER ARE MIXED?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> M = 30 @25% = 37.5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> W = 0 = 0</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> M+W = 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> M W</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 37.5 0</span></p><p><span style="font-size: large;"> 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30 7.5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS 60 STUDENS AVERAGE AGE IS 15 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BIYS AGERAGE IS 16 YEARS GIRLS AVERAGE AGE IS 13 YEARS THEN FIND HOW MANY BOYS AND HOW MANY GIRLS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B G</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16 13</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS BOYS AVERAGE WEIGHT 40 KGS GIRLS AVERAGE WEIGHT 30 KGS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">TOTAL STUDENTS AVERAGE WEIGHT 34 KGS IN THAT CLASS IF THERE ARE 12 BOYS FIND HOW MANY GIRLS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 34</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 2P = 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P =6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3*6 = 18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;">WE HAVE TO DISTRIBUTE 2.50 RS TO 100 STUDENTS IN AN AVERAGE BOYS CAN CAN 3.10 PAISE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">GALS CAN GET 2.10 PAISE THEN FIND BOYS AND GIRLS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100 STUDENTS AVG = 2.50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 STUDENT AVERAGE = 2.50 RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> BOYS AVG = 3.10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> GIRLS AVERAGE = 2.10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3.10 2.10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2.50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> .40 .60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40 BOYS 60 GIRLS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A SOLUTION 20 % MILK IN B SOLUTION 30% MILK 14 LETERS FIRST SOLUTION IS WITH</span></p><p><span style="font-size: large;"> X LITERS OF B SOLUTION THEN NEW SOLUTION FORMED IN THAT SOLUTION 28% MILK</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND X?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% 30%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 28%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 14 L</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 PARTS 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ANAND BAUGHT 2 ITEMS WITH 500 RE ON FIRST ITEM 10% ON SECOND ONE 20% THEN HE GOT OVERALL PFROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF 14% ON THOSE TWO ITEMS FIND WITHHOW MUCH COST HE BAUGHT THOSE TWO ITEMS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 10 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> RS 50O 3 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRAMOD BAUGHT 2 ITEMS FOR RS 500 RE HE SOLD FIRST ITEM FOR 10% PROFIT AND 2 ND ITEM FOR 5% LOSS THEN </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OVERALL NO LOSS AND NO GAIN ON TWO ITEMS THEN FIND WITH HOW MUCH COST HE HE BOUGHT THOSE TWO ITEMS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10% PROFIT 5% LOSS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 110% 95%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5% 10%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS = 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART = 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SIDDHU DIVIDED 600RS INTO TWO PARTS FIRST PART HE LENDED AT THE RATE OF 3%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2ND PART LENDED AT THE RATE OF 6% THEN HE GOT TOTAL INTEREST 300 RS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND THE AMOUNT LENDED FOR 3%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 3% 180</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6% 360</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 180 360</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 2000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PART 6000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A TOWN 35000 POPULATIUON 6% MALE AND 4 % FEMALE INCREASED THEN TOTAL POPULATION INCREAED TO 36766 THEN FIND </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HOW MANY MALE AND HOW MANY FEMALE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MALE FEMALE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6% 4%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2100 1400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1760</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 360 340</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18 17</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">35000 = 35PARTS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART = 1000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18000 17000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A GARDEN SOME HENS AND SOME GOATS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">TOTAL HEADCOUNT IS 60 AND TOTAL LEGS IS 150 THEN FIND TOTAL HENS AND TOTAL GOATS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> HEADS LEGS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ASSUM TOTAL HENS 120 240 TOTAL GOATS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120 240 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 1 </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4 PARTS 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> GOAT 15 HENS 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> Allegation</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A CLASS AVERAGE AGE OF 60 STUDENTS IS 15 YEARS AVERAGE AGE OF BOYS IS 13 YEARS AND GIRLS IS 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">YEARS FIND NO OF BOYS AND NO OF GIRLS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> BOYS GIRLS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 13 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16-15= 1 15-13 = 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1 PART ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 60/3 = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 2*20 = 40 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20,40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A SOLUTION THERE IS 20% FINISHED </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN ANOTHER THERE IS 30% FINISHED </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HOW MANY LITERS OF FIRST SOLUTION IS MIXED WITH 60 LITERS OF SECOND SOLUTION SO THAT THERE IS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">24% IN THE MIXURE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 20 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 30-24 = 6 24-20 = 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SO 3 :2 </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 2 PARTS 60 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS 90</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN BOUGHT 2 ARTICLES FOR RS 600 ONE ARTICLE IS SOLD AT 10% PROFIT AND ANOTHER ARTICLE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SOLD AT 5% LOSS OVERALL THERE IS NO LOSS OR NO GAIN FIND THE COST OF EACH ARTICLE ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> SAY PERCENTAGE 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 110 95</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 3 ----------600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 .........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 200,400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN BORROWED RS 60,000 IN 2PARTS ONE AT 3% AND ANOTHER AT 6% RATE OF INTERESTIF TOTAL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SIMPLE INTEREST FOR 1 YEAR IS RS 3000 FIND THE MONEY LENDED 2% PER ANUM?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%........60,000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1%..........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3% 6%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600 1200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3.....60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 ......?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60000/3 = 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">POPULATION OF A TOWN IS 10000 IF MALES INCREASED BY 3% AND FEMALE INCREASED BY 8% THEN THE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OVERALL POPULATION BECOMES 10,500 FIND NO OF FEMALES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% .........100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300 800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5............10000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:IN A BAG THERE ARE 80 COINS PARTIY OF 50 PAISE AND PARTLY OF 25 PAISE THE TOTAL AMOUNT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN THE BAG 36 RA FIND THE TOTAL NO OF 50 PAISEAND NO OF 25 PAISE COINS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50P 20P</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5 .............80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (4*80)/5</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 64</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN AN EXAM THERE ARE 40 QUESTIONS A STUDENT GET 3 MARKS FOR EVERY CORRECT ANSWER</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1 CMARK DEDUCTION FOR EVERY WRONG ANSWER A STUDENT ATTENDED ALL THE QUESTIONS AND GOT 88 MARKS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">CORRECT ANS ? WRONG ANS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120 - 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 88</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 128 32</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5..........40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1......?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40/5 = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> WRONG 8 CORRECT 32</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> METHOD 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 3C-1W = 88</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C+W = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ..................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4C = 128</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C = 32</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> W = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A GARDEN THERE ARE SOME PIGEONS AND RABBITS TOTAL NUMBER OF HEADS 60 TOTAL NO OF LEGS 150 FIND</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE NO OF PIGEONS AND RABBITS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P R</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120L 240</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4.........60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3......?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (3*60)/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">COST OF 1 VARIETYRICE IS 16 PER KG</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AND ANOTHER RICE IS RS 20 PER KG</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND IN WHICH RATIO THERE ARE MIXED SO THAT BY SELLING THE MIXURE AT RUPEES 19.80 PER KG </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THERE IS A PROFIT OF 10%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1,2 @10% OF PROFIT = 19.80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16 10% = 16.0</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1.6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> .......</span></p><p><span style="font-size: large;"> 17.6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">20 10% = 20.0</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2.0</span></p><p><span style="font-size: large;"> ..........</span></p><p><span style="font-size: large;"> 22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 17.60 22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 19.80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2.20 2.20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">COST OF 1 LETER PURE MILK IS RS 30 AFTER MIXING WATER IN THAT DILUTED MILK IS SOLDED </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AT RS 30 THERE MILK AND WATER ARE MIXED?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> M = 30 @25% = 37.5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> W = 0 = 0</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> M+W = 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> M W</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 37.5 0</span></p><p><span style="font-size: large;"> 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30 7.5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS 60 STUDENS AVERAGE AGE IS 15 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BIYS AGERAGE IS 16 YEARS GIRLS AVERAGE AGE IS 13 YEARS THEN FIND HOW MANY BOYS AND HOW MANY GIRLS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B G</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16 13</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS BOYS AVERAGE WEIGHT 40 KGS GIRLS AVERAGE WEIGHT 30 KGS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">TOTAL STUDENTS AVERAGE WEIGHT 34 KGS IN THAT CLASS IF THERE ARE 12 BOYS FIND HOW MANY GIRLS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 34</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 2P = 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P =6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3*6 = 18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;">WE HAVE TO DISTRIBUTE 2.50 RS TO 100 STUDENTS IN AN AVERAGE BOYS CAN CAN 3.10 PAISE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">GALS CAN GET 2.10 PAISE THEN FIND BOYS AND GIRLS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100 STUDENTS AVG = 2.50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 STUDENT AVERAGE = 2.50 RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> BOYS AVG = 3.10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> GIRLS AVERAGE = 2.10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3.10 2.10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2.50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> .40 .60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40 BOYS 60 GIRLS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A SOLUTION 20 % MILK IN B SOLUTION 30% MILK 14 LETERS FIRST SOLUTION IS WITH</span></p><p><span style="font-size: large;"> X LITERS OF B SOLUTION THEN NEW SOLUTION FORMED IN THAT SOLUTION 28% MILK</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND X?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% 30%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 28%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 14 L</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 PARTS 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ANAND BAUGHT 2 ITEMS WITH 500 RE ON FIRST ITEM 10% ON SECOND ONE 20% THEN HE GOT OVERALL PFROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF 14% ON THOSE TWO ITEMS FIND WITHHOW MUCH COST HE BAUGHT THOSE TWO ITEMS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 10 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> RS 50O 3 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRAMOD BAUGHT 2 ITEMS FOR RS 500 RE HE SOLD FIRST ITEM FOR 10% PROFIT AND 2 ND ITEM FOR 5% LOSS THEN </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OVERALL NO LOSS AND NO GAIN ON TWO ITEMS THEN FIND WITH HOW MUCH COST HE HE BOUGHT THOSE TWO ITEMS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10% PROFIT 5% LOSS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 110% 95%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5% 10%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS = 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART = 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SIDDHU DIVIDED 600RS INTO TWO PARTS FIRST PART HE LENDED AT THE RATE OF 3%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2ND PART LENDED AT THE RATE OF 6% THEN HE GOT TOTAL INTEREST 300 RS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND THE AMOUNT LENDED FOR 3%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 3% 180</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6% 360</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 180 360</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 2000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PART 6000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A TOWN 35000 POPULATIUON 6% MALE AND 4 % FEMALE INCREASED THEN TOTAL POPULATION INCREAED TO 36766 THEN FIND </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HOW MANY MALE AND HOW MANY FEMALE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MALE FEMALE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6% 4%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2100 1400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1760</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 360 340</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18 17</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">35000 = 35PARTS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART = 1000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18000 17000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A GARDEN SOME HENS AND SOME GOATS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">TOTAL HEADCOUNT IS 60 AND TOTAL LEGS IS 150 THEN FIND TOTAL HENS AND TOTAL GOATS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> HEADS LEGS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ASSUM TOTAL HENS 120 240 TOTAL GOATS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120 240 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 1 </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4 PARTS 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> GOAT 15 HENS 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><br /></p>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-27754317963693480952021-06-17T05:29:00.000-07:002021-06-28T02:44:15.769-07:00AVERAGE ARTHMETIC MATERIAL RATION AND PROPORTIONS<p><span style="font-size: large;"> AVERAGE:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Average = sum/n</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">n = sum/average</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Find the average of first 5 prime numbers ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2+3+5+7+11 = 28/5 = 5.6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Find the average of first 5 even numbers?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2+4+6+8+10 =30/5 =6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">if it is a arthmetic progression </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">constant increase </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">avg : (first term + last term)/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(2+10)/2 = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> or</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">exact middle number</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">find average of 10,12,14,16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(10+16)/2 = 13</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> or</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(10+12+14+16)/4 = 52/4 =13</span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">find the average on first 15 multiples of 3?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(3 + (3*15))/2 = 48/2 = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Find the average on first 20 multiples of 6?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(6+(20*6))/2 = 126/2 = 63</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">average of 5 consecutive even numbers is 36 then find numbers?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">32 34 36 38 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Average of 6 consecutive odd numbers is 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">35 37 39/41 43 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">sum of 3 consecutive rational numbers is 45 find sum?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">x+x+1+x+2 = 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">14,15 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">note:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">if the total sum of items is share equally in between each and every item then per head value is called average</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">pre head change = average change</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">average of sum of numbers is 50 each number is increased by 2 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">then find new average </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ans : 52</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">average sum of numbers is 25 if each number is multiplied by 2 and then deminished by 5 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">then find the new average</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (25*3) - 5 = 75-5 = 70</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">in a class average age of 20 students is 12 years if teacher age is included age increased by 2 years then find</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">age of teacher</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">20*12 = 240</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">21*14 = 294</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ......</span></p><p><span style="font-size: large;"> 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> or</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12 +(21*2) </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">average weight of 11 players is 80 kg if coach weight is included average decreased by 2 kg then find coach age?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">11*80 = 880</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">12*78 = 936</span></p><p><span style="font-size: large;"> ......</span></p><p><span style="font-size: large;"> 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">The score of a batsman for 12 matches is 45 rums howmany runs he has to score in his next match to increase his vaerage by 3 runs?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">12 matchs ave45 = 12*45 624</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">13 match ave increased by 3 13*48 540</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 624- 540 = 84</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">average score of a batsman for 15 matches is 40 runs how many runs he has to score in his nextmatch to decrease his average by 1 run?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">15*40 - 16 *39 40 </span></p><p><span style="font-size: large;"> 16 </span></p><p><span style="font-size: large;"> .........</span></p><p><span style="font-size: large;"> 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 2:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OUT OF SIX MEMBERS IN A GROUP ONE PERSON WHOSE WEIGHT IS 40 KG IS REPLACE BY A NEW PERSON THEIR BY AVERAGE IS INCREASED BY 2 KG THEN FIND THE WEIGHT OF NEW PERSON?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">40 +(6*2) = 52</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">out of 10 members in a group one person whose weight is 80 kg is replaced by a new person thereby average is decreased by 3kg </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">find thw weight of new person?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">80 - (10*3) = 50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">our of 10 members 2 members whose weight is 50 kg and 60 kg respectivilt are replace by 2 new persons thereby average is increased by 2 kg then find the avrage </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">weight of 2 new persons?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">110 + (10*2) = 130</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">130/2 = 65</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">out of 9 observations one record was wrongly taken as 36 instead of 63 therefore average </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">is 50 find correct average?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">n = 9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ave = 50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">actual 63 wrong 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">so 63-36 =27</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">avg + 27/9 = 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">actual average = 50 +3 =53</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">out of 10 observations 1 reading was wrongly taken as 80 instead of 30 therefore the average is 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">find the correct average?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">n = 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">average = 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">50 decreased</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">50/10 =5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">correct average = 28 -5 = 23</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;">Out of some numbers two numbers wrongle taken as 23 & 76 instead of 32 & 67 find the change in average?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">99 99</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">no change</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Model 4:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4 years ago average age of 3 members in a family is 14 years in the meanwhile a baby has been born </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">therefore the present average of family remains same find present age of baby?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3*14 = 42</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12</span></p><p><span style="font-size: large;"> ..........</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4*14 = 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ........</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Five years ago average age of 4 members in a family is 22 years in the meanwhile a baby has been born</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">therefore present average age of a family remain same find the age of baby?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4*22 = 88</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4*5 = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ......</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 108</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5*22 = 110</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 110</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 108</span></p><p><span style="font-size: large;"> ......</span></p><p><span style="font-size: large;"> 2 years</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">6 years ago average age of a,b,cd is 44 years 2 years ago c expire present average age of a,bd is 48 years find the age of c when he expire?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4*44 = 176</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6*4 24</span></p><p><span style="font-size: large;"> ..............</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 144</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> .....................</span></p><p><span style="font-size: large;"> 56</span></p><p><span style="font-size: large;"> 2 years ago -2</span></p><p><span style="font-size: large;"> ...........</span></p><p><span style="font-size: large;"> 54 years c age</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">average of 5 numbers is 6 fine the sum of numbers 5*6 = 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">the average of 5 elements is 12 and another 10 elements is 9find new avg?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (60+90)/15 = 150/15 =10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">the average marks obtained by 30 boys is 55 and the average marks obtained of 20 girls is 40 avg?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (1650 +800)/50 = 49</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG: </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">the average of 8 observations is 26 if the average of first 5 observations is 18.2 what is the average of remain?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8*26 = 5*18.2 +b</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 208 = 91.0 +b</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 117/3 = 39</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;">average of 11 numbers is 40 the average of first 5 numbers is 38 and the average of last 5 numbers</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">is 41 find middle number?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5*38 = 190</span></p><p><span style="font-size: large;"> 5*41 = 395</span></p><p><span style="font-size: large;"> .........</span></p><p><span style="font-size: large;"> 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">average of 7 results is 20 = 140</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">first 4 results is 25 == 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">last four results is 15 = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 160-140 =20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">T average temperature of monday,tuesday,wednesday,thursday is 48 and the average temperaturw on tuesday,wednesday,thursday,friday was 46 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">if the average temperature on friday was 34 find the temperature on monday?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> m,t,w,th ---------48</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> t,w,th,f ------------46</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> f --- 34</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">t,w,th,34 ..... 46</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 46-34 = 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">m,12 = 48</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> m=48-12 = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">the average of 4 elements is 11 if each element is increased by 7 what will be new average?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">28/4 = 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">11+7 = 18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">the average of 13 num 18 if each num is multipled by 3 find new average?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18 *3 = 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3*13*18 = 702</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 702/13 = 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A batsman 17 innings make a score of 85 runs and there by his average increased by 3 runs find </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">16 innings avg?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16 x = 16x</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 17 x+3 = 17(x+3)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16x+85 = 17(x+3)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> x = 85 -51 = 34</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">The average marks obtained by 60 students in an exam is 35 if the average marks of pass students 39 and that of failed students</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">is 15 how many students passed the exam?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> x 60-x</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 39x+ 15(60-x) = 60*35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">the average age of a family of 6 members is 44 if the age of a youngest member be 14 years find the average age of the family at the birth</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">of the younger member?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 6*44 = 264</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -14*6 = -84</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ....................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 180</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 180/5 = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">The average age of a and b is 20 years if c were to replace a the average would be 19 nif c were</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">to replace b the average would be 21 find the ages of a,b,c?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> a+b = 20*2 = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> c+b = 19*2 = 38</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a+c = 21*2 = 42</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2(a+b+c) = 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a+b+c = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a+b = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> c= 20 a =22 b =18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">35 students in a hostel if no of students increases by 7 the expenses of the hostel increased by 42 rs perday while the average expenditure per head decreases by 1 find the original</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">expenditure of the hostel?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> no avgexp totalexp</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 35 x = 35x</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 42 (x-1) = 42(x-1)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 35x+42 = 42(x-1)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 75x = 42(x-1)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7x = 84</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x =12 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 35x = 35*12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS TOTAL AVERAGE OF 20 STUDENTS IS 12 YEARS AFTER ADDING TEACHER AGE THEIR AVERAGE INCREASED BY 2 YEARS THEN FIND TEACHER AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CASE 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> N = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL = 20*12</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 240</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">CASE 2:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> N = 20+1 = 21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AVERAGE = 12+2 = 14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL = 14*12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 294</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TEACHER AGE = 294</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 240</span></p><p><span style="font-size: large;"> ..........</span></p><p><span style="font-size: large;"> 54 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> METHOD 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12 + (21*2)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 12+42</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 54 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">30 MEMBERS AVERAGE AGE IS 16 YEARS AFER ADDING TEACHER AGE TOTAL AVERAGE INCREASED BY 1 YEAR THEN</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND TEACHER AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> N =30 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AVERAGE = 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30*16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 480</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CASE : 31</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AVG = 17</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 31*17</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">TEACHER AGE = (31*17) - 480</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 47</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">15 MATCHES BATSBAN AVERAGE SCORE IS 35 RUNS THEN HOW MANY RUNS HE HAS TO SCORE IN IN HIS NEXT MATCH</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THERE BY HIS AVG TO INCREASE 3 RUNS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 35 + (16 MATCHES * 3 )</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 35+48</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 83 RUNS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 11 MEMBERS AVERAGE WEIGHT 80 KGS AFTER ADDING COACH AGE AVERAGE DECREASED BY 2 KGS THEN FIND COACH AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 80- (12*2)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80-24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 YEARS BACK A,B,C,D AVERAGE AGE 44 YEARS 2 YEARS BACK C DIED NOW PRESENT AVERAGE OF A,B,D IS 48 YEARS THEN FIND C AGE AT THE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">TIME OF HIS DEATH?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">CASE 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 YEARS BACK = 44*4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 176</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A+B+D = 48*3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 144</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRESENT C = 200-144</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 56 YEARS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 YEARS BACK = 56 -2 =54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 YEARS BACK AVERAGE AGE OF A 3 FAMILY MEMBERS IS 14 YEARS IN THESE DAYS ONE BABY BORN THEREBY NO CHANG </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN AVERAGE OF THEIR AGES THEN FIND BABY AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CASEI</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 YEARS BACK:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AVERAGE : 14 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL = 14*3 = 42</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">CASE 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">NOW :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PEOPLE TOTAL = 42+12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRESENT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 MEMBERS AVG = 14*4 = 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> BABY AGE = 56-54= 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3 YEARS BACK IN A FAMILY 5 MEMBERS AVERAGE IS 17 YEARS IN THESE DAYS ONE BABY BORN THEREBY</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">NO CHANG IN THEIR AVERAGE THEN FIND BABY AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> CASE 1:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 YEARS BACK 5*17</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 85</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT 85+15 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">6 PEOPLE AVE = 17</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 17*6 = 102 YEARS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> BABY AGE = 102 - 100 = 2 YEARS</span></p><p><span style="font-size: large;"> RATION AND PROPORTIONS</span></p><p><span style="font-size: large;"> .......................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Ratio is comparison between two or more quantitys having same units</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">any ratio does not have units</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">the general form to represent a ratio is a : b or a/b</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a : anticipate</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">b : consequent</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">NOTE: Ka : Kb</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2 : 3 = 10 : 15 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">K = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Model 1 : </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1. An amount of rs 500 is shared between a,b,c in the ratio 2 : 3: 5 find the share of each person?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A : B : C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2: 3 :5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2X : 3X : 5X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">TOTAL = 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2x+3x+5x = 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">10 x = 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">x = 50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2x = 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3x = 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5x = 250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2nd method :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A : B : C </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A= 2/10(500) = 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">B = 3/10 (500) = 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">C = 5/10 (500) = 250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3rd method</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2 : 3 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">100 150 250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">10 parts = 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1 part = 50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2 )An amount of rs 600 is shared between a,b,c in the ratio 3 : 4: 5 find the share of each person?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ans </span></p><p><span style="font-size: large;"> 3/12(600) = 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4/12(600) = 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5/12(600) = 250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3) A and b are in the ratio 3 : 5 difference between their ages is 12 years find the sum :?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5parts - 3parts = 2parts</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2parts = 12 years</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1 part = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3parts *6 = 18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5parts * 6 = 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">total = 18 +30 = 48</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4) A and b are in the ratio 3 : 4 square of their ages is 225 years then find sum of their ages?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(3x)(3x) +(4x)(4x) = 225</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(25x)2= 225</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">x= 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5) in a school boys and girls are in the ratio 6 : 5 then find the total number of studens?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a)33</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> b) 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> c) 37</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">6x +5x =11x </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">so eleven multiple is 33</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ans : 33</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Method 2 :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">in a school boys and girls are in the ratio 2 : 3 then find the total number of studens?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ans :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 42 44 45 47</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7) in a class there are 60 students which of the following can not be ration between boys and girls?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a: 2 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">b) 5 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">c) 7 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">d) 5 : 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 2:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">method 1 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B = (2:3 )4 = 8 :12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B :C = (4 :5 )3 = 12 : 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B :C = 8 :12 :15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">METHOD 2 : </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a : b = 2:3 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">b :c = 4 :5 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ans : 2*4 + 3 *4 +3*5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8 :12 :15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">..............................................</span></p><p><span style="font-size: large;">eg : </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a: b = 3 :5 b : c = 4 :7 then a : b :c </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12 : 20 :35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B = 4 :5 B : C =7 :9 THEN A :B :C </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 28 : 35 : 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B = 2 :3 b :c =4:5 c :d = 2:1 then</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a :b c : d =</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4 :5 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a : 2 * 4 * 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">b = 3 * 4 * 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">c = 3 * 5 *2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">d = 3 * 5 * 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">eg :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a : b = 2 : 5 b : c = 2 :3 c :d = 5 :4 d : e = 7 :3 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">then a : e?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 3 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">In a vessel milk and water are in the ratio 5 : 2 if 6 leters of water is added then the ratio 5 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">find the quality of the milk ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5-2 = 1part</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1 part = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5parts = 5*6 = 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">eg:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">milk and water are in the ratio 7 :5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">if 20 liters of water is added then ratio 1 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1: 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">multiple (1:1) with 7 = 7 : 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7 : 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2p = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">p = 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7*10 = 70</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">eg:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">In a class boys and girls are in the ratio 3 :2 if 20 girls newly joined in the class then the ratio 2 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">find the intial no of students?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3 , 2 lcm 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2(3 :2 ) = 6 :4 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3(2 :3 ) = 6 :9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5p =20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">p = 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">6 * 4 = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4 *4 =16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">24 +16 =40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">In a solution salt and water there is 75 % of salt if 5 liters of water there is 80 % of salt find the initial quality of that solution</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">75 %</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 75 : 25 80 : 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3 : 1 4 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3 , 4 lcm 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">12 :4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">12 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1p = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">16 part = 16 * 5 = 80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 4 :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Eg :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a : (b+c) = 3 : 5 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> b : (c+a) = 1 :7 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">then a : b : c </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1st cond = 3 +5 = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2nd cond = 1+7 = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">total 8 parts</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a = 3 b = 1 c = 8-4 = 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Eg : </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a : (b +c ) = 3 : 7 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> b : (c+a) = 1 :4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a : b : c </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1st cond 3 +7 = 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2nd cond 1+4 = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">multiple 2nd cond with 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3 :7 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2 :8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3 : 2 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Eg :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a : (b+c) = 2 :5 b : (c +a) = 1 :3 then a :b :c </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7 *4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4 *7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(2 :5 ) 4 = 8 :20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(1:3)b 7 = 7 :21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a : b : c 8: 7 :13 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">total = 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a+b = 15 c = 13</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 5 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Three equal capacity vassel contains milk and water in the ratio 3 :1 , 5 :3,7:5 if they are mixed in a baig container find the new ratio?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> m w</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (3 :1 )6 =18 :6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5 :3 ) 3 = 15 :9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (7 :5 )2 = 14 :10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ............</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 47 : 25</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Eg:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">the equal capacity vassel contains milk and water in the ratio 3 :2, 7 :3, 8:7 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">if they are mix in a big container fine new ratio?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(3 :2 )6 = 18 :12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(7 :3)3 = 21 :9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(8:7)2 = 16 :14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ...............</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 55 :35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 11 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Eg</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">two vessels contains milk and water in the ratio 3 ;1 and 5 ;3 respectivily if they mixed in the proportion 3 :4 then find new ratio?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(3 :2 ) 2 (6 :2)3 = 18 :6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5 :3 (5 : 3)4 = 20 :12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> .............</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 38 :18</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 19 :9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 6 :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><br /></p>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-51354201323659865802021-06-16T05:27:00.000-07:002021-06-28T02:44:37.017-07:00 PROBLEMS ON NUMBERS PARTNERSHIPS ARTHMETIC MATERIAL<h1 style="text-align: left;"><span style="font-size: large;"> PROBLEMS ON NUMBERS PARTNERSHIPS ARTHMETIC MATERIAL</span></h1><h2 style="text-align: left;"><span style="font-size: large;"> PROBLEMS ON NUMBERS</span></h2><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/3) OF (2/5) OF A NUMBER IS 24 THEN FIND THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/3)* (2/5) *X = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = (24 *3*5)/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> = 180</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> IF x2 = 25 FIND X?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x2-25 = 0</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X+5)(X-5)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X=-5 OR X= +5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IF (1/6)TH OF (3/7) OF A NUMBER IS 21 WHAT IS 30% OF THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/6)*(3/7)*X = 21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = (21*6*7)/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> = 88.2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> WHEN 14 IS ADDED TO A NUMBER IT BECOMES (5/4) TH OF ORIGINAL NUMBER WHAT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IS 25% OF THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+14 = (5/4) X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4X+56 = 5X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25% of (56)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A NUMBER CAN DIVIDED BY 4 THEN IT REDUCED BY 21 FIND THE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X REDUCED BY MEAN X-21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X-(X/4)) = 21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3X/4 = 21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A NUMBER WHEN DIVIDED BY 4 IT REDUCED TO 21 FIND THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X/4 = 21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X = 84</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A NUMBER EXCEEDS 20% OF ITSELF BY 40 FIND THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X-(20%)X = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X-(X/5) = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4X = 200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X= 50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A NUMBER IS 68% OF OTHER NUMBER IF THE SUM OF THOSE TWO NUMBERS IS 84% OF 500 FIND THE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">LARGER NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%X + 68%X= 84%OF 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X =250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF 3 CONSICUTIVE EVEN NUMBERS IS 108 WHAT WILL BE THE MIBBLE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+X+2+X+4 = 108</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3X+6 = 108</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3x = 108</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 34 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MIDDLE NUMBER = 34+2 = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF 3 CONSICUTIVE NUMBERS IS 27 WHAT IS SQUARE OF MIDDLE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+X+1+X+2 = 27</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MIDDLE NUMBER = X SQUARE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">RAMU WAS ASKED TO DIVIDE A NUMBER BY 5 BUT WRONGLY MULTIPLIED THE NUMBER WITH 5 HIS ANSWER IS 144</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MORE THAN THE CORRECT ANSWER WHAT WAS CORRECT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X/5) 5X </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5X-(X/5)) = 144</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X = 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X/5 =30/5 = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A NUMBER WHEN MULTIPLIED BY 17 IT INCREASED BY 96 FIND THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X(17) = X+96</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16X = 96</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X =6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EX:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHEN 84 IS ADDED TO A NUMBER THE NEW NUMBER BECOMES 400% OF ORIGINAL NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X+84 = X(400/100)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3X = 84</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A NUMBER IS AS MUCH GREATERTHAN 65 AS IS LESSTHAN 105 FIND THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 65< X < 105</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 85</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X-65 = 105=X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X = 170</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X =85</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3 NUMBERS ARE IN THE RATIO 4 : 5 :6 AND THE AVERAGE IS 25 FIND THE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (4X+5X+6X)/3 = 25</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15X = 25*3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 5 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5*5) (6*5)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2 NUMBERS ARE SUCHTTHAT THE RATIO BETWEEN 4:7 IF EACH NUMBER INCREASED BY 4 THE RATIO BECOMES 3:5 FIND THE LARGER NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4X+4 = 3</span></p><p><span style="font-size: large;"> ....... ...</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7X+4 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20X+20 = 21X+12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7X = 7*8 = 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF TWO NUMBERS IS 22 FIVE TIMES OF ONE NUMBER IS 6 TIMES OF OTHER NUMBER FIND THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5X = 6Y</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X/Y = 6/5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X= 6Y/5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (6Y/5) + Y = 22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> Y = 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X =12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF THREE NUMBERS IS 264 IF THE FIRST NUMBER IS TWICE THE SECOND AND THIRD NUMBER IS 1/3RD OF FIRST </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND THE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X+X+(2X)(1/3) = 264</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3X+ (2X/3) = 264</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9X +2X = 264 *3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 11X = 264 *3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 72</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2ND METHOD:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X : Y : Z</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 : 3 : 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 11P = 264</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = 72</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF THE NUMANATOR AND DENOMINATOR ARE INCREASED BY 20% AND 30% RESPECTIVILY THE FRACTION BECOMES 9/13 WHAT WAS THE ORIGINAL FRACTION?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100X +20x) = 9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ............. ...</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100Y+30X) 13</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12X/13Y = 9/13</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X/Y = 9/12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IF 20% OF THE NUMANATOR AND 30% OF THE DENOMINATOR IS TAKEN THEN NEW FRACTION BECOMES 7/9 FIND THE ORIGINAL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FRACTION?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20%X)/(30%Y) = (7/9)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (2X/3Y) = (7/9)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X/Y =(7/9)(3/2)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X = 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ..... ....</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> Y 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A 2 DIGIT NUMBER THE DIGITS IN UNIT PRICE IS TWO TIMES MORE THAN THREE OF DIGIT IN THE TENS PLACE IF THE SUM OF TWO DIGITS IS 6 FIND THE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> Y = 2+3X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+3X+2 = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4X =4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> Y = 6-1 = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF THE DIGITS OF A TWO DIGIT NUMBER IS 8 IF THE DIGITS ARE REVERSED THE NUMBER IS DECREASED BY 54 FIND THE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+Y = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TWO DIGTI NUMBER = 10X+Y 10Y +X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (10X+Y) - (10Y-X) = 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9X - 9Y = 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X-Y = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X +Y = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE DIFFERENCE BETWEEN TWO DIGIT NUMBER AND THE NUMBER OBTAINED AFTER INTERCHANGING 2 DIGITS IS 27</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF THE SUM OF THE TWO DIGITS IS 15 WHAT IS THE TWO DIGIT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ORIGINAL = 10X+Y</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> REVERSE = 10y+X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (10X+Y)-(10Y-X) = 27</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (10Y+X)-(10X+Y) = 27</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X-Y = 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+Y = 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 96 OR 69</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE DIFFERENCE NBETWEEN THE TWO DIGTI NUMBER AND THE NUMBER OBTAINED BY INTERCHANGING THE TWO</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">DIGIT IS 18 THE SUM OF THE TWO DIGITS OF A NUMBER IS 12 WHAT IS THE PRODUCT OF THE DIGITS OF TWO DIGIT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X-Y) OR (X+Y) = 18/9 =2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X+Y = 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X-Y = 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X = 14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X =7 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7-2 =5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRODUCT = 5*7 = 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF THE SQUARES OF TWO DIGIT IS 80 AND THE SQUARE OF DIFFERENCE IS 36 FIND THE PRODUCT OF TWO NUMBERS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X-Y)(X-Y) = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x^2 +y^2 = 80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80-2XY = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> XY = 22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> THE DIFFERENCE OF TWO NUMBERS IS 5 AND THE DIFFERENCE OF SQUARE IS 135 FIND THE SUM OF THE SUMBERS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X-Y = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x^2-y^2= 135</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X+Y)(X-Y) = 135</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 135/5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 27</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+Y = 27</span></p><p><span style="font-size: large;"> ........ ...</span></p><p><span style="font-size: large;"> X-Y 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 32</span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF TWO NUMBERS IS 29 AND THE DIFFERENCE OF THE SQUARE IS 145 FIND THE DIFFERENCE BETWEEN THE NUMBERS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+Y = 29</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x^2 -y^2 = 145</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X+Y)(X-y) = 145</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X-Y) = 145/29 = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A NUMBER WHEN INCREASED BY 20% GIVES 720 FIND THE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100X + 20X = 720</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 120X = 720</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100X = 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHEN 60 IS ADDED TO 60% OF A NUMBER THE RESULT IS THE NUMBER ITSELF FIND THE NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60+(60%X) = 100%X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40%X = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X =150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHEN 75 IS ADDED TO 75% OF A NUMBER THE RESULT IS 125% OF THAT ORIGINAL NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 75 +75%X = 125%X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 75 = 50%X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%X = 150</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE PRODUCT OF TWO NUMBERS IS 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF THEIR SQUARE IS 289</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND THE SUM OF THE TWO NUMBERS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> XY - 120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x^2 +y^2 =289</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x^2 +y^2+2XY = 289 +2XY</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x^2 +y^2 = 289+2*120</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x^2 +y^2 = 529</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X-Y = 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+Y =23</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X= 15 Y = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THERE ARE TWO NUMBERS SUCHTHAT THE SUM OF TWICE THE FIRST AND THRICE THE SECOND IS 39 BY THE SUM OF THRICE THE FIRST AND TWICE THE SECOND IS 36 FIND THE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">LARGER OF THE TWO NUMBERS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3Y+2X = 39</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2Y+3X = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> Y =9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SHANKAR GETS 3 MARKS IN EXAMINATION FOR EACH CORRECT ANSWER 2 MARKS FOR EACH WRONG ANSWER HE ATTEMPTS ALL THE 30 QUESTIONS AND SCORED 40 MARKS FIND THE NUMBER</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF HIS CORRECT ANSWERS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> NO OF QUESTIONS EQUATON = X+Y = 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3X-2Y = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2(X+Y) = 30*2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X =100/5 =20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> PARTNERSHIPS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> partnership</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> simple compound</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">partnership:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">if two are more persons invests certain capital in a business then the deal is called partnership</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">there are two types of partnerships</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">simple</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">compound</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">simple:</span></p><p><span style="font-size: large;">.......</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">if the capitals are invested for the same period then the partnership is called simple</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">partnership in this case profits must be divided in the ratio of their investments</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> inv ratio a : b</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> profit ratio a : b</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> p1 : p2 = i1 : i2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">compound :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">if the capatals are invested for different time period then it is called compoundpartnership</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">in this case profits must be divided in the ratio of the products</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">of respective investments and time periods</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> pr= i1t1 = i2t2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">profits can also can be devided in the products form of ratio of investments and time perios</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> I1TI/I2T2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (I1/I2)*(T1/T2)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A INVESTED 10000 AND B INVESTED 15000 RESPECTIVILY FIND THE SHARE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF A IN THE ANNUAL PROFIT OF 40000?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 10000 : 15000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A INVESTMENT (2/5)40000 = 16000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A ,B INVESTED 8000 AND B INVESTED 12000 RESPECTIVILY FIND THE SHARE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF B IN THE ANNUAL PROFIT OF 25000?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8000 : 12000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8 : 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B INVESTMENT = (3/5)*25000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A ,B,C INVESTED 20000 AND B INVESTED 30000 C INVESTED 40000 </span></p><p><span style="font-size: large;">RESPECTIVILY THEN FIND C SHARE IS HOW MUCH MORE THAN A IN THE ANNUAL PROFIT OF 45000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A : B : C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20 30 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (4-2)/9 = 2/9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (2/9)*45000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A 10000 FS FOR 4 MONTHS B INVESTED 12000 RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> FIND THE SHARE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF A IN THE ANNUAL PROFIT OF 30000?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10*4 : 12*5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> I1TI :I2T2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE (2/5)30000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A INVESTED 10000 AND B INVESTED 15000 RESPECTIVILY SFTER 6 MONTHS B LEFT THE BUSINESS</span></p><p><span style="font-size: large;">THEY GOT A ANNUAL PROFIT OF 35OOO THEN FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> I1T1 :I1T2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10*12 : 15*16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE : (4/7) *35000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A AND B STARTED A BUSINESS WITH CAPTITAL OF 30000 AND 20000 AFTER 10 MONTHS A LEFT THE BUSINESS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER ONE AND HALF YEAR THEY GOT A ANNUAL PROFIT OF 44000 THEN FIND B SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20 *10 : 20 *18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 :6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">B SHARE (44000) (6/11)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A AND B STARTED A BUSINESS WITH CAPTITAL OF 20000 AND 30000 AFTER 6 MONTHS B LEFT THE BUSINESS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AT TIME SAME TIME C JOINED WITH CAPITAL WITH A AMOUNT OF 40000 THEY GOT A ANNUAL PROFIT OF 60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B :C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20*12 :30 *6 : 40*6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 :3 :4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE (4/11)*66000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A AND B STARTED A BUSINESS WITH CAPTITAL OF 8000 AND 12000 AFTER 6 MONTHS B LEFT THE BUSINESS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 2 MONTHS C JOINED WITHA CAPITAL OF 18000 RS THEN THEY GOT THE ANNUAL PROFIT OF 60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND B SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B :C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8*12 : 12*16 : 18*14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 :3 :3 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B SHARE : (3/10)* 60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A STARTED A BUSINESS WITH A CAPITAL OF 20000 AFTER 4 MONTHS B JOINED WITH A CAPITAL OF 30000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ATER ONE YEAR THEY GOT ANNUAL PROFIT OF 50000 FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30*12 :30*8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1:1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/2)*50000</span></p><p><span style="font-size: large;"> 25000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A STARTED A BUSINESS WITH A CAPITAL OF 10000 AFTER ONE YEAR B JOINED WITH A CAPITAL OF 18000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 6 MONTHS C JOINED WITH 20000 THEY GOT A PROFIT OF 80000 IN 3 YEARS FIND A SHARE ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10*36 : 18*24 : 18*20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5 6 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5/16(80000) </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A, B INVESTMENTS RATIO 5 : 3 THEIR INVESTMENT TIMES RATIO 9 :10 IN WHICH RATIO THEY</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WILL DISTIBUTE THEIR SHARES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5*9 : 3*10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 45 : 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 : 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A INVESTMENT IS 3 TIMES TO B'S INVESTMENT </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A INVESTMENT TIME IS DOUBLE TO B'S INVESTMENT TIME THEN THEY GOT A PROFIT OF 21000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND A SHARE ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1*3 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2*1 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B : 6 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A PFOFIT : </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (6/7)*21000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A INVESTMENT IS DOUBLE TO B INVESTMENT B INVESTMENT IS 3 TIMES TO C INVESTMENT THEN THEY GOT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PROFIT OF 6000 FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B : C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2*3*1 3*1 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 3 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A SHARE (6/10)60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 36000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B STARED A BUSINESS A INVESTED 20000 RS IF THE PROFITS AT THE END OF THE YEAR IN THE RATIO 4 : 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND B INVESTMENT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20000 : X = 4 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X = (20000*7)/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 35000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A STARTED A BUSINESS WITH A CAPITAL OF 15000 AFTER 3 MONTHS B JOINED PROFITS AT THE END OF THE YEAR DISTIBUTED EQUALLY</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND B SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15000 * 12 : 9*12 = 1 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9X = (15000*12)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A STARTED A BUSINESS WITH A CAPITAL OF 30000 AFTER SOME TIME B JOINED WITH A CAPITAL OF 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFITS AT THE END OF THE YEAR DISTIBUTED IN THE RATIO 2 : 1 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND HOW MANY MONTHS LATER B JOINED IN THE BUSINESS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 30*12 : 20 *X = 2 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X = (30*12)/(20*12)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 MONTHS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> HOW MANY MONTHS LATER B JOINED = 12 -9 = 3 MONTHS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A STARTED A BUSINESS WITH A CAPITAL OF 20000 AFTER SOMETIME B JOINED WITH 10000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A YEAR A'S SHARE IS 3/4 OF TOTAL PROFIT THEN FTER HOW MUCH TIME LATER B JOINED IN THE BUSINESS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 20000*12 10000*X = 3 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X = (20000*12)/(10000*3)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> = 12-4 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A AND B STARTED A BUSINESS WITH 10000 AND 15000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">15 % OF THEIR PROFIT GOES TO CHARITY THEN THEY GOT ANNUAL PROFIT OF 40000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 : 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">REMAINING AMOUNT AFER GIVING TO CHARITY = (40000)*(85/100)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 34000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (34000)(2/5)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 13600 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A AND B STARTED A BUSINESS WITH 15000 AND 21000 RESPECTIVILY 20% OF THEIR PFOFIT SHARE GOES TO CHARITY </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER ONE YEAR THEY GOT A PROFIT OF 60000 THEN FIND B SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (60000)*(80/100)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 48000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15 : 21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 : 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B SHARE : (48000)(7/21)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 28000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A , B STARTED HEIR BUSINESS WITH 8000,12000 RESPECTIVILY THEY DONATED 10% OF THEIR PFOFIT TO </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">CAHRITY AFTER ONE YEAR A SHARE 5400 THEN FIND TOTAL PROFIT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8 :12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A SHARE 2 -------5400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B SHARE 3 .......8100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL SHARES = 5400 +8100 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 13500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL PROFIT :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90% ----------- 13500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%..............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (100*13500)/90</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B STARTED A BUSINESS WITH 20000,30000 RESPECTIVILY B IS A SLEEPING PARTNER</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SO A GOT 20% OF THEIR PROFIT AS SALARY</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER ONE YEAR THEY GOT A PROFIT OF 40000 THEN A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20 : 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A SALARY 8 THOUSAND</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (40000*(80/100))</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 32000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN A SHARE = (2/5)*(32000)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A TOTAL SHARE = 8000+12800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B STARTED A BUSINESS WITH 15000 AND 25000 RESPECTIVILY B IS A SLEEPINGPARTNER IN THAT BUSINESS AFTER ONE YEAR</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A AND B GOT PROFIT OF 30000 THEN FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15 : 25</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B 5 -------30000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A 3 ...... 18000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A = 30000-18000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A AND INVESTED 25000 AND 40000 RESPECTIVILY IN THAT B IS A SLEEPING PARTNER AFTER ONE YEAR A AND B GOT A PROFIT </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF 48000 THEN FIND A S MONTHLY SALARY?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> *6</span></p><p><span style="font-size: large;"> B ----- 8 ------- 48000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A.... 5.....*6.... 30000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A'S SALARY = 48000 -30000 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A'S MONTHLYSALARY = 18000/12 = 1500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A, B STARTED A BUSINESS WITH 10000,15000 AFTER 6 MONTHS A INVESTED 5 THOUSAND RUPEEES</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A YEAR THEY GOT A PROFIT OF 44000 THEN FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (10*6)+ (15*6) : 15*12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25 :30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 :6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE : (5/11)*44000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B STARTED A BUSINESS WITH 20000 AND 30000 AFTER 6 MONTHS A INVESTED 10000 MORE AND B ALSO INVESTED</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5000 MORE IN A YEAR THEY GOT PROFIT OF 69000 THEN FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20*6 + 30*6 : 30*6 + 35*6)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 : 13</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE : (10/23) * 69000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B STARTED A BUSINESS WITH 8000 AND 12000 AFTER 6 MONTHS A INVESTED 4000 MORE BUT B WITHDRAN 2000 RS THEY GOT ANNUAL INCOME OF 84000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (8*6 +12*6 ) : (12*6 +10*6)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 : 11</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (12000-2000)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE (10/12)*84000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN BUSINESS A,B INVESTMENT RATIO IS 4 :5 AFTER 6 MONTHS A INVESTED HALF OF THE INITIAL INVESTMENT </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AGAIN BUT B B WITHDRAW (1/5)TH OF HIS INVESTMENT THEN FIND AFTER ONE YEAR THEY HAVE TO DISTRUBUTE THEY AMONT IN</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEIR PROFITS WHICH RATIO?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B 5 - 5*(1/5)</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5-1 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> HLF OF THE 4 = 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4+2 =6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4*6 + 6*6 : 5*6 +4*6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 :9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A,B INVESTED IN THE RATIO 5 :8 AFTER 6 MONTHS A INVESTED 20% EXTRA BUT B WITHDRAW 25% AFTER ONE YEAR THEY GOT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PROFIT OF 50000 THEN FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5*6+6*6 : 8*6+6*6 = 11:14 5(20/100) = 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5+1 =6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8*(25/100) = 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8-2 = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE (11/25)*50000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 22000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A , B AND C INVESTED 35000 RS A INVESTED 3000 MORE THAN B B INVESTED 4000 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MORE THAN C THEN IN WHICH RATIO THEY WILL DISTRIBUTE THEIR SHARES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C = X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B = X+4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A = X+7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X +X+4+X+7 = 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B : C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15 : 12 : 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A INVESTED 1/3RD AMOUNT IN 1/3RD TIME</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">B INVESTED 1/4TH IN 1/4TH TIME </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">C INVESTED REMAINING AMOUNT TOTAL TIME THEN THEY GOT PROFIT OF 34000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND A SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B : C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/3)(1/3) : (1/4)(1/4) :(5/12*1)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C INVESTMENT = (1/3)+(1/4)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7/12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1-(7/12)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5/12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/9) (1/16) (5/12)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16: 9:60</span></p><p><span style="font-size: large;"> ............</span></p><p><span style="font-size: large;"> 144</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 16 : 9 :60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE = (16/85)*34000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B,C INVESTED 32000,36000,AND 46 THOUSAND IN A BUSINESS FIND THE SHARE OF B IN THE ANNUAL </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PROFIT OF 11400?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 32 : 36 : 46</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 16 : 18 : 23</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 57</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (18/57)*11400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3600</span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A B AND C INVESTED 40000 AND 64000 AND 72000 IN A BUSINESS IF A RECEIVES 24000 RS LESSTHAN </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">C AS HE SHARE IN THE ANNUAL PROFIT WHAT IS THE SHARE OF B?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40 64 72</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT C -A = 24000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B = ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 : 8 : 9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C-A = 9-5 = 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 ----------24000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8 ..........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (8*24000)/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 48000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS P CONTRIBUTES 45000 FOR 5 MONTHS Q 60000 FOR 5 MONTHS R CONTRIBUTES 80000 FOR 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MONTHS WHAT IS THE SHARE OF Q IN THE TOTAL 134000?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 45000*5 : 60000*5 : 80000*6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15 20 32</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 13400*(20/67)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SRINIVAS BEGAN A BUSINESS WITH 13000 AFTER 4 MONTHS SRIDHAR JOINED WITH A CERTAIN CAPTAIL AT THE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">END OF THE YEAR THPROFITS WERE DIVIDED IN THE RTIO 5 : 2 HOW MUCH DID SRIDHAR INVEST?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P1/P2 = (I1/I2)*(T1/T2) 13000 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5/2 = (13000/X)/(12/8) 12 : X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X = (13000*12*2)/(5*8)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A BEGAN A BUSINESS WITH 45000 AND WAS LATER JOINED BY B WITH 54000 AFTER HOW MANY MONTHS B JOINED IF THE PROFITS AT THE END OF THE YEAR</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ARE DIVIDED IN THE RATIO 2 : 1?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (2/1) = (45000/54000)/(12/(12-X)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12-X = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A AND B PARTNERS IN A BUSINESS A CONTRIBUTES 1/4 OF THE CAPTIAL FOR 15 MONTHS AND B RECEIVED 2/3OF THE PROFIT FIND FOR HOW LONG B'S </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MONEY WAS INVESTED?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> P = IT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> INV 1/4 3/4 = 1 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TIME 15 X = 15 : X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT 1/3 2/3 = 1 : 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1/2 = (1/15)(15/X)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X = 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">RAM INVESTED 1/3 RD OF THE THE CAPTIAL FOR 1/4TH TIME</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">KRISHNA INVESTED 1/5 TH OF THE CAPITAL FOR 1/2 TIME</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AND RAHIM INVESTED REMAINING CAPITAL FOR WHOLE TIME WHAT IS THE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SHARE OF RAM IN THE TOTAL ANNUAL PROFIT OF 78000?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> INV 1/3 1/5 1/15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TIME 1/4 1/2 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ( 1/12 1/10 1/15)60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 6 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 39..............78000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 ..................?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A JOINT VENTURE A,B AND C INVESTED 1/4TH OF THE CAPITAL 1/5 TH OF THE CAPITAL AND THE RESPECTIVILY FIND THE SHARE OF B IN THE TOTAL </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PROFIT OF 600000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1/4 1/5 11/20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 4 11 1-(9/20) = 11/20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20.............600000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 .................?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20..............600000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 .............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25 20 C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 55%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B AND C INVESTED A TOTAL SUM OF 10000000 IN A BUSINESS A INVESTS 3000000 MORE THAN C B INVEST </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">10000000 MORE THAN C THEN FINE THE SHAR EOF C OUT OF TOTAL PROFIT </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF 20 LACK RUPEES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30+C 10+C C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3C+4000000 = 1000000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C = 60/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B= 10+20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30/100(20000)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B,C PURCHASED A FIRM FOR 10000000 RS OF WHICH A PAYS 400000 RS A SELL IT SOAS TO GAIN CERTAIN SUM OF </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHICH B GETS 2,75000 AND C GETS 175000 RS FIND A'S SHARE IN THE PROFIT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4L 6L</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3..........4.5L</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2.........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (2*4.5L)/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 3L</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS THE INVESTMENTS OF A AND B ARE IN THE RATIO 3 :2 IF 10% OF THE TOTAL </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PROFIT GOES TO CHARITY AND A RECEIVED FINALLY 8100 RS FIND THE PROFIT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A : B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90%A = 8100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%A = 9000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 .........9000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 ...........6000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ..........</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A ANB B INVESTS 5,6 LACK IN BUSINESS A RECEIVES 25% OF THE PROFIT AS SALARY AND BALANCE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IS DIVIDED IF THE TOTAL PROFIT ARE 44000 RS FIND THE TOTAL ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL PROFIT 44000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25% OF PROFIT 11000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL PROFIT - A PROFIT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 44000 - 11000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 33000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 : 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 11P .........33000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 .............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15000 +11000= 26000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">X AND Y STARTED A BUSINESS WITH CAPITALS 20K AND 25K AFTER FEW MONTHS Z JOINED THEM WITH CAPITAL OF 30 THOUSAND</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF THE SHARE OF Z IN THE ANNUAL PROFIT OF 50000 RS IS 14000 RS THEN AFTER HOW MANY DAYS FROM THE BEGINING Z JOINED?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X Y Z</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20 25 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12 12 (12-X)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ..............................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 48 10 6(12-X)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18 (12-X)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2(12-X) = 14000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG//;</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A, B,C INVESTED 20000,30000,AND 50000 IN A BUSINESS IN A YEAR THEY GOT PFOFIT OF 60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> FIND EACH ONE SHARE ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B : C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20000 30000 50000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 PARTS ------------60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART.............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12000 18000 30000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A INVESTED 1/3RD AND B INVESTED 1/4TH C INVESTED REMAINING AMOUNT TOTAL PROFIT 60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND C SHARE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 - ((1/3)+(1/4))</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (4+3)/12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1-7/12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5/12)*60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE 1/3(60000) = 20000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B SHARE 1/4(60000) = 15000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A +B = 35000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> C = 60000-35000 = 25000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 2 :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = IT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN THE ABOVE RULT ONLY FOR TO FIND RATIOS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A STARTED ONE BUSINESS WITH 20000 AFTER 3 MONTHS B JOINED WITH 40000 AFTER 3 MONTHS C JOINED WITH</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">60000 THEN FIND THEIR ANNUAL PROFIT IN WHICH RATIO?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20000 40000 60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 2 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TIME 12M 9M 6M</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 3 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT 1*4 2*3 3*2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 6 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 3 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A INVESTED 1/3RD AMOUNT 1/3RD TIME </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">B INVESTED 1/6TH AMOUNT 1/6TH TIME C INVESTED REMAINING AMOUNT WHOLE TIME FIND </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">TOTAL PROFIT IN WHICH RATIO?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL INVESTMENT 6 PARTS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> INVESTMENT 2 1 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TIME 2 1 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT 4 1 18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG: </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A BUSINESS A,B,C INVESTED TIME 1 : 2 : 3 THEY PROFIT RATIO 2 : 3 : 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A S INVESTMENT IS 60000 RS FIND C INVESTMENT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> INVESTMENT = (PROFIT/TIME)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (2 : 3 : 4/1 : 2 : 3)6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12 : 9 :8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (8/12)*60000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A STARTED A BUSINESS WITH 30000 THEN B JOINED WITH 40000 THEIR PFOFIT SHARE AFTER THE YEAR IS EQUAL </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND HOW MANY MONTHS LATER B JOINED?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30000 40000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> INVESTMENT 3 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PROFIT 1 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TIME 1/3 : 1/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12M 9M</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> B JOINED 3 MONTHS LATER</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 3 :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B STARTED A BUSINESS WITH 20000 RS AND 30000 RS AFTER 4 MONTHS A INVESTED 5000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">B REMOVED 5000 FROM HIS INVESTMENT THEN IN WHICH RATIO THEY WILL DISTRIBUTE THEIR </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ANNUAL INCOME?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2000*4 3000*4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30000*8 2500*8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 +10 : 6 +10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 14 : 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 : 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A,B,C STARTED A BUSINESS WITH 20000 RS AND 30000 RS AND 40000 RS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 3 MONTHS A INVESTED 10000 RS B WITHDRAW 10000 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">C NOT IN A BUSINESS AFTER 6 MONTHS THEN FIND THE RATIO OF THE ANNUAL PROFITS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A B C</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20000*3 30000*3 40000*6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> + + +</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30000*9 20000*9 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 11 9 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A AND B STRTED A BUSINESS WITH 30000 AND 50000 RS B IS A SLEEPING PARTNER SO A GOT 20% AS SALARY </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FINALLY THEY GOT PROFIT 90000 FIND THEIR SHARES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL PROFIT 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SALARY 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A B</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3000 5000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> REMAINING</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30% 50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A SHARE 30%+20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B SHARE 50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A 45000 B 45000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><div><br /></div>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-58438420140616714232021-06-14T02:31:00.002-07:002021-07-03T23:31:03.857-07:00IMPORTANT INSTRUCTIONS TO ENGINEERING, AGRICULTURE & PHARMACY CANDIDATES<h1 style="text-align: left;"><span style="font-size: large;">IMPORTANT INSTRUCTIONS TO ENGINEERING, AGRICULTURE & PHARMACY CANDIDATES</span></h1><h2 style="text-align: left;"><span style="font-size: large;"> AP EAPCET 2021</span></h2><h3 style="text-align: left;"><span style="font-size: large;">(Engineering, Agriculture and Pharmacy Common Entrance Test Conducted by JNTUK, Kakinada on behalf of APSCHE)</span></h3><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Date of Examination: 19-08-2021 to 25-08-2021</span></p><p><span style="font-size: large;">(9.00 A.M. to 12.00 P.M. & 3.00 P.M to 5.00 P.M)</span></p><p><span style="font-size: large;">INSTRUCTION BOOKLET</span></p><p><span style="font-size: large;">AGRICULTURE AND PHARMACY</span></p><p><span style="font-size: large;">ENGINEERING, AGRICULTURE & PHARMACY COMMON ENTRANCE TEST</span></p><p><span style="font-size: large;">(being conducted on behalf of APSCHE)</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">AGRICULTURE AND PHARMACY</span></p><p><span style="font-size: large;">ENGINEERING, AGRICULTURE & PHARMACY COMMON ENTRANCE TEST</span></p><p><span style="font-size: large;">(being conducted on behalf of APSCHE)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AP EAPCET-2021</span></p><p><span style="font-size: large;">FOR ENTRANCE TEST RELATING TO PROFESSIONAL COURSES IN</span></p><p><span style="font-size: large;"><br /></span></p><head><script data-ad-client="ca-pub-1795821529243874" async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
</head><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A)<span style="white-space: pre;"> </span>B.Sc.(Ag.) / B.Sc.(Hort.) / B.V.Sc. & AH / B.F.Sc. / B.Tech. (FST) / B.Sc. (CA&BM)</span></p><p><span style="font-size: large;">B)<span style="white-space: pre;"> </span>B.Pharm. / B.Tech.(Bio-Technology) (Bi.P.C.)</span></p><p><span style="font-size: large;">C)<span style="white-space: pre;"> </span>Pharm-D (Bi.P.C)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Note: Information about the Entrance test is also available in the Website</span></p><p><span style="font-size: large;">http://www.sche.ap.gov.in/eapcet</span></p><p><span style="font-size: large;">LAST DATES FOR SUBMISSION<span style="white-space: pre;"> </span>OF<span style="white-space: pre;"> </span>ONLINE<span style="white-space: pre;"> </span>APPLICATION</span></p><p><span style="font-size: large;">WITHOUT LATE FEE<span style="white-space: pre;"> </span>25-07-2021</span></p><p><span style="font-size: large;">WITH LATE FEE Rs. 500/-<span style="white-space: pre;"> </span>05-08-2021</span></p><p><span style="font-size: large;">WITH LATE FEE Rs. 1000/-<span style="white-space: pre;"> </span>10-08-2021</span></p><p><span style="font-size: large;">WITH LATE FEE Rs. 5000/-<span style="white-space: pre;"> </span>16-08-2021</span></p><p><span style="font-size: large;">WITH LATE FEE Rs. 10000/-<span style="white-space: pre;"> </span>18-08-2021</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Address for Correspondence:</span></p><p><span style="font-size: large;">CONVENER, AP EAPCET - 2021 GROUND FLOOR, ADMINISTRATIVE BUILDING JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY KAKINADA</span></p><p><span style="font-size: large;">KAKINADA – 533003, ANDHRA PRADESH</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">AP EAPCET - 2021 (AGRICULTURE & PHARMACY)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A Common Entrance Test designated as “Engineering, Agriculture & Pharmacy Common Entrance Test” (AP EAPCET – 2021) will be conducted by JNT University Kakinada, KAKINADA for the academic year 2021-2022 for admission into the First Year of Professional Courses i.e . i) B.Sc.(Ag.) / B.Sc.(Hort.) / B.V.Sc. & AH / B.F.Sc. / B.Tech. (FST) / B.Sc. (CA&BM),ii) B.Pharm / B.Tech. (Bio-Technology) (Bi.P.C.) & iii) Pharm-D (Bi.P.C)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">I.<span style="white-space: pre;"> </span>PARTICULARS OF AP EAPCET – 2021</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>The Test will be conducted during 19-08-2021 to 25-08-2021 in two sessions every day ie 9.00 A.M. to 12.00P.M. and 3.00 P.M to 6.00 P.M during Online Test mode only.</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>The Entrance test is conducted in online (Computer Based Examination) only for a during of 3 hour and the question paper consists of total 160 questions comprising of 80 questions in Biology (Botany-40, Zoology-40), 40 questions in Physics and 40 questions in Chemistry.</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>All questions are of objective type (multiple choice) only and each question carries one mark. The syllabus in Mathematics, Physics and Chemistry is furnished in Annexure-I. The model questions are given in Annexure-II.</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>A sample/mock test will be available on www.sche.ap.gov.in/EAPCET website for practice purpose and to give the candidate look and feel of the On- Line (Computer Based) Examination.</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>ELIGIBILITY TO APPEAR FOR AP EAPCET – 2021</span></p><p><span style="font-size: large;">Candidates satisfying the following requirements shall be eligible to appear for AP EAPCET- 2021:</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>Candidates should be of Indian Nationality or Persons of Indian Origin (PIO) / Overseas Citizen of India (OCI) Card Holders.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>Candidates should belong to the state of Andhra Pradesh / Telangana. The candidates should satisfy Local / Non-Local status requirements as laid down in the Andhra Pradesh / Telangana. Educational Institutions (Regulation of Admission) order, 1974 as subsequently amended (See Annexure III).</span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>For B.V.Sc. & A.H. / B.Sc. (Ag) / B.Sc. (Hort) / B.F.Sc. / B.Tech. (FS&T)courses: Candidates should have passed or appeared for the final year of intermediate examination</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">(10+2 pattern) or any examination recognized as equivalent there to by the Board of Intermediate Education, Andhra Pradesh/ Telangana, with any two / three of the subjects indicated against each course noted below:</span></p><p><span style="font-size: large;">With any two of the subjects:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a) B.Sc.(Ag.)<span style="white-space: pre;"> </span>I.<span style="white-space: pre;"> </span>Physical Science</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>Biological or Natural Sciences</span></p><p><span style="font-size: large;">III.<span style="white-space: pre;"> </span>Agriculture</span></p><p><span style="font-size: large;">IV.<span style="white-space: pre;"> </span>Vocational Course in Agriculture</span></p><p><span style="font-size: large;">b) B.Sc.(Hort<span style="white-space: pre;"> </span>I.<span style="white-space: pre;"> </span>Physical Science</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>Biological or Natural Sciences</span></p><p><span style="font-size: large;">III.<span style="white-space: pre;"> </span>Agriculture</span></p><p><span style="font-size: large;">IV.<span style="white-space: pre;"> </span>Vocational Course in Agriculture</span></p><p><span style="font-size: large;">c) B.V.Sc. & A.H<span style="white-space: pre;"> </span>I.<span style="white-space: pre;"> </span>Physical sciences</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>Biological or Natural Sciences</span></p><p><span style="font-size: large;">III.<span style="white-space: pre;"> </span>Vocational Courses in Veterinary Sciences</span></p><p><span style="font-size: large;">d) B.F.Sc<span style="white-space: pre;"> </span>I.<span style="white-space: pre;"> </span>Physical Sciences</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>Biological or Natural Sciences</span></p><p><span style="font-size: large;">III.<span style="white-space: pre;"> </span>Vocational Courses in Fishery Sciences</span></p><p><span style="font-size: large;">e) B.Tech. (FS & T)<span style="white-space: pre;"> </span>I.<span style="white-space: pre;"> </span>Mathematics</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>Physical Sciences or</span></p><p><span style="font-size: large;">I.<span style="white-space: pre;"> </span>Physical Sciences</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>Biological or Natural sciences</span></p><p><span style="font-size: large;">f) B.Pharmacy & Pharm-D<span style="white-space: pre;"> </span>I.<span style="white-space: pre;"> </span>Mathematics</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>Physical Sciences or</span></p><p><span style="font-size: large;">I.<span style="white-space: pre;"> </span>Physical Sciences</span></p><p><span style="font-size: large;">II.<span style="white-space: pre;"> </span>Biological or Natural sciences</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Note: i) Irrespective of the subjects taken at the qualifying examination, candidates seeking admission to the above courses should appear for Biology, Physics and Chemistry in AP EAPCET -2021.(AM Category).</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ii) Candidates should have completed 17years of age as on 31st December of the year of admission (2021) and an upper age limit of 22 years for all the candidates and 25 years in respect of SC/ST candidates as on 31st December of the year of admission (2021).</span></p><p><span style="font-size: large;">For B. Pharm Course:</span></p><p><span style="font-size: large;">i.<span style="white-space: pre;"> </span>Candidates should have passed or appeared for the final year of the intermediate examination (10+2 pattern) with Biology, Physics and Chemistry as optionals, conducted by the Board of Intermediate Education, Andhra Pradesh / Telangana as equivalent there to.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ii.<span style="white-space: pre;"> </span>Candidates should have completed 16 years of age by the date of commencement of admission or on such other date as may be notified by the CET committee. There is no upper age limit</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">For B.Tech. (Bio-Technology) Course:</span></p><p><span style="font-size: large;">Candidates should have passed or appeared for the final year of the intermediate examination (10+2 pattern) with Biology, Physics and Chemistry as optionals, along with the bridge course examination in mathematics conducted by the Board of Intermediate Education, Govt. of Andhra Pradesh / Telangana shall be eligible.</span></p><p><span style="font-size: large;">For Pharm-D Course:</span></p><p><span style="font-size: large;">i.<span style="white-space: pre;"> </span>Candidates should have passed or appeared for the final year of Intermediate Examination (10+2 pattern) with Physics, Chemistry and Biology as optional conducted by the Board of Intermediate Education, Andhra Pradesh / Telangana or any other examination recognized by the Board of Intermediate Education, Andhra Pradesh / Telangana as equivalent thereto or should have passed or appeared at the final year of the diploma examination in pharmacy course conducted by the Andhra Pradesh / Telangana State Board of Technical Education and Training or any other examination recognized as equivalent thereto by the Board of Intermediate Education, Andhra Pradesh / Telangana.</span></p><p><span style="font-size: large;">ii.<span style="white-space: pre;"> </span>Candidate should obtain at least 45% marks (40% in case of candidate belongs to reserved category) in the subjects specified taken together in the qualifying examination.</span></p><p><span style="font-size: large;">iii.<span style="white-space: pre;"> </span>The candidates should have completed 17 years of age as on 31st December of the year of admission (2021) to the above course.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">III.<span style="white-space: pre;"> </span>GENERAL INFORMATION / INSTRUCTIONS:</span></p><p><span style="font-size: large;">a)<span style="white-space: pre;"> </span>The Convener, AP EAPCET – 2021 reserves the right to reject the application of the candidate at anystage, if:</span></p><p><span style="font-size: large;">(I)<span style="white-space: pre;"> </span>The Online Application Form is incomplete.</span></p><p><span style="font-size: large;">(II)<span style="white-space: pre;"> </span>The candidate fails to satisfy the eligibility conditions.</span></p><p><span style="font-size: large;">(III)<span style="white-space: pre;"> </span>Any false or incorrect information is furnished.</span></p><p><span style="font-size: large;">(IV)<span style="white-space: pre;"> </span>The Online Application Form is submitted after the due date.</span></p><p><span style="font-size: large;">(V)<span style="white-space: pre;"> </span>No correspondence will be entertained in this regard.</span></p><p><span style="font-size: large;">a)<span style="white-space: pre;"> </span>The Convener is not responsible for non-receipt of application by the notified date and time for any reason.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IV.<span style="white-space: pre;"> </span>MEDIUM OF ENTRANCE TEST:</span></p><p><span style="font-size: large;">The question paper contains questions in “English” and “Telugu” medium only. Candidates, who have studied the qualifying examination in Urdu medium and wish to avail assistance for translating the questions into Urdu, will be allotted a Test Centre at Kurnool only.</span></p><p><span style="font-size: large;">V.<span style="white-space: pre;"> </span>REGISTRATION FEE:</span></p><p><span style="font-size: large;">Payment of Registration Fee for submission of Online Application Form is the first step and the Registration Fee is Rs. 600/- for student belongs to open category (for SC/ST Candidates</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">Rs 500/- and for BC Candidates Rs 550/- ) which has to be paid through the following modes:</span></p><p><span style="font-size: large;">a)<span style="white-space: pre;"> </span>AP ONLINE / TS ONLINE</span></p><p><span style="font-size: large;">b)<span style="white-space: pre;"> </span>CREDIT CARD / DEBIT CARD / NET BANKING</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">VI.<span style="white-space: pre;"> </span>SAME CENTRE FOR CANDIDATES APPEARING FOR BOTH ENGINEERING AND AGRICULTURE & PHARMACY: Candidates of E – Category who are eligible and desirous of taking the test in AM - Category, in addition to the test for E - Category should select the option Both (E & AP Category) together, during the submission of the Online Application Form, so that same Test Centre can be allotted to them for both the tests. If this instruction is not followed, the candidate may be allotted different Test Centres for E & AM category tests and Convener, AP EAPCET- 2021 is not responsible in allotment of different centres.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">VII REGIONAL CENTERS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Districts<span style="white-space: pre;"> </span>Regional</span></p><p><span style="font-size: large;">Centers<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>1<span style="white-space: pre;"> </span>2<span style="white-space: pre;"> </span>3<span style="white-space: pre;"> </span>4<span style="white-space: pre;"> </span>5</span></p><p><span style="font-size: large;">Anantapur<span style="white-space: pre;"> </span>Anantapur<span style="white-space: pre;"> </span>Gooty<span style="white-space: pre;"> </span>Hindupur<span style="white-space: pre;"> </span>Putaparthy<span style="white-space: pre;"> </span>Tadiparthy</span></p><p><span style="font-size: large;">Chittoor<span style="white-space: pre;"> </span>Chittoor<span style="white-space: pre;"> </span>Madanapalle<span style="white-space: pre;"> </span>Puttur<span style="white-space: pre;"> </span>Tirupati<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">East</span></p><p><span style="font-size: large;">Godavari<span style="white-space: pre;"> </span>Amalapura</span></p><p><span style="font-size: large;">m<span style="white-space: pre;"> </span>Kakinada<span style="white-space: pre;"> </span>Rajahmundry<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">Guntur<span style="white-space: pre;"> </span>Guntur<span style="white-space: pre;"> </span>Narasaraopeta<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">Krishna<span style="white-space: pre;"> </span>Gudlavalle</span></p><p><span style="font-size: large;">ru<span style="white-space: pre;"> </span>Machilipatnam<span style="white-space: pre;"> </span>Mylavaram<span style="white-space: pre;"> </span>Tiruvuru<span style="white-space: pre;"> </span>Vijayawad</span></p><p><span style="font-size: large;">a</span></p><p><span style="font-size: large;">Kurnool<span style="white-space: pre;"> </span>Kurnool<span style="white-space: pre;"> </span>Nandyal<span style="white-space: pre;"> </span>Yemmiganur<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">Nellore<span style="white-space: pre;"> </span>Gudur<span style="white-space: pre;"> </span>Kavali<span style="white-space: pre;"> </span>Nellore<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">Prakasam<span style="white-space: pre;"> </span>Chirala<span style="white-space: pre;"> </span>Markapuram<span style="white-space: pre;"> </span>Ongole<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">Srikakulam<span style="white-space: pre;"> </span>Rajam<span style="white-space: pre;"> </span>Srikakulam<span style="white-space: pre;"> </span>Tekkali<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">Visakhapatn</span></p><p><span style="font-size: large;">am<span style="white-space: pre;"> </span>Anakapalle<span style="white-space: pre;"> </span>Anandapuram<span style="white-space: pre;"> </span>Gajuwaka<span style="white-space: pre;"> </span>Visakhapa</span></p><p><span style="font-size: large;">tnam City<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">Vizianagara</span></p><p><span style="font-size: large;">m<span style="white-space: pre;"> </span>Bobbili<span style="white-space: pre;"> </span>Vizianagaram<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">West</span></p><p><span style="font-size: large;">Godavari<span style="white-space: pre;"> </span>Bhimavara</span></p><p><span style="font-size: large;">m<span style="white-space: pre;"> </span>Eluru<span style="white-space: pre;"> </span>Narasapuram<span style="white-space: pre;"> </span>Tadepallig</span></p><p><span style="font-size: large;">udem<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">YSR</span></p><p><span style="font-size: large;">Kadapa<span style="white-space: pre;"> </span>Kadapa<span style="white-space: pre;"> </span>Proddatur<span style="white-space: pre;"> </span>Rajampeta<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">Hyderabad<span style="white-space: pre;"> </span>LB Nagar<span style="white-space: pre;"> </span>Nacharam<span style="white-space: pre;"> </span>Secunderabad<span style="white-space: pre;"> </span>--<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">Note: 1.The Convener reserves the right to add or delete some online Test Centres from the list of Regional Centres notified.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>The Convener reserves the right to allot the candidates to any online Test Centre other than that opted by the candidates.</span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>Candidate has to submit not more than one application either for „E‟ or „AM‟ or „E&AM‟ category test. If any candidate submits more than one application for one category, the Convener reserves the right to reject all the applications or accept any one of them.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">VIII.<span style="white-space: pre;"> </span>SUBMISSION OF ONLINE APPLICATION FOR AP EAPCET – 2021</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Application should be submitted through Online mode only.</span></p><p><span style="font-size: large;">The following information must be kept ready for filling the details during Online submission:</span></p><p><span style="font-size: large;">a.<span style="white-space: pre;"> </span>Hall ticket Number of Qualifying Examination</span></p><p><span style="font-size: large;">b.<span style="white-space: pre;"> </span>Hall ticket Number of S.S.C. or equivalent</span></p><p><span style="font-size: large;">c.<span style="white-space: pre;"> </span>Date of Birth</span></p><p><span style="font-size: large;">d.<span style="white-space: pre;"> </span>Caste in case of SC/ST/BC candidates</span></p><p><span style="font-size: large;">e.<span style="white-space: pre;"> </span>Aadhar Number</span></p><p><span style="font-size: large;">f.<span style="white-space: pre;"> </span>PH, NCC, Sports etc.</span></p><p><span style="font-size: large;">g.<span style="white-space: pre;"> </span>Income Upto One Lakh or Up to Two Lakhs or More than Two Lakhs(Rupees)</span></p><p><span style="font-size: large;">h.<span style="white-space: pre;"> </span>Ration Card</span></p><p><span style="font-size: large;">i.<span style="white-space: pre;"> </span>Study or Residence or relevant certificate for proof of local status (last 12years)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Online submission:</span></p><p><span style="font-size: large;">For Online submission, visit the website www.sche.ap.gov.in/eapcet. A candidate has to pay Rs.600/- as Registration Fee (for SC/ST Candidates Rs 500/- and for BC Candidates Rs 550/-) and late fee (if applicable) by opting any of the following two modes of payment: (a) AP ONLINE / TS ONLINE (b) Debit / Credit Card / Net Banking. After filling the Online Application Form with the required details, the candidate is required to verify all the details carefully and press Submit button. Filled in Online Application Form will be generated which contains Registration Number along with filled in details. The candidate is required to take printout of Filled In Online Application Form and it is to be submitted to the Invigilator during the examination after affixing a recent color photograph duly attested by the Gazetted Officer or Principal of the College where studied qualifying examination. The candidate should use the Registration Number for futurecorrespondence.</span></p><p><span style="font-size: large;">IX.<span style="white-space: pre;"> </span>Mere appearance and qualifying at AP EAPCET-2021 does not confer any right for admission into professional courses. Candidate has to fulfill the eligibility criteria laid down</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">in the relevant G.O at the time of admission.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">X.<span style="white-space: pre;"> </span>QUALIFYING MARKS FOR AP EAPCET – 2021</span></p><p><span style="font-size: large;">The qualifying percentage of marks for the AP EAPCET-2021 is 25% of the maximum marks considered for ranking. However, for candidates belonging to Scheduled Caste and Scheduled Tribe, no minimum qualifying mark is prescribed. But their admission will be limited to the extent of seats reserved for such categories (vide G.O.Ms. No. 179, LEN&TE, dated 16.06.1986).</span></p><p><span style="font-size: large;">XI.<span style="white-space: pre;"> </span>AP EAPCET-2021 RESULTS</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>Evaluation: Every care will be taken to avoid errors in the evaluation, checking, scrutiny, tabulation, normalization and ranking.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>Ranking:</span></p><p><span style="font-size: large;">a.<span style="white-space: pre;"> </span>Candidates shall be ranked based on the EAPCET normalized marks (75% weightage) and 10+2 (25% weightage) in the order of merit as explained in the Annexure-IV and Annexure-V.</span></p><p><span style="font-size: large;">b.<span style="white-space: pre;"> </span>Rank obtained in AP EAPCET-2021 is valid for admission to the courses mentioned in the application form for the academic year 2021-2022 only.</span></p><p><span style="font-size: large;">c.<span style="white-space: pre;"> </span>Rank card shall be downloaded from the website www.sche.ap.gov.in/eapcet</span></p><p><span style="font-size: large;">d.<span style="white-space: pre;"> </span>Rank obtained with the benefit of relaxation of the minimum qualifying marks at AP EAPCET-2021 by any candidate claiming as SC/ST Category will be cancelled in case the claim is found to be invalid at the time of admission to any course of study in any participating University / Institution.</span></p><p><span style="font-size: large;">XII.<span style="white-space: pre;"> </span>The candidates should preserve the Filled In Online Application Form, the Hall Ticket and the Rank Card to produce them when called for verification.</span></p><p><span style="font-size: large;">XIII.<span style="white-space: pre;"> </span>Any malpractice in AP EAPCET-2021 will be dealt with as per rules in force vide G.O.Ms.No: 114, Edn / (IE) Dt: 13th May 1997 for the CET.</span></p><p><span style="font-size: large;">XIV.<span style="white-space: pre;"> </span>In any litigation concerning AP EAPCET-2021 Test, Convener is the person to sue and be sued. The Convener (Examination), AP EAPCET – 2021 is not responsible for allotment of seats at the time of admissions. The Commissioner of Technical Education, Andhra Pradesh is the Convener for the Admissions.</span></p><p><span style="font-size: large;">XV.<span style="white-space: pre;"> </span>Any litigation concerning AP EAPCET-2021 shall be subject to the jurisdiction of the</span></p><p><span style="font-size: large;">A.P. High Court, Amaravathi only.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">XVI.<span style="white-space: pre;"> </span>HALL TICKET</span></p><p><span style="font-size: large;">The<span style="white-space: pre;"> </span>candidate<span style="white-space: pre;"> </span>should<span style="white-space: pre;"> </span>download<span style="white-space: pre;"> </span>the<span style="white-space: pre;"> </span>Hall<span style="white-space: pre;"> </span>Ticket<span style="white-space: pre;"> </span>from<span style="white-space: pre;"> </span>website</span></p><p><span style="font-size: large;">http://www.sche.ap.gov.in/eapcet</span></p><p><span style="font-size: large;">XVII.<span style="white-space: pre;"> </span>COUNSELLING AND ALLOTMENT OF SEATS</span></p><p><span style="font-size: large;">The list of institutions for allotment of candidates with intake in each discipline and category, as per reservations through AP EAPCET – 2021 would be released in the Information Booklet for Counseling in due course and the same information would also be released on website http:// www.sche.ap.gov.in</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">IMPORTANT INSTRUCTIONS TO CANDIDATES</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>Material to be brought on the date of examination</span></p><p><span style="font-size: large;">Hall Ticket along with Filled in Online Application Form with duly affixed recent colour photograph attested by Gazetted Officer (or) Principal of the College where candidate has studied the qualifying examination. However, Signature of the candidate and Left Hand Thumb impression in the presence of Invigilator to be captured in the respective places provided in the Filled in Online Application form.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>Other important instructions</span></p><p><span style="font-size: large;">a.<span style="white-space: pre;"> </span>Hall ticket issued to the candidate is an important document. Candidates are required to preserve it carefully.</span></p><p><span style="font-size: large;">b.<span style="white-space: pre;"> </span>Hall ticket is not transferable. Any tampering of Hall Ticket will automatically lead to the disqualification of the candidate</span></p><p><span style="font-size: large;">c.<span style="white-space: pre;"> </span>Candidate shall arrive at the online examination centre 2 hours before commencement of the examination. This will enable the candidate to familiarize himself/herself with the online examination process.</span></p><p><span style="font-size: large;">d.<span style="white-space: pre;"> </span>Candidate is not allowed even late by One Minute from the commencement of the online examination.</span></p><p><span style="font-size: large;">e.<span style="white-space: pre;"> </span>The candidate does not have option of choosing specific date / session to appear for the AP EAPCET- 2021 entrance examination. This information is known to him / her only after downloading Hall Ticket. For any reason if the candidate fails to appear in the given slot, he / she is treated as absent.</span></p><p><span style="font-size: large;">f.<span style="white-space: pre;"> </span>Candidates are required to bring the following to the online examinationcentre:</span></p><p><span style="font-size: large;">i)<span style="white-space: pre;"> </span>Hall Ticket, ii) Filled in Online Application Form, iii) A good Ball Point Pen (for rough work, working sheets will be provided by the Test Centre) and iv) Attested copy of Caste certificate (in case of SC/ST category candidates only).</span></p><p><span style="font-size: large;">g.<span style="white-space: pre;"> </span>Candidates are not allowed to carry any textual material, Calculators, DocuPen, Slide Rules, Log Tables, Electronic Watches with facilities of calculator, printed or written material, bits of papers, mobile phone, pager or any other device, except the Hall Ticket, document as required under point no. 2.(e) inside the Examination Room/Hall. If any candidate is in possession of any of the above items, his/her candidature will be treated as unfair means and his/her current examination will be cancelled & he/she will also be debarred for future examination(s) & the equipment will beseized.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large; white-space: pre;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">GUIDELINES TO CANDIDATES</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>Please check the Hall ticket carefully for your Name, Date of Birth, Gender, Category, Test Centre Name, Date and Time of examination.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>Candidates are advised to reach the venue at least 2 hours before the examination so as to complete the frisking and registration formalities well before the time. Registration desk will be closed 05 minutes prior to the examination.</span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>The candidate must show, on demand, the Hall Ticket for admission in the examination room/hall. A candidate who does not possess the Hall Ticket issued by the Convener, AP EAPCET-2021, shall not be permitted for the examination under any circumstances by the Centre Superintendent.</span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>No candidate, under any circumstances, will be allowed to enter the Examination Centre after the commencement of the examination.</span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>A seat indicating Hall Ticket number will be allocated to each candidate. Candidate should find out and occupy their allotted seat only. Any candidate found to have changed room or the seat on his/her own other than allotted, his/her candidature shall be cancelled and no plea would be accepted for it.</span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>The candidate should ensure that the question paper available on the computer in English and Telugu languages only.</span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>No Candidate will be allowed to carry any baggage inside the Examination Centre. The Convener, AP EAMPET-2021 will not be responsible for any belongings stolen or lost at the premises.</span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>Smoking and eating is strictly prohibited in the examinationroom.</span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>Tea, coffee, cool drinks or snacks are not allowed to be taken into the examination rooms during examination hours.</span></p><p><span style="font-size: large;">10.<span style="white-space: pre;"> </span>Approach the Centre Superintendent/Invigilator in the room for any technical assistance, first aid emergency or any other information during the course of examination.</span></p><p><span style="font-size: large;">11.<span style="white-space: pre;"> </span>No candidate, without the special permission of the Centre Superintendent or the Invigilator concerned, will leave his/her seat or Examination Room until the full duration of the Examination. Candidates must follow the instructions strictly as instructed by the Centre Superintendent/Invigilators.</span></p><p><span style="font-size: large;">12.<span style="white-space: pre;"> </span>For any queries or issues regarding computer based examination, the candidates may contact on help line numbers which will be available on www.sche.ap.gov.in/eapcet website later on.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">INSTRUCTIONS FOR ON-LINE (COMPUTER BASED) EXAMINATION</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">The On- Line (Computer Based) Examination will be conducted as per the following schedule.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>A sample/mock test will be available on www.sche.ap.gov.in/eapcet website for practice purpose and to give the candidate look and feel of the On- Line (Computer Based) Examination.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>The test will start exactly at the time mentioned in the Hall Ticket and an announcement to this effect will be made by the invigilator.</span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>The Entrance test is conducted for a during of 3 hour and the question paper consists of total 160 questions comprising of 80 questions in Mathematics, 40 questions in Physics and 40 questions in Chemistry. All questions are having equal weightage.</span></p><p><span style="font-size: large;">4.<span style="white-space: pre;"> </span>There is only one correct response for each question out of four responses given.</span></p><p><span style="font-size: large;">5.<span style="white-space: pre;"> </span>There is no negative marking and No deduction from the total score will be made if no response is indicated for a question.</span></p><p><span style="font-size: large;">6.<span style="white-space: pre;"> </span>All calculations/writing work are to be done only in the rough sheet provided at the centre and on completion of the test candidates must hand over the rough sheets to the invigilator on duty in the Room/Hall.</span></p><p><span style="font-size: large;">7.<span style="white-space: pre;"> </span>During the examination time, the invigilator will check Hall ticket of the candidate to satisfy himself/herself about the identity of each candidate.</span></p><p><span style="font-size: large;">8.<span style="white-space: pre;"> </span>The candidates are governed by all Rules and Regulations of the Convener, EAPCET- 2021 with regard to their conduct in the Examination Hall. All cases of unfair means will be dealt with as per rules.</span></p><p><span style="font-size: large;">9.<span style="white-space: pre;"> </span>The candidates must sign and give his/her Left Hand Thumb impression on the Attendance Sheet at the appropriate place.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">The following Proforma I, II and III are to be submitted at the time of counseling to claim nativity, community and local status.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PROFORMA – I</span></p><p><span style="font-size: large;">REVISED PROFORMAAS PER G.O.Ms.No.58, SOCIAL WELFARE (J) DEPT. DATED 12.05.1997 ANDHRA PRADESH GAZETTE EXTRAORDINARY PART-I</span></p><p><span style="font-size: large;">Serial No.<span style="white-space: pre;"> </span>FORM III</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">S.C.<span style="white-space: pre;"> </span>District Code :</span></p><p><span style="font-size: large;">S.T.<span style="white-space: pre;"> </span>Emblem<span style="white-space: pre;"> </span>Mandal Code:</span></p><p><span style="font-size: large;">B.C.<span style="white-space: pre;"> </span>Village Code:</span></p><p><span style="font-size: large;">Certificate No.:<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">COMMUNITY, NATIVITY AND DATE OF BIRTH CERTIFICATE</span></p><p><span style="font-size: large;">(Integrated Community Certificate)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>This is to Certify that Sri / Smt / Kum <span style="white-space: pre;"> </span> Son / Daughter of Sri<span style="white-space: pre;"> </span>of village /Town</span></p><p><span style="font-size: large;"> <span style="white-space: pre;"> </span>Mandal<span style="white-space: pre;"> </span>_District of the state of Andhra Pradesh / Telangana belongs to<span style="white-space: pre;"> </span>Community which was recognized as SC/ST/BC under</span></p><p><span style="font-size: large;">The Constitution (Scheduled Caste) Order, 1950 The Constitution (Scheduled Tribes) Order, 1950</span></p><p><span style="font-size: large;">G.O.Ms.No.1793, Education, dated 25.09.1970 as amended from time to time BCs, SCs, STs list (Modification) Order 1956, SCs and STs (Amendment) Act, 1976.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>It is to certify that Sri / Smt / Kum<span style="white-space: pre;"> </span>is a native of <span style="white-space: pre;"> </span> District of Andhra Pradesh / Telangana</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>It is to certify that date of birth of Sri / Smt / Kum<span style="white-space: pre;"> </span>is</span></p><p><span style="font-size: large;">Day<span style="white-space: pre;"> </span>Month<span style="white-space: pre;"> </span>Year<span style="white-space: pre;"> </span>(in words</span></p><p><span style="font-size: large;"> <span style="white-space: pre;"> </span>) as per the declaration given by his /her Father / Mother / Guardian and as entered in the school records where he / she studied</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Signature Date</span></p><p><span style="font-size: large;">(Seal)<span style="white-space: pre;"> </span>Name in Capital letters:</span></p><p><span style="font-size: large;">Designation:</span></p><p><span style="font-size: large;">Explanatory Note:</span></p><p><span style="font-size: large;">1) While mentioning the community, the competent Authority must mention the sub-caste (in case of SCs) and Sub-Tribe or Sub- Group (in case of STs) as listed out in the SCs and STs (Amendment) Act, 1976.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">PROFORMA – II</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">RESIDENCE CERTIFICATE IN SUPPORT OF APPLICATION</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>It is hereby certified</span></p><p><span style="font-size: large;">a.<span style="white-space: pre;"> </span>That Sri/Smt / Kum <span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">son / daughter of</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">Sri / Smt.<span style="white-space: pre;"> </span>a candidate for admission to the course appeared for the first time for the<span style="white-space: pre;"> </span>examination (being the minimum qualifying examination for admission to the course mentioned above) in<span style="white-space: pre;"> </span>(month)</span></p><p><span style="font-size: large;"> <span style="white-space: pre;"> </span>(year).</span></p><p><span style="font-size: large;">b.<span style="white-space: pre;"> </span>That in the 7 years, immediately preceding the commencement of the aforesaid examination he / she has resided in the following place / places falling within the area in respect of the AU/OU/SVU region (Tick appropriate one).</span></p><p><span style="font-size: large;">S.No.<span style="white-space: pre;"> </span>Period<span style="white-space: pre;"> </span>Village<span style="white-space: pre;"> </span>Mandal<span style="white-space: pre;"> </span>District</span></p><p><span style="font-size: large;">1<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">2<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">3<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">4<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">5<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">6<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;">7<span style="white-space: pre;"> </span></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>The above candidate is, therefore, a local candidate in relation to the area specified in Paragraph 3(1)(2)(3) of the Andhra Pradesh Educational Institution (Regulation of Admissions) Order 1974 as amended.</span></p><p><span style="font-size: large;">Officer of the Revenue Department (Issued by the competent authority of Revenue Dept.)</span></p><p><span style="font-size: large;">Date:<span style="white-space: pre;"> </span>(OFFICE SEAL)</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">PROFORMA – III</span></p><p><span style="font-size: large;">CERTIFICATES IN SUPPORT OF NON-LOCAL STATUS FOR E – CATEGORY</span></p><p><span style="font-size: large;">(A)<span style="white-space: pre;"> </span>Certificate to be furnished when the candidate has resided in the state for a period of 10 years (Read Instructions under 3(a) of Annexure (III) of Instruction Booklet of admission)</span></p><p><span style="font-size: large;">This is to certify that Mr./ Kum. <span style="white-space: pre;"> </span> Son / Daughter of Sri. / Smt. <span style="white-space: pre;"> </span> a candidate seeking admission in to professional courses (Engineering stream & Agricultural and Pharmacy stream) through AP EAPCET 2021 for the Academic Year 2021-22 is a resident of</span></p><p><span style="font-size: large;"> <span style="white-space: pre;"> </span>(Place) in<span style="white-space: pre;"> </span>(District) of Andhra Pradesh / Telangana for a total period of 10 years from the year<span style="white-space: pre;"> </span>to<span style="white-space: pre;"> </span>excluding the periods of study outside the state.</span></p><p><span style="font-size: large;">Place:<span style="white-space: pre;"> </span>Signature of the Competent</span></p><p><span style="font-size: large;">Date:<span style="white-space: pre;"> </span>Authority from Revenue Dept.</span></p><p><span style="font-size: large;">Office Seal:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(B)<span style="white-space: pre;"> </span>Certificate to be furnished when either of the parents of the candidate has resided in the state for a period of 10 years. (Read Instructions under 3(b) of Annexure (III) of Instruction Booklet of admission)</span></p><p><span style="font-size: large;">This is to certify that Sri/Smt.<span style="white-space: pre;"> </span>, Father / Mother of <span style="white-space: pre;"> </span> a candidate seeking admission in to professional courses (Engineering stream & Agricultural and Pharmacy stream)<span style="white-space: pre;"> </span>through AP EAPCET 2021 for the Academic Year 2021-22, is a resident of</span></p><p><span style="font-size: large;"> <span style="white-space: pre;"> </span>(Place) in<span style="white-space: pre;"> </span>(District) of Andhra Pradesh / Telangana for a total period of 10 years from the year<span style="white-space: pre;"> </span>to<span style="white-space: pre;"> </span>excluding the periods of study outside the state.</span></p><p><span style="font-size: large;">Place:<span style="white-space: pre;"> </span>Signature of the Competent</span></p><p><span style="font-size: large;">Date:<span style="white-space: pre;"> </span>Authority from Revenue Dept.</span></p><p><span style="font-size: large;">Office Seal:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(C)<span style="white-space: pre;"> </span>Certificate to be furnished when the parent / spouse is an employee of the State or Central Government or Quasi- Government Organization.</span></p><p><span style="font-size: large;">(Read Instructions under 3(c ) and 3(d) of Annexure (III) of Instruction Booklet of admission)</span></p><p><span style="font-size: large;">This is to certify that Sri/Smt. <span style="white-space: pre;"> </span> Father / Mother of <span style="white-space: pre;"> </span> a candidate seeking admission in to professional courses (Engineering stream & Agricultural and Pharmacy stream) through AP EAPCET 2021 for the<span style="white-space: pre;"> </span>Academic<span style="white-space: pre;"> </span>Year<span style="white-space: pre;"> </span>2021-22,<span style="white-space: pre;"> </span>is<span style="white-space: pre;"> </span>presently employed<span style="white-space: pre;"> </span>in<span style="white-space: pre;"> </span>Andhra<span style="white-space: pre;"> </span>Pradesh<span style="white-space: pre;"> </span>State<span style="white-space: pre;"> </span>in the Organization from<span style="white-space: pre;"> </span>till to-date. This Organization is a State / Central / Quasi Government Organization in the State of Andhra Pradesh</span></p><p><span style="font-size: large;">/ Telangana.</span></p><p><span style="font-size: large;">Place:<span style="white-space: pre;"> </span>Signature of the Competent</span></p><p><span style="font-size: large;">Date:<span style="white-space: pre;"> </span>Authority from Revenue Dept.</span></p><p><span style="font-size: large;">Office Seal:</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ANNEXURE – II</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ANNEXURE – III</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">DEFINITION OF LOCAL / NON - LOCAL STATUS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>A Candidate shall be regarded as a local Candidate in relation to a local area (AU/OU/SVU)</span></p><p><span style="font-size: large;">If he/she has studied in an Educational Institution or Educational Institutions in such local area for a period of not less than four consecutive academic years ending with the academic year in which he/she appeared or first appeared in the relevant qualifying examination as the case may be.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Where, during the whole or any part of the four consecutive academic years in which he/she appeared, or first appeared in the relevant qualifying examination, he/she has not studied in any educational institutions, if he/she resided in that local area for a period of not less than four years immediately preceding the date of commencement of the relevant qualifying examination in which he/she appeared, or first appeared, as the case maybe.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>A candidate who is not regarded as local candidate under clause (1.1) above in relation to any local areashall</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">If he/she studied in the educational institutions in the state for a period of not less than seven consecutive academic years ending with the academic year in which he/she appeared or first appeared for the relevant qualifying examination as the case may be, be regarded as a local candidate in relation to</span></p><p><span style="font-size: large;">i.<span style="white-space: pre;"> </span>Such local area where he/she studied for the maximum period out of period of seven years.</span></p><p><span style="font-size: large;">OR</span></p><p><span style="font-size: large;">ii.<span style="white-space: pre;"> </span>Where the period of his/her study in two or more local areas is equal, such local area where he/she studied last in such equal periods.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">If during the whole or any part of the seven consecutive academic years ending with the academic year in which he/she appeared or first appeared for the relevant qualifying examination, he/she has not studied in the educational institutions, in any local area, but has resided in the state during the whole of the said period of seven years, be regarded as a local candidate in relation to</span></p><p><span style="font-size: large;">i.<span style="white-space: pre;"> </span>Such local area where he/she has resided for the maximum period out of the said period of seven years.</span></p><p><span style="font-size: large;">OR</span></p><p><span style="font-size: large;">ii.<span style="white-space: pre;"> </span>Where the period of his/her residence in two or more local areas is equal such local area where he/she had resided last in such periods.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Note:</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>Local area in respect of Andhra University (A.U. area) includes Nagarjuna University area. In respect of Sri Venkateswara University (S.V.U. area), it includes Sri Krishnadevaraya University area. In respect of Osmania University (O.U. area), it includes Kakatiya University area.</span></p><p><span style="font-size: large;">2.<span style="white-space: pre;"> </span>The Candidate belonging to PIO / OCI category will be considered as under non local category only.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">3.<span style="white-space: pre;"> </span>Candidates coming under any of the categories given below and not satisfying the conditions mentioned in 1 or 2 above are treated as „Non-Local‟ to all the three University areas specified above.</span></p><p><span style="font-size: large;">a.<span style="white-space: pre;"> </span>Candidates who have resided in the state of A.P. for a total period of 10 years or more excluding the period of study outside this state.</span></p><p><span style="font-size: large;">OR</span></p><p><span style="font-size: large;">b.<span style="white-space: pre;"> </span>Candidates either of whose parents has resided in this state for a total period of 10 years or more excluding the periods of employment outside the state</span></p><p><span style="font-size: large;">OR</span></p><p><span style="font-size: large;">c.<span style="white-space: pre;"> </span>Candidates either of whose parents is employed in the State of A.P. or Central Government Public Sector Corporations, Local Bodies, Universities and other similar quasi Government Institutions within this state, at the time of submitting the application</span></p><p><span style="font-size: large;">OR</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Candidates who are spouses of those employed in the State of A.P. or Central Government, Public Sector Corporations, Local Bodies, Universities and other similar quasi Government Institutions within this state, at the time of submitting the application.</span></p><p><span style="font-size: large;">For full details refer G.O.No. 646, dated 10.07.1979.</span></p><p><span style="font-size: large;">Note:</span></p><p><span style="font-size: large;">Blank Proforma III is provided for submitting relevant information regarding Local/Non- Local status of candidates.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">ANNEXURE – IV NORMALIZATION PROCEDURE</span></p><p><span style="font-size: large;">Candidates are aware that the APEAPCET-2021 (MPC and Bi.PC Streams) are conducted from 19-09-2021 to 25- 08-2021 in multiple sessions.</span></p><p><span style="font-size: large;">APEAPCET-2021 is being conducted in multiple sessions based on the same syllabus, same pattern for candidates having same eligibility criteria. A candidate will be eligible to appear only in one session. Since the question paper will be different for each session, there is a possibility that the candidates compare themselves about the variation in the difficulty level of questions. However, it may be noted that utmost care will be taken so that all the papers are of same standard. Further, it is decided to adopt a normalization process to eliminate any such variations in the difficulty level of various sessions.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">What is Normalization?</span></p><p><span style="font-size: large;">Normalization, as used in Indian context, is a process for ensuring the students neither advantaged nor disadvantaged by the difficulty of examinations conducted in multiple sessions. This process is based on a simple formula which has been adopted as recommended by the experts from reputed educational institutions at all India level and Universities. The process is being implemented in other all India / Nationwide entrance tests for admission into undergraduate and graduate professional courses. Normalization process ranks all the candidates across all sessions on a comparative scale. In any normalization process, the marks of the easier session may be reduced marginally and the marks of the harder paper may increase marginally on the global level, depending on the average performance in each session. If there is no much difference in the averages between two sessions then there won‟t be much difference in the normalized marks as well. Normalizing marks would justify the candidates while protecting their actual performance.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AP EAPCET marks Normalization Process:</span></p><p><span style="font-size: large;">The main aim of the normalization is to justify the candidates who got a difficult paper compared to an easier paper. Hence, the task is to rationalize in a best possible sense and rank the candidates based on the global performance. Various national level examination bodies like JEE (Main), GATE etc. are currently adopting such normalization procedures. Correspondingly, EAPCET committee has deliberated extensively and decided to use the following normalization procedure.</span></p><p><span style="font-size: large;">Normalized Marks of the candidate</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(𝐺𝑀𝑆) + (𝑇𝑜𝑝 𝐴𝑣𝑒𝑟𝑎𝑔𝑒 𝐺𝑙𝑜𝑏𝑎𝑙 − 𝐺𝑀𝑆) × (𝑀𝑎𝑟𝑘𝑠 𝑂𝑏𝑡𝑎𝑖𝑛𝑒𝑑 𝑏𝑦 𝐶𝑎𝑛𝑑𝑖𝑑𝑎𝑡𝑒 − 𝑆𝑀𝑆) (𝑇𝑜𝑝 𝐴𝑣𝑒𝑟𝑎𝑔𝑒 𝑆𝑒𝑠𝑠𝑖𝑜𝑛 − 𝑆𝑀𝑆)</span></p><p><span style="font-size: large;">where</span></p><p><span style="font-size: large;">SMS: (Average + Standard Deviation) of the session in which the candidate belongs to GMS: (Average + Standard Deviation) of all the candidates across all sessions together Top Average Session: Average marks of the top 0.1% of the candidates in the session in</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">which the candidate belongs to</span></p><p><span style="font-size: large;">Top Average Global: Average marks of the top 0.1% of all the candidates across all sessions Together</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Weightage for assigning merit ranks:</span></p><p><span style="font-size: large;">75% of AP EAPCET normalized marks and 25% of Intermediate Marks in group subjects to prepare the rank.</span></p><p><span style="font-size: large;">Note:</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>For Candidates having qualifying marks in AP EAPCET-2021, if after normalization, the marks(s) in any individual subject(s) become negative, then the normalized mark(s) in the respective subject(s) are treated as zero. However, total marks in three subjects are considered as EAPCET marks.</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>For the candidates for whom there is no qualifying cut off in AP EAPCET - 2021, if the marks in all the three subjects after normalization goes below zero (negative), the total marks is treated as zero and the rank is assigned. If the tie persists then APEAPCET 2021 normalization marks (though negative are considered for breaking the tie).</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Demonstration with a sample data:</span></p><p><span style="font-size: large;">The following is based on a sample data to explain the normalization process. The data is based on almost equal number of candidates in all the four sessions. The normalization is shown subject wise so that students get the benefit based on subject wise performance rather than the entire paper in a session.</span></p><p><span style="font-size: large;">Averages and Standard Deviations in a particular session and averages of top 0.1% candidates of a particular session, Global Average and Standard Deviations of all sessions together, Averages of top 0.1% candidates in all sessions is given in Table</span></p><p><span style="font-size: large;">1.<span style="white-space: pre;"> </span>Example data of normalized marks is shown in Table 2 to Table 5.</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">Table 1: Averages and Standard Deviations of sample data</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Maths<span style="white-space: pre;"> </span>Physics<span style="white-space: pre;"> </span>Chemistry</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Session1<span style="white-space: pre;"> </span>Avg<span style="white-space: pre;"> </span>27.01245<span style="white-space: pre;"> </span>11.44816<span style="white-space: pre;"> </span>13.56629</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Std_Dev<span style="white-space: pre;"> </span>10.23632<span style="white-space: pre;"> </span>4.135746<span style="white-space: pre;"> </span>5.939418</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Top 0.1% Avg<span style="white-space: pre;"> </span>74.28<span style="white-space: pre;"> </span>37.93<span style="white-space: pre;"> </span>37.7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Session2<span style="white-space: pre;"> </span>Avg<span style="white-space: pre;"> </span>27.23746<span style="white-space: pre;"> </span>11.49711<span style="white-space: pre;"> </span>13.69626</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Std_Dev<span style="white-space: pre;"> </span>10.38974<span style="white-space: pre;"> </span>4.177132<span style="white-space: pre;"> </span>6.005731</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Top 0.1% Avg<span style="white-space: pre;"> </span>74.85<span style="white-space: pre;"> </span>38.03<span style="white-space: pre;"> </span>37.93</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Session3<span style="white-space: pre;"> </span>Avg<span style="white-space: pre;"> </span>23.8686<span style="white-space: pre;"> </span>10.25933<span style="white-space: pre;"> </span>13.55555</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Std_Dev<span style="white-space: pre;"> </span>7.717783<span style="white-space: pre;"> </span>3.20095<span style="white-space: pre;"> </span>5.403734</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Top 0.1% Avg<span style="white-space: pre;"> </span>70.05<span style="white-space: pre;"> </span>35.55<span style="white-space: pre;"> </span>39</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Session4<span style="white-space: pre;"> </span>Avg<span style="white-space: pre;"> </span>23.95383<span style="white-space: pre;"> </span>10.2931<span style="white-space: pre;"> </span>13.55808</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Std_Dev<span style="white-space: pre;"> </span>7.793973<span style="white-space: pre;"> </span>3.212227<span style="white-space: pre;"> </span>5.460391</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Top 0.1% Avg<span style="white-space: pre;"> </span>70.18<span style="white-space: pre;"> </span>36.4<span style="white-space: pre;"> </span>39.38</span></p><p><span style="font-size: large;">All</span></p><p><span style="font-size: large;">sessions together<span style="white-space: pre;"> </span>Global_Avg<span style="white-space: pre;"> </span>25.52725<span style="white-space: pre;"> </span>10.87743<span style="white-space: pre;"> </span>13.60516</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Global_Std_Dev<span style="white-space: pre;"> </span>9.252138<span style="white-space: pre;"> </span>3.764241<span style="white-space: pre;"> </span>5.718592</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Top 0.1% Global Avg<span style="white-space: pre;"> </span>73.92<span style="white-space: pre;"> </span>37.65<span style="white-space: pre;"> </span>38.74</span></p><p><span style="font-size: large;">Table 2: Example of Normalized marks in Session 1:</span></p><p><span style="font-size: large;">Candidate<span style="white-space: pre;"> </span>Marks<span style="white-space: pre;"> </span>Maths<span style="white-space: pre;"> </span>Physics<span style="white-space: pre;"> </span>Chemistry<span style="white-space: pre;"> </span>Total</span></p><p><span style="font-size: large;">C1<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>0<span style="white-space: pre;"> </span>0<span style="white-space: pre;"> </span>0<span style="white-space: pre;"> </span>0</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>-4.6<span style="white-space: pre;"> </span>-1.407<span style="white-space: pre;"> </span>-1.49<span style="white-space: pre;"> </span>-7.498</span></p><p><span style="font-size: large;">C2<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>8<span style="white-space: pre;"> </span>3<span style="white-space: pre;"> </span>5<span style="white-space: pre;"> </span>16</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>3.857<span style="white-space: pre;"> </span>1.682<span style="white-space: pre;"> </span>3.845<span style="white-space: pre;"> </span>9.385</span></p><p><span style="font-size: large;">C3<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>61<span style="white-space: pre;"> </span>16<span style="white-space: pre;"> </span>25<span style="white-space: pre;"> </span>102</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>59.89<span style="white-space: pre;"> </span>15.07<span style="white-space: pre;"> </span>25.19<span style="white-space: pre;"> </span>100.1</span></p><p><span style="font-size: large;">C4<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>76<span style="white-space: pre;"> </span>36<span style="white-space: pre;"> </span>38<span style="white-space: pre;"> </span>150</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>75.75<span style="white-space: pre;"> </span>35.67<span style="white-space: pre;"> </span>39.06<span style="white-space: pre;"> </span>150.5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Table 3: Example of Normalized marks in Session 2:</span></p><p><span style="font-size: large;">Candidate<span style="white-space: pre;"> </span>Marks<span style="white-space: pre;"> </span>Maths<span style="white-space: pre;"> </span>Physics<span style="white-space: pre;"> </span>Chemistry<span style="white-space: pre;"> </span>Total</span></p><p><span style="font-size: large;">C1<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>1<span style="white-space: pre;"> </span>3<span style="white-space: pre;"> </span>4<span style="white-space: pre;"> </span>8</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>-3.74<span style="white-space: pre;"> </span>1.595<span style="white-space: pre;"> </span>2.595<span style="white-space: pre;"> </span>0.451</span></p><p><span style="font-size: large;">C2<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>14<span style="white-space: pre;"> </span>9<span style="white-space: pre;"> </span>2<span style="white-space: pre;"> </span>25</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>9.932<span style="white-space: pre;"> </span>7.771<span style="white-space: pre;"> </span>0.464<span style="white-space: pre;"> </span>18.17</span></p><p><span style="font-size: large;">C3<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>48<span style="white-space: pre;"> </span>24<span style="white-space: pre;"> </span>33<span style="white-space: pre;"> </span>105</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>45.69<span style="white-space: pre;"> </span>23.21<span style="white-space: pre;"> </span>33.49<span style="white-space: pre;"> </span>102.4</span></p><p><span style="font-size: large;">C4<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>78<span style="white-space: pre;"> </span>38<span style="white-space: pre;"> </span>39<span style="white-space: pre;"> </span>155</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>77.24<span style="white-space: pre;"> </span>37.62<span style="white-space: pre;"> </span>39.88<span style="white-space: pre;"> </span>154.7</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">Table 4: Example of Normalized marks in Session 3:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Candidate<span style="white-space: pre;"> </span>Marks<span style="white-space: pre;"> </span>Maths<span style="white-space: pre;"> </span>Physics<span style="white-space: pre;"> </span>Chemistry<span style="white-space: pre;"> </span>Total</span></p><p><span style="font-size: large;">C1<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>0<span style="white-space: pre;"> </span>0<span style="white-space: pre;"> </span>0<span style="white-space: pre;"> </span>0</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>2.634<span style="white-space: pre;"> </span>0.622<span style="white-space: pre;"> </span>0.957<span style="white-space: pre;"> </span>4.21</span></p><p><span style="font-size: large;">C2<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>10<span style="white-space: pre;"> </span>5<span style="white-space: pre;"> </span>1<span style="white-space: pre;"> </span>16</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>12.81<span style="white-space: pre;"> </span>5.83<span style="white-space: pre;"> </span>1.926<span style="white-space: pre;"> </span>20.6</span></p><p><span style="font-size: large;">C3<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>50<span style="white-space: pre;"> </span>17<span style="white-space: pre;"> </span>31<span style="white-space: pre;"> </span>98</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>53.52<span style="white-space: pre;"> </span>18.33<span style="white-space: pre;"> </span>30.99<span style="white-space: pre;"> </span>103</span></p><p><span style="font-size: large;">C4<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>74<span style="white-space: pre;"> </span>39<span style="white-space: pre;"> </span>38<span style="white-space: pre;"> </span>151</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>77.94<span style="white-space: pre;"> </span>41.24<span style="white-space: pre;"> </span>37.77<span style="white-space: pre;"> </span>157</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Table 5: Example of Normalized marks in Session 4:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Candidate<span style="white-space: pre;"> </span>Marks<span style="white-space: pre;"> </span>Maths<span style="white-space: pre;"> </span>Physics<span style="white-space: pre;"> </span>Chemistry<span style="white-space: pre;"> </span>Total</span></p><p><span style="font-size: large;">C1<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>4<span style="white-space: pre;"> </span>1<span style="white-space: pre;"> </span>2<span style="white-space: pre;"> </span>7</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>6.457<span style="white-space: pre;"> </span>1.97<span style="white-space: pre;"> </span>2.935<span style="white-space: pre;"> </span>11.4</span></p><p><span style="font-size: large;">C2<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>19<span style="white-space: pre;"> </span>7<span style="white-space: pre;"> </span>9<span style="white-space: pre;"> </span>35</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>21.75<span style="white-space: pre;"> </span>8.018<span style="white-space: pre;"> </span>9.641<span style="white-space: pre;"> </span>39.4</span></p><p><span style="font-size: large;">C3<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>13<span style="white-space: pre;"> </span>6<span style="white-space: pre;"> </span>16<span style="white-space: pre;"> </span>35</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>15.63<span style="white-space: pre;"> </span>7.01<span style="white-space: pre;"> </span>16.35<span style="white-space: pre;"> </span>39</span></p><p><span style="font-size: large;">C4<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>67<span style="white-space: pre;"> </span>9<span style="white-space: pre;"> </span>24<span style="white-space: pre;"> </span>100</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>70.69<span style="white-space: pre;"> </span>10.03<span style="white-space: pre;"> </span>24.01<span style="white-space: pre;"> </span>105</span></p><p><span style="font-size: large;">C5<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>57<span style="white-space: pre;"> </span>8<span style="white-space: pre;"> </span>35<span style="white-space: pre;"> </span>100</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>60.49<span style="white-space: pre;"> </span>9.025<span style="white-space: pre;"> </span>34.55<span style="white-space: pre;"> </span>104</span></p><p><span style="font-size: large;">C6<span style="white-space: pre;"> </span>Actual Marks<span style="white-space: pre;"> </span>80<span style="white-space: pre;"> </span>38<span style="white-space: pre;"> </span>40<span style="white-space: pre;"> </span>158</span></p><p><span style="font-size: large;"><span style="white-space: pre;"> </span>Normalized Marks<span style="white-space: pre;"> </span>83.94<span style="white-space: pre;"> </span>39.26<span style="white-space: pre;"> </span>39.34<span style="white-space: pre;"> </span>163</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">ANNEXURE – IV</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">CRITERIA FOR RANKING (AP EAPCET – 2021 “AM” CATEGORY”)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">As per G.O.Ms.No 73 of Higher Education(EC.2) Department, dated 28-07-2011, the candidates who have secured qualifying marks in AP EAPCET-2021 and candidates belonging to the category of Scheduled Caste and Schedule Tribe, for whom qualifying marks have not been prescribed, shall be assigned ranking in the order of merit on the basis of combined score obtained by giving 75% weightage to the marks secured in AP EAPCET- 2021 and 25% weightage to the marks secured in the relevant group subjects namely Mathematics, Physics, Chemistry of the qualifying examination.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">For the preparation of merit list, in case of more than one student securing the same combined score obtained as mentioned above, the tie shall be resolved to decide the relative ranking by successively considering the following</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(I)<span style="white-space: pre;"> </span>The total marks secured in AP EAPCET-2021</span></p><p><span style="font-size: large;">(II)<span style="white-space: pre;"> </span>The Marks secured in Biology in AP EAPCET-2021</span></p><p><span style="font-size: large;">(III)<span style="white-space: pre;"> </span>The marks secured in Physics in AP EAPCET-2021</span></p><p><span style="font-size: large;">(IV)<span style="white-space: pre;"> </span>If the tie still persists, the older (based on date of birth) being given preference over the younger.</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">The weightage of marks, in case of candidates belonging to the category of Persons of Indian Origin (PIO) / Overseas Citizen of India (OCI) Card</span></p><div><div><span style="font-size: large;">AP EAPCET – 2021</span></div><div><span style="font-size: large;">IMPORTANT INSTRUCTIONS TO THE CANDIDATES</span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">1)<span style="white-space: pre;"> </span>The Candidates who wish to apply for APEAPCET-2021 are requested to fill the particulars carefully in the ONLINE APPLICATION FORM. The required information should be collected from the relevant documents.</span></div><div><span style="font-size: large;">2)<span style="white-space: pre;"> </span>The Candidates are requested to check the filled in particulars before pressing SUBMIT button during online application process.</span></div><div><span style="font-size: large;">3)<span style="white-space: pre;"> </span>After submission of ONLINE APPLICATION FORM, if any corrections are to be incorporated, candidate has to see the corrections link in Homepage of https://sche.ap.gov.in/eapcet</span></div><div><span style="font-size: large;">4)<span style="white-space: pre;"> </span>To fill the required details in ONLINE APPLICATION FORM, the following documents may be referred:</span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">S.NO<span style="white-space: pre;"> </span>Details Required<span style="white-space: pre;"> </span>Documents to be referred</span></div><div><span style="font-size: large;">1.<span style="white-space: pre;"> </span>AP Online/ TS Online Transaction Id. (if</span></div><div><span style="font-size: large;">payment is being made through AP Online/ TS Online)<span style="white-space: pre;"> </span>Receipt form from AP Online / TS Online</span></div><div><span style="font-size: large;">2.<span style="white-space: pre;"> </span>Qualifying Examination appeared or passed, Hall<span style="white-space: pre;"> </span>ticket<span style="white-space: pre;"> </span>Number<span style="white-space: pre;"> </span>of<span style="white-space: pre;"> </span>Qualifying</span></div><div><span style="font-size: large;">Examination<span style="white-space: pre;"> </span>Marks<span style="white-space: pre;"> </span>Memo<span style="white-space: pre;"> </span>/<span style="white-space: pre;"> </span>Hall<span style="white-space: pre;"> </span>Ticket Intermediate (10+2) / Equivalent<span style="white-space: pre;"> </span>of</span></div><div><span style="font-size: large;">3.<span style="white-space: pre;"> </span>Stream Applied for (E), (AM), or both (E &</span></div><div><span style="font-size: large;">AM)<span style="white-space: pre;"> </span>Eligibility Criteria in the APEAPCET-</span></div><div><span style="font-size: large;">2020 website</span></div><div><span style="font-size: large;">4.<span style="white-space: pre;"> </span>Date of Birth, Birth District, Birth State<span style="white-space: pre;"> </span>Birth Certificate / SSC or Equivalent</span></div><div><span style="font-size: large;">Certificate</span></div><div><span style="font-size: large;">5.<span style="white-space: pre;"> </span>Hall Ticket Number of SSC or Equivalent</span></div><div><span style="font-size: large;">examination Certificate<span style="white-space: pre;"> </span>SSC or Equivalent Certificate</span></div><div><span style="font-size: large;">6.<span style="white-space: pre;"> </span>Local Status (OU/AU/SVU/ Non- local)<span style="white-space: pre;"> </span>The local candidate certificate issued by</span></div><div><span style="font-size: large;">MRO or Competent Authority</span></div><div><span style="font-size: large;">7.<span style="white-space: pre;"> </span>Income of Parents (Income upto Rs.1.00</span></div><div><span style="font-size: large;">Lakh (or) up to Rs.2.00 Lakhs (or) more than Rs. 2.0 lakhs<span style="white-space: pre;"> </span>The<span style="white-space: pre;"> </span>Income<span style="white-space: pre;"> </span>certificate<span style="white-space: pre;"> </span>issued Competent Authority<span style="white-space: pre;"> </span>by</span></div><div><span style="font-size: large;">8.<span style="white-space: pre;"> </span>STUDY DETAILS<span style="white-space: pre;"> </span>Study<span style="white-space: pre;"> </span>certificates<span style="white-space: pre;"> </span>from<span style="white-space: pre;"> </span>Class</span></div><div><span style="font-size: large;">Intermediate (10+2) / Equivalent<span style="white-space: pre;"> </span>I<span style="white-space: pre;"> </span>to</span></div><div><span style="font-size: large;">9.<span style="white-space: pre;"> </span>Category (SC, ST, BC, etc.) and Application</span></div><div><span style="font-size: large;">number of the Caste Certificate<span style="white-space: pre;"> </span>The latest Caste Certificate issued by</span></div><div><span style="font-size: large;">Competent Authority</span></div><div><span style="font-size: large;">10.<span style="white-space: pre;"> </span>Special Category (NCC, PH, Sports, CAP,</span></div><div><span style="font-size: large;">etc.)<span style="white-space: pre;"> </span>The Certificate Issued by Competent</span></div><div><span style="font-size: large;">Authority</span></div><div><span style="font-size: large;">11.<span style="white-space: pre;"> </span>Aadhaar Card details<span style="white-space: pre;"> </span>Aadhaar Card</span></div><div><span style="font-size: large;">12.<span style="white-space: pre;"> </span>Ration Card details<span style="white-space: pre;"> </span>Ration Card</span></div><div><span style="font-size: large;">13.<span style="white-space: pre;"> </span>Economically Weaker Sections Certificate</span></div><div><span style="font-size: large;">details<span style="white-space: pre;"> </span>EWS Certificate</span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">5)<span style="white-space: pre;"> </span>Other Information required for filling Online Application</span></div><div><span style="font-size: large;">a)<span style="white-space: pre;"> </span>Recent passport size digital color photograph (file size less than 30 KB and “.jpg” file format) of candidate for uploading (whose photograph is not available in Intermediate databases)</span></div><div><span style="font-size: large;"> </span></div><div><span style="font-size: large;">b)<span style="white-space: pre;"> </span>Digital Signature of the candidate (file size less than 15 KB and “.jpg” file format) of candidate or uploading (whose Signature is not available in Intermediate databases.)</span></div><div><span style="font-size: large;">c)<span style="white-space: pre;"> </span>Regional Center to which candidate wishes to appear for AP EAPCET-2021 examination. d) Gender (Male / Female/Transgender.)</span></div><div><span style="font-size: large;">e)<span style="white-space: pre;"> </span>Non-Minority / Minority</span></div><div><span style="font-size: large;">f)<span style="white-space: pre;"> </span>Mobile Number of the candidate.</span></div><div><span style="font-size: large;">g)<span style="white-space: pre;"> </span>E-mail of the candidate.</span></div><div><span style="font-size: large;">h)<span style="white-space: pre;"> </span>Place of Education - Municipality / Corporation or Rural area in SSC and Intermediate.</span></div><div><span style="font-size: large;"><br /></span></div><div><span style="font-size: large;">6)<span style="white-space: pre;"> </span>It is advised to visit your allotted Examination Center well before so that you can take examination tension – free.</span></div><div><span style="font-size: large;">7)<span style="white-space: pre;"> </span>The candidate will not be allowed to take the examination even if late by 1minute.</span></div><div><span style="font-size: large;">8)<span style="white-space: pre;"> </span>The candidate does not have option of choosing specific date / session to appear for the AP EAPCET-2021 entrance examination. This information is known to him / her only after downloading Hall Ticket. For any reason if the candidate fails to appear in the given slot, he / she is treated as absent.</span></div><div><span style="font-size: large;">9)<span style="white-space: pre;"> </span>The candidate has to submit the “FILLED IN ONLINE APPLICATION FORM” to the invigilator in the Examination Hall on the day of the AP EAPCET-2021 exam. Also, affix a recent color photograph (3.5cms x 3.5cms) in the box provided (Bottom – Left side) on the FILLED IN ONLINE APPLICATION FORM and get it attested by a Gazetted Officer / Principal of the college where studied.</span></div><div><span style="font-size: large;">10)<span style="white-space: pre;"> </span>The candidate belonging to SC / ST category has to submit the attested “CASTE CERTIFICATE” along with the FILLED IN ONLINE APPLICATION FORM” to the Invigilator on day of the AP EAPCET-2021 exam in the Examination Hall, in case, the Application number of his/her Caste Certificate is not provided at the time of the Online submission of the Application.</span></div><div><span style="font-size: large;">* NOTE: For items 5(a) and 5(b), please don’t paste Photograph and Signature on another paper and scan. Instead scan the photograph and Signature as separate files</span></div></div><div><br /></div>Unknownnoreply@blogger.com0tag:blogger.com,1999:blog-5675036936367608346.post-26497212564891613542021-06-13T05:26:00.006-07:002021-06-25T19:52:22.131-07:00 PROBLEMS ON AGES PERCENTAGES ARTHIMETIC MATERIAL<h4 style="text-align: left;"><span style="font-size: large;"> PROBLEMS ON AGES PERCENTAGES ARTHIMETIC MATERIAL PROBLEMS ON AGES</span></h4><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ...................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> Five years ago laxmi's age was seven times the age of her son at that</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">time and after 5 years her age will be thrice the age of her son. how old is laxmi now?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 years ago 7 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 years after 3:1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7x+10 = 3</span></p><p><span style="font-size: large;"> ........ ...</span></p><p><span style="font-size: large;"> x+10 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7x+10 = 3x+30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4x = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7*5 = 35+5 = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">METHOD 2:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (3: 1)3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2PARTS INCREASED </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 5 YEARS BEFORE 5 YEARS 5 TOTAL 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2P =10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5*7)+5 = 40</span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SANDHYA GOT MARRIED 4 YEARS AGO TODAY HER AGE IS 1(1/8) TIMES HER AGE AT THE TIME OF MARRIAGE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HER SONS AGE IS 1/12 OF HER AGE WHAT IS THE AGE OF SANDHYAS AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT AGE = X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MARRIAGE AGE = X-4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 1(1/8)(X-4)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8X = 9X - 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/12) *36 = 3 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">METHOD 2:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 :8 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1P = 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4*9 = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/12) *36 = 3 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG3:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MOHAN GOT MARRIED 9 YEARS AGO TODAY HIS AGE IS 1(1/3) TIMES HIS AGE AT THE TIME OF MARRIAGE FIND HIS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRESENT AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1P = 9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4*9 = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MADHU GOT MARRIED 6 YEARS AGO TODAY HER AGE IS 125% TIMES HER AGE AT THE TIME OF MARRIAGE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HER SONS AGE IS ONE TENTH OF HER AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HER SONS AGE IS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 125%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 125 : 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 : 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MADHU GOT MARRIED 6 YEARS AGO</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1P =6 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> SO 5*6 =30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> HER SONS AGE IS ONE TENTH OF HER AGE (1/10)*30 = 3 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AGES OF 3 PERSONS ARE IN THE RATIO 5 : 7 :9 SUM OF SQUARES OF THE AGES OF PERSONS EXCLUDING THAT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">OF YOUNGEST PERSON IS 3250 WHAT WILL BE THE RATIO OF THEIR AGES AFTER 10 YEARS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 x^2 +9 x^2 = 3250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16 x^2 = 3250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> x^2 = 3250/16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;">IN 10 YEARS THE AGE OF ROHIT WILL BE 3 TIME THAT OF HIS AGE 6 YEARS AGO WHAT IS THE PRESENT AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> NOW X </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER X+10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> X+10 = 3(X+6)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X = 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 14</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> RAM WILL BE 5 TIMES AS OLS AS HE IS NOW AFTER 8 YEARS HOW MANY YEARS HENCE WILL BE 10 TIMES</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AS OLD AS HE IS NOW?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT AGE = X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 8 YEARS = X+8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+8 = 5X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X= 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10*2 = 20YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 20-2 =18 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">RAKESH IS 30 YEARS YOUNGER THAN HIS AUNT TODAY FIVE YEARS AGO RAKESH WAS (1/4) AS OLD AS HIS AUNT </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HOW OLD WILL RAKESH AUNT BE 8 YEARS HENCE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5 YEARS AGO 1: 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3P =30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P =10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 10*4 = 40 + 5 = 45+8= 53</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SAMPATH IS AS MUCH YOUNGER TO VAMSI AS HE IS OLDER TO RAKESH IF THE SUM OF THE AGES OF VAMSI AND RAKESH IS 56 YEARS HOW OLD IS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SAMPATH NOW?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> R S V</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> SAME DIFFERNCE </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> IF A,B,C ARE IN AP </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B= (A+C)/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 56/2 = 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">P IS AS MUCH YOUNGER TO Q HE IS OLDER TO R IF THE SUM OF THE AGES OF Q AND R IS 50 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT IS THE DIFFERENCE BETWEEN AGES OF P AND Q?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P,Q,R IN A P</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (P+Q)/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50/2 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 25</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SAHITHI'S AGE IS (1/6) TH OF HER FATHERS AGE SAHITHIS FATHER AGW WILL BE TWICE OF KAMALS AGE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 10 YEARS . IF KAMALS 8 TH BIRTHDAY WAS CELEBRATED TWO YEARS AGO THEN WHAT IS SAHITHIS PRESENT AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8 YEARS KAMAL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8 +2 = 10 YEARS PRESENT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 10 YEARS 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> HIS FATHER DOUBLE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40 : 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT FATHER AGE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40-10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/6)*30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 YEARS AGO THE FATHERS AGE WAS TWICE THE AGE OF HIS FOUR DAUGHTERS IN 3 YEARS TIME THE AGE OF</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HIS FOUR DAUGHTERS.IN 3 YEARS TIME THE FATHERS AGE WILL BE EQUAL TO SUMOF AGES OF THE DAUGHTERS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND THE PRESENT AGE OF FATHER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> FATHER 4 DAUGHTERS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X+6 X+24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X+6 = 1</span></p><p><span style="font-size: large;"> ..... .....</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+24 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X+6 = X+24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2*18 = 36</span></p><p><span style="font-size: large;"> PRESENT = 36 +3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> = 39</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHEN I ADD 4 TIMES MY AGE 4 YEARS FROM NOW TO 5 TIMES MY AGE 5 YEARS FROM NOW I GET</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">10 TIMES MY PRESENT AGE HOW OLD I WILL BE 3 YEARS FROM NOW?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT AGE X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4(X+4) + 5 (X+5) = 10X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 25+16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> = 41</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 3 YEARS = 44 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> THE RATIO OF AGES OF A MOTHER AND HIS SON IS 2 :1 MOTHER WAS 24 YEARS OLD WHEN SHE GAVE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BIRTH TO HER ONLY DAUGHTER WHO IS 6 YEARS YOUNGER TO HER ONLY SON FIND THE PRESENT AGE OF </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MOTHER AD SON (IN YEARS)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 36 ,18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> WHEN I WAS MARRIED 10 YEARS AGO MY WIFE IS THE 6TH MEMBER OF THE FAMILY TOADY MY FATHER DIED AND A BABY BORN TO ME THE AVERAGE AGE OF MY FAMILY</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A BABY BORN TO ME THE AVERAGE AGE OF MY FAMILY DURING MY MARRIAGE IS SAME AS TODAY WHAT IS THE AGE OF FATHER WHEN DIED?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MARIAGE AGE = PRESENT AGE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> F+ X1+X2+X3+X4+X5 = (X1+X2+x3+X4+X5+50)+0</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ................... ................</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> F = 50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 YEARS AGO = 50</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> THE AGE OF THE TWO FRIENDS WERE IN THE RATIO OF 6 :5 IF THE SUM OF THEIR AGES IS 55 THEN AFTER</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HOW MANY YEARS THEIR AGES WILL BECOME 8 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 11P = 55</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P =5 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2*5 = 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF THE AGES OF SUNIL AND HIS FATHER IS 46 YEARS 3 YEARS BACK FATHERS AGE WAS 4 TIMES SUNILS AGE FIND PRESENT AGE OF SUNIL?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> S+F =46</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 YEARS AGO =40 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AT THAT TIME 4 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5P = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8 +3 = 11</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 30 YEARS A'S AGE IS 3 TIMES TO THE PRESENT AGE THEN FIND A AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT AGE X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+30 = 3X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X = 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE RATIO OF THE AGES OF MR RAO AND HIS SON I1 6 : 1 AFTER 5 YEARS THE RATIO WILL BE 7 :2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT WILL BE THE AGE OF MR RAO?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 : 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PAR 5 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5*6 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE AGES OF A FATHER AND HIS DAUGHTER ARE IN THE RATIO 4: 1 IF 5 YEARS AGO THEIR AGES WERE IN THE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">7 :1 FIND THE AGE OF FATHER AND PARENT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 :1 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MULTIPLE 1ST EQUATION WITH1 ( 4 :1) 2 = 8 : 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 7 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5*6 = 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5 YEARS AGO LAKSHMI'S AGE WAS 7 TIMES THE AGE OF HER DAUGHTER AT THE TIME AFTER 5 YEARS HER AGE WILL BE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THRICE THE AGE OF HER DAUGHTER HOW OLD NOW?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (3 :1 )3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 2P =10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7*5 = 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> NOW 35+5 = 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MR KRANTHI IS 4 TIMES AS OLD AS BINDU 3 YEARS HENCE THE SUM OF THEIR AGES WILL BE 41 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT IS THE AGE OF KRANTHI?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4X : X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> + 3 YEARS = 41</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> MINUS 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ...........</span></p><p><span style="font-size: large;"> 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5PARTS ----------- 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART ..........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ANS 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PHANI IS AS MUCH YOUNGER TO MICHAEL AS HE IS OLDER TO RAMESH IF THE SUM OF THEIR AGES OF</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MICHAEL AND RAMESH IS 48 YEARS FIND THE AGE OF PHANI?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> V- P = P-R</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> V+ R = 48</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> V+R = 2P</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2P = 48</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P =24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE SUM OF THE AGES OF RAMANA AND RAJESH IS 56 YEARS 6 YEARS AGO THE RATIO OF THE AGES WAS 7 :4 HOW OLD IS MR RAJESH NOW ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> RAM+RAJ = 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 :4 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -6 *2 = -12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 56</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ....</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 44</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 :4 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 11P = 44</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P =4 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 YEARS BACK = 4 *4 = 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> +6 = 16 +6 = 22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN 8 YEARS THE AGE OF RAHUL WILL BE 4 TIMES THAT OF HIS AGE 13 YEARS AGO WHAT IS THE PRESENT AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> RAHUL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+8 X-13</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X+8) = 4(X-13)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3X = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE PRESENT AGE OF PRANATHI IS TWICE THE AGE OF SARADA 3 YEARS AGO IF PRANATHI IS 2 YEARS OLDER TO SARADA WHAT IS THE PRESENT AGE OF PRANATHI?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P,S</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 YEARS AGO = S-3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P 2(S-3)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = S+2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P-2 = S</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = 2(P-5)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> P = 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MOTHER HAD 3 SONS THEY WERE BORN AT AN INTERVALS OF 3 YEARS THE TOTAL AGE OF 3 SONS IS 24 YEARS WHAT IS THE AGE OF YOUNGEST</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SON?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X+X+3+X+6 = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3X+9 = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3X = 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X =5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> NEELIMA GOT MARRIED 4 YEARS AGO TODAY HER AGE IS 1(1/6) TIMES THE AGE AT THE TIME OF HER MARRIAGE HER SONS AGE IS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(1/14) OF HER AGE WHAT IS THE AGE OF NEEELIMA'S AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X-4) (1(1/6)) =X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X-4)(7/6) = X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 28</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/14)*28 = 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE RATIO OF THE PRESENT AGES OF TWO BROTHERS IS 1 :2 AND 5 YEARS BACK THE RATIO </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WAS 1 :3 WHAT WILL BE THE RATIO OF THEIR AGES AFTER 5 YEARS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 : 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1:2) 2 = 2 :4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 :4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER FIVE YEARS +1 TO RATIO = 3 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE RATIO BETWEEN THE SCHOOL AGES OF NEELAM AND SHYAM IS 5 :6 RESPECTIVILY IF THE RATIO BETWEN</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">ONE THIRD AGE OF NEELAM AND HALF OF SHYAMS AGE IS 5 :9 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN WHAT IS THE SCHOOL AGE OF SHYAM?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> N :S</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5: 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> N/3 : S:2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/3)5 : (1/2)6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5/3) : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A MAN IS 24 YEARS OLDER THAN HIS SON IN TWO YEARS HIS AGE WILL BE TWICE THE AGE OF HIS SON</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND THE AGE OF HIS SON?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> F -S = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> F : S </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1P = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> .....</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 22</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;">THE AGES OF A AND B ARE IN THE RATIO 4 :1 THE PRODUCT OF THEIR AGES IS 64</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT WILL BE THE RATIO OF THE AGES AFTER 4 YEARS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A: B = 4 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4X,X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (4X) (4X) = 64</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X= 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">RAJESH WAS N YEARS OLD X YEARS AGO HIS AGE M YEARS FROM NOW WOULD BE EXPRESED AS?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> N+M+X</span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE RATIO BETWEEN THE PRESENT AGES OF A AND B IS 5 :3 RESPECTIVILY </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THE RATIO BETWEEN THE A'S AGE 4 YEARS AGO AND B'S AGE 4 YEARS HENCE IS 1 :2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT IS THE RATIO BETWEEN A'S AGE 4 YEARS HENCE AND B'S AGE 4 YEARS AGO?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A : B = 5 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5X-4)/(3X+4) = 1/1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5X = 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20 : 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> +4 -4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24 : 8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 :1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A PERSONS PRESENT AGE IS 2/5 TH OF THE AGE OF HIS MOTHER AFTER 8 YEARS HW WILL BE ONE HALF OF THE AGE OF HIS MOTHER </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">HOW OLD IS THE MOTHER AT PRESENT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PERSON MOTHER</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (2/5 ) X X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 8 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 :2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1 :2 ) 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 : 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 2 :5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 :6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART = 8 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5*8 =40 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">eg:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">RAHUL MARRIED 4 YEARS AGO NOW HIS AGE IS 1(1/8) TIMES AT THE TIME OF HIS MARRIAGE NOW HIS PRESENT AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1(1/8) (X-4) = X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> OR</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 :8 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART 4 YEARS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 PARTS 36 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SHARMA MARRIED 6 YEARS AGO NOW HIS AGE 1(1/3) TIMES AT THE TIME OF HIS MARRIAGE THEN TIND HIS PRESENT AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4/3(X-6) = X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> OR</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 : 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PAR T 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 *6 = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AHUJA MARRIED 7 YEARS AGO NOW HIS AGE 125 % AT THE TIME OF HIS MARRIAGE THEN FIND HIS AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X-7 ) (125/100) = X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5X - 35 = 4X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRESENT RATIO OF THE AGES OF A AND B IS 3 :4 AFTER 6YEARS THEIR AGES RATIO 4 :5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND PRESENT AGE RATIO?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 : 4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4 : 5</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1 PART INCREASED</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS = 3 *6 = 18 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRESENT RATIO OF AGES OF A AND B IS 3 : 5 AFTER 10 YEARS THEIR AGES ARE IN THE RATIO 5 :7 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND PRESENT AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 PARTS INCREASED</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PART = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 PARTS = 15</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 PARTS = 25</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT RATIO OF THE AGES OF A AND B IS 5 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 5 YEARS THEIR RATIO WILL BE CHANGED TO 3 :4 THEN FIND PRESENT RATIO OF THEIR AGES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5X+5/7X+5) = 3/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (5X+5)4 = 3(7X+5)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X =5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A = 5*5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B = 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> OR</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 :4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2(3) : 2(4)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5 : 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 6 :8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 PARTS = 35</span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRESENT FATHER IS 7 TIMES TO SONS AGE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 10 YEARS FATHER AGE IS 3 TIMES TO HIS SONS AGE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND FATHER AGE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> FATHER SON</span></p><p><span style="font-size: large;"> 7 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 10 YEARS3 TIME SO MULTIPLE WITH 3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (3 : 1)3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 : 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 9 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2P = 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P = 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7X = 7 *5 = 35</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5 YEARS BACK RATIO OF THE AGES OF A AND B IS 4 : 7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 7 YEARS A AND B AGES RATIO IS 2:3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND THEIR AGES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 YEARS BACK 4 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 YEARS LATER 2 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 5 YEARS BACK + 7 YEARS LATER = 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (4X+12/7X+12) = (2/3)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A = 4X = 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B = 7X = 42</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">NOW AGES</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24 + 5 = 29</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 42 +5 =47</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">METHOD 2:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 YEARS BACK 4 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7 YEARS LATER 6 :9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 PARTS 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 PART = 6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3 YEARS BACK FATHER AGE IS DOUBLE TO TOTAL AGES OF HIS 4 SONS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 4 YEARS FATHER AGE IS DOUBLE TO TOTAL AGES OF HIS 4 SONS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> FATHER 4 SONS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 1</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X X</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">3 YEARS LATER 2X +6 X +24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X+6 = X+24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> X +18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2X = 2*18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 3 YEARS 36 +3 = 39 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PRESENT DIFFERENCE BETWEEN A AND B AGES IS 12 YEARS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">AFTER 10 YEARS AND B AGES RATIO IS 5 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">THEN FIND PRESENT AGES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10 YEARS LATER 5 :7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ( 7 -5) =2 PARTS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 PARTS = 12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> = 6* 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 7*6 = 42</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30 -10 42-10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20 32</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT AGES OF A AND B IS 50 YEARS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 5 YEARS THIER AGEIR AGES RATIO IS 2 :3 THEN FIND PRESENT AGES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT TOTAL = 50 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> AFTER 5 YEARS = 60 YEARS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ] 5P = 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> P =12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 :3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2*12 : 3 *12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24 : 36</span></p><p><span style="font-size: large;">'</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRESENT 24- 5 =19</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> B = 36-5 =29</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> PERCENTAGES</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">To convert percentage into fractions divide the given value with hundred</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">To convert fraction into percentage multiple the given fraction with 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 50% = 50/100 = 1/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1/2 = 1/2(100%) = 50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">EX:</span></p><p><span style="font-size: large;"> convert the folowing percentages into fraction </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1) 60% = 60/100 = 3/5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2) 12.5 % = 12.5/100 = 5/40 = 1/8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3) 33 (1/3)% = 100/3 = 1/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4) 16(2/3)% = 50/(3*100) = 1/6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EX:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">convert the following fractions into percentage</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1) (3/4)*100 = 75 %</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">2) (4/5) * 100 = 80%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">3) (2/3) * 100 = 200/3 = 66(2/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">4) (1/5) *100 = 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">5) (1/12)*100 = 25/3 % = 8 (1/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">NOTE:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">50% = 1/2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">25% = 1/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">12(1/2)% = 1/8</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">6(1/4)% = 1/16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">66 (2/3)% = 2/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">33(1/3)% = 1/3</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">16(2/3) % = 1/6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">8(1/3)% = 1/12</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">75% = 3/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">14 (2/7)% = 1/7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">11(1/9)% = 1/9 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">9 (1/11)% = 1/11</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">NOTE:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/1 = 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/2 = 50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/3 = 75%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/4 = 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/5 = 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/6 = 16 (2/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/7 = 14(2/7)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/8 = 12(1/2)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/4 = 11(1/4)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/10 = 10%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/11 = 9(1/11)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">1/12 = 8(1/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FORMULAE:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 x%y = (x/100)y</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (xy)/100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 x is what percentage of y</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> what = (100%x)/y</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> is/of just remember</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN 250 FIND 30 % VALUE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10% = 25</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30 % = 75</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN 360 FIND 15%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 10% = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5% = 18</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 15% = 54</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"> IN 450 FIND 22 % VALUE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 10% = 45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 20% = 90</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2% = 9</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ......</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 99</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN 240 FIND 19%?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% 48</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -1% 2.4</span></p><p><span style="font-size: large;"> ........</span></p><p><span style="font-size: large;"> 45.6</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30 % OF 120 = 36</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> total 5 parts</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> boys (3/5) * 100 = 60%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> girls (2/5) *100 = 40%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">METHOD 2</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5 - 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 2 ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5---100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3 ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;">boys what percentage more that girls?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/2) * 100 = 50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">girls what percentage more than boys ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/3)* 100 = 33(1/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Boys is what percentage of girls?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (3/2)100 = 150%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A CLASS BOYS AND GIRLS ARE IN THE RATIO 3:2 then find percentage of boys </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">girls is what percentage of Boys ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (2/5)*100 = 200/3 = 66(2/3) %</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A Salary is 20 % less than b salary then b salary is what % more than a salary?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 4 : 5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (1/4) 100 = 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> short cut formulae</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (X/(100±X))*100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MORE - PLUS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">DECREASE OR LESS -- MINUS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">COMPARE ABOVE PROBLEM</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20/(100-20))*100 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20/80)*100 = 25%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A rectangle length increased by 10 % by what percentage breadth has to be decrease sothat no change in its area?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (10/(100+10))*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (10/110)*100</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 9(1/11)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">price of a article decreased by 30% by what percentage it sales has to be increase so that these is no effect in revenue?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (30/70)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300/7</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 42(6/7)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">price of a sugar increased by 20% by what percentage it consumption has to be decreased sothat there is no change </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (20/120)*100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 16(2/3)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG: </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> Population of a town is 5000 in the first year it is increased by 10 % and then 2nd year it decreased by 20 % find the </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">find the population after 2 years and the overall percentage </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> population first year 10% increased so 110/100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> population second year 20% decreased 80/100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5000 *(110/100) * (80/100)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 550*8 </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4400</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (600/5000)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 12% decreased</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">METHOD 2:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> +10% -20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> ONLY ON TWO PERCENTAGE CHANGES ONLY</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> ((X+Y+(XY/100)) %</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> (10-20-200/100)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> -12% DECREASED</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A rectangle length is decreased by 10% and bredth decreased by 10 %</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> find the effect on its area?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (-10-20+(200/100)%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -28% decrease</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> thrice of a article first increased by 10% and again increased by 20 % then decrease by 25 %?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100*(110/100)* (75/100)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 99%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 percentage decreased</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">MODEL 3: </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> EG: </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> population of a town first increased by 10 %and then decreased by 205 if the final population is 4400 initial population?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> increased by 10% so 100/110</span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> decreased by 20% so 100/80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4400*(100/110)*(100/80)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 5000</span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> A man spends 85% of his income per household items and out of the remaining 50% per transport if he finally saves 900 find his income?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 900*(100/15)*(100/50)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 12500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> In a college 30% are arts graduates out of the remaining 40% are science graduates out of the remaining 50% are computer</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">graduates find total no of students?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> -30% -40% -50%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 210*(100/70)*(100/60)*(100/50)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> The ratio between a ,b,c is 3 :4 :5 a increased by 20% and b increased by 25% and c reduced by 10% then find new ratio?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300 : 400 : 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 360 : 400 : 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 36 : 50 :45</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Total votes polled in a election is 1200 votes difference between the winning and loosing candidate is 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">then find how much votes that winning candidate got?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 20% 80%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> differcnce 60% = 1200</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% = 20 votes</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80% = 1600 votes</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A ELECTION BETWEEN TWO CANDIDATES ONE CANDIDATE GOT 60% VOTES AND WON BY 500 VOTES THEN FIND TOTAL VOTES?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 40% 60%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> DIFFERENCE 20% = 500</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% = 25 VOTES</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TORAL = 100*25 = 2500 VOTES</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">TO pass in an exam every guy need 40% marks but one candidate got 40 marks and then failed by 40 marks then </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">total marks in that exam?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> pass : 40 + 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> so pass percentage 40% = 80marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 1% = 2 marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100% = 200 marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> to pass in an exam students need 30 % marks but one student got 100 marks </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">he got 10 marks more than pass mark then total marks in that exam?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> pass % pass marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30% 100marks - 10 marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30% 90 marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% 3 marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100% = 300 marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Eg</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> in an exam a got 32% marks and failed by 9 marks </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">b got 40% marks and pass by 15 marks then find total marks in that exam?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> a 32% -9marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> b 40% 15 marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> difference 15-(-9)</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 8% 24 marks</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1% ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1 percent 3 marks </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> total marks 300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">Percentage: </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> percentage literally means every hundred </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">comparing every quantity with respectto t100 is called percentage</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">25% = 1/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a percentage can be expressed in fraction</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">25% = 1/4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">in aratio = 1:4</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">and also in a decimal form .25</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">conversions:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">percentage can be converte into fraction by dividing with hundred</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">45% = 45/100 = 9/20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">a fraction can be converted into percentage by multiplying with 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(3/4)*100 = 75%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">60% = (60/100) = 3/5</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(4/5) = (4/5)*100 = 80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">10 interms of percentage</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">10*100 =1000%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG :</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 38 IS WHAT PERCENT OF 152</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 152 ------------ 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 38 ?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> WHAT PERCENTAGE IS 50 OF 40</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IS/OF *100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30% OF A NUMBER IS 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30............60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100.........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% OF A NUMBER IS 16</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">100% OF A NUMBER IS 80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 32% OF A NUMBER EXCEEDS 12% OF THE SAME BY 60 WHAT IS THAT NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 32% - 12% = 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% ----------------60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">100%.....................?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60*5 = 300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A NUMBER WHEN INCREASED BY 30% GIVES 780</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">FIND HUNDRED PERCENT OF NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A NUMBER INCREASED BY 30% SO 130%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 130% NUMBER IS 780</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100 %..........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (780*100)130</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A NUMBER WHEN DECREASED BY 12% OF IT IT GIVES 220 FIND NUMBER?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> DEC BY 12% SO 100-12 =88%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 88%----------220</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100% ............?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100*220)/88</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> PRECENTAGE INCREASE = (INCREASE/INITIAL)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">PERCENTAGE DECREASE = (DECREASE/INITIAL)*100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> THE NUMBER OF STUDENTS IN A SCHOOL IS DECREASED TO 320 FROM 400 WHAT IS THE PERCENT DECREASED</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (320/400)*100 = 80</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SO 100-80 = 20%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">RAVI SPENDS 76% OF HIS SALARY WHAT HE SAVING IF HIS TOTAL SALARY IS 4000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">76% ---------- 3040</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 4000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 3040</span></p><p><span style="font-size: large;"> ...........</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 960</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN AN ELECTION BETWEEN TWO CANDIDATES A CANDIDATE GOT 38 % OF VOTES POLLED AND LOST TO HIS RIVAL BY 3600 VOTES FIND TOTAL?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 62 38</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 62-38 = 24%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 24% - 3600</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%--?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN AN ELECION BETWEEN A AND B A GOT 60% OF VOTES WON BY MAJORITY OF 1800 VOTES FIND THE TOTAL NUMBER OF VOTES POLLED?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"> 60% 40%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% ------------1800</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100% ........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 1800 *5 = 9000</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A SCHOOL OF 300 STUDENTS 70% OF STUDENTS BOYS</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% OF THE BOYS ARE ABSEST THEN HOW MANY BOYS ARE PRESENT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">BOYS = 70% OF TOTAL ABSENT 20% OF BOYS </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 20% OF 70% OF TOTAL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 14% OF TOTAL</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (14/100)*300</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 42</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG: </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> IN A SCHOOL OF 300 STUDENTS BOYS ARE 70% </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IF 30% OF GIRLS ARE ABSENT FIND THE TOTAL NUMBER OF GIRLS PRESENT?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 70% = 210</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 300 - 210 =90</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 30% OF GIRLS ABSENT </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">SO 30% OF 80 = 27</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 90-27 = 63</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">IN A SCHOOL OF 400 STUDENTS 40% ARE GIRLS 30% OF THE BOYS AND 50%OF THE</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">GIRLS FAILED IN AN EXAM EHAT PERCENTAGE OF THE STUDENTS IN A SCHOOL PASSED THE EXAM?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> TOTAL 100 PERCENT</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60 40 </span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 18 42 20 20</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 42 +20 = 62%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG: </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">A STUDENT HAS TO GET 38% OF MARKS TO PASS THE EXAMINATION ARUN GOT 81 MARKS BUT FAILED BY 14 MARKS FIND THE MAXIMUM MARKS IN AN EXAM?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 38% = 81+14 = 95</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 38% ------95</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100%........?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100*95)/38</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> A STUDENT HAS TO GET 44% OF MARKS TO PASS THE EXAMINTION RAMYA GOT 143 MARKS WHICH ARE </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">33 MARKS MORE THAN NECESSARY TO PASS THE EXAM?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 44----------110</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 100------?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> (100*110)/44</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 250</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">EG:</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">60 LITERS OF A MIXURE WHICH CONTAINS MILK AND WATER HAVE 35% OF WATER IF 10 LITERS OF MILK IS ADDED</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">WHAT WILL BE THE PERCENTAGE OF WATER IN THE RESULTANT MIXURE?</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 60</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 35% 65%</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 39 21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> plus 10 LITER MILK 10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 39+10</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> 49 21</span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;">(21/70)* 100 =30% </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p><p><span style="font-size: large;"><br /></span></p><p><span style="font-size: large;"> </span></p>Unknownnoreply@blogger.com0